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Salesforce JS-Dev-101 Exam Syllabus Topics:

Topic	Details
Topic 1	Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 2	Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 3	Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 4	Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
Topic 5	Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q116-Q121):

NEW QUESTION # 116
Given two expressions var1 and var2, what are two valid ways to return the concatenation of the two expressions and ensure it is data type string?

A. var1.toString() + var2.toString()
B. String(var1).concat(var2)
C. var1 + var2
D. String.concat(var1 + var2)

Answer: A,B

Explanation:
We want to guarantee that the result is of type string regardless of what var1 and var2 are (numbers, booleans, etc.).
Option A:
String(var1).concat(var2)
String(var1) converts var1 explicitly to a string.
.concat(var2) calls String.prototype.concat, which:
Converts var2 to string if needed.
Returns a new string that is the concatenation of the two.
Result is always a string.
So A is valid.
Option B:
String.concat(var1 + var2)
String.concat (as a static method) does not exist. concat is an instance method on string objects, not on the String constructor.
var1 + var2 might be a number (if both numeric) and used incorrectly here.
So B is invalid.
Option C:
var1 + var2
+ can mean:
String concatenation (if at least one operand is a string).
Numeric addition (if both operands are numbers).
If var1 and var2 are both numbers, var1 + var2 will be a number, not a string.
This does not ensure the result is always a string.
So C is not guaranteed to satisfy the requirement.
Option D:
var1.toString() + var2.toString()
var1.toString() converts var1 to a string (for most primitive/object types).
var2.toString() does the same.
Now both operands of + are strings, so the result is string concatenation.
Result is guaranteed to be a string.
So D is valid.
Therefore, the two valid ways are A and D.
Study Guide / Concept Reference (no links):
String() conversion vs .toString()
String.prototype.concat
+ operator overload: numeric addition vs string concatenation
Type coercion rules for primitives

NEW QUESTION # 117
Refer to the code below:
const searchText = 'Yay! Salesforce is amazing!';
let result1 = searchText.search(/sales/i);
let result2 = searchText.search(/sales/);
console.log(result1);
console.log(result2);
After running this code, which result is displayed on the console?

A. 5
undefined
B. 5
-1
C. true
false
D. 5
0

Answer: B

Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
String: "Yay! Salesforce is amazing!"
Index positions:
'Y' at 0, 'a' at 1, 'y' at 2, '!' at 3, space at 4, 'S' at 5, 'a' at 6, 'l' at 7, 'e' at 8, 's' at 9, etc.
Substring "Sales" starts at index 5.
String.prototype.search with a regex returns the index of the first match or -1 if there is no match.
searchText.search(/sales/i);
/sales/i is case-insensitive because of the i flag.
It matches "Sales" beginning at index 5.
So result1 is 5.
searchText.search(/sales/);
/sales/ is case-sensitive.
It requires lowercase "sales".
The text has "Sales" with uppercase S, so this does not match.
search returns -1 when there is no match.
So result2 is -1.
Console output:
First log: 5
Second log: -1
Option D matches this.
Concepts: regex search, case sensitivity vs i flag, String.prototype.search return values.
________________________________________

NEW QUESTION # 118
A developer writes the code below to return a message to a user attempting to register a new username. If the username is available, a variable named msg is declared and assigned a value on line 03.
```javascript
function getAvailabilityMessage(item) {
if (getAvailability(item)) {
var msg = "Username available";
return msg;
}
}

A. undefined
B. "Username available"
C. "msg is not defined"
D. "newUserName"

Answer: B

NEW QUESTION # 119
Which statement phrases successfully?

A. JSON.parse( " ' foo ' " );
B. JSON.parse(' " foo " ');
C. JSON.parse ( ' foo ' );
D. JSON.parse ( " foo " );

Answer: B

NEW QUESTION # 120
A developer has the following array of student test grades:
Let arr = [ 7, 8, 5, 8, 9 ];
The Teacher wants to double each score and then see an array of the students who scored more than 15 points.
How should thedeveloper implement the request?

A. Let arr1 = arr.map((num) => ( num *2)).filterBy((val) => ( val >15 ));
B. Let arr1 = arr.mapBy (( num) => ( return num *2 )) .filterBy (( val ) => return val > 15 )) ;
C. Let arr1 = arr.map((num) => num*2). Filter (( val) => val > 15);
D. Let arr1 = arr.filter(( val) => ( return val > 15 )) .map (( num) => ( return num *2 ))

Answer: C

NEW QUESTION # 121
......

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