P.S. Free & New JavaScript-Developer-I dumps are available on Google Drive shared by BraindumpsIT: https://drive.google.com/open?id=1mqWxNCGLvvS1Mb8pJxuyugYUdGktnq54
When you buy or download our JavaScript-Developer-I training materials ,we will adopt the most professional technology to encrypt every user’s data，giving you a secure buying environment. If you encounter similar questions during the installation of the JavaScript-Developer-I Practice Questions, our staffs will provide you with remote technical guidance. We believe that our professional services will satisfy you on our best JavaScript-Developer-I exam braindumps.
| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I Exam |
| Exam Number: | JS-Dev-101 / JavaScript-Developer-I |
| Certificate Validity Period: | No expiration; requires regular maintenance via Trailhead modules |
| Related Certifications: | Salesforce Certified Lightning Web Components Specialist Salesforce Certified Platform Developer I |
| Real Exam Qty: | 60 scored + up to 5 unscored |
| Exam Price: | USD 200 (+ applicable taxes) |
| Exam Format: | Multiple-select, Multiple-choice |
| Passing Score: | 65% |
| Available Languages: | Japanese, English |
| Exam Duration: | 105 minutes |
| Recommended Training: | Salesforce JavaScript Developer I Certification Prep |
| Exam Registration: | Salesforce Certification Registration |
| Sample Questions: | Salesforce JavaScript-Developer-I Sample Questions |
| Exam Way: | Online proctored or onsite at authorized testing centers |
| Pre Condition: | No formal prerequisites; 1–2 years of JavaScript development experience recommended |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascript-developer-i |
>> High JavaScript-Developer-I Passing Score <<
In this circumstance, if you are the person who is willing to get JavaScript-Developer-I exam prep, our products would be the perfect choice for you. Here are some advantages of our JavaScript-Developer-I exam prep, our study materials guarantee the high-efficient preparing time for you to make progress is mainly attributed to our marvelous organization of the content and layout which can make our customers well-focused and targeted during the learning process. If you are interested our JavaScript-Developer-I Guide Torrent, please contact us immediately, we would show our greatest enthusiasm to help you obtain the certification.
Salesforce JavaScript-Developer-I Certification Exam is designed for developers who have a strong foundation in JavaScript and are looking to specialize in Salesforce development. JavaScript-Developer-I exam measures the candidate's knowledge of Salesforce development concepts, including Apex, Visualforce, and Lightning Components, as well as their proficiency in JavaScript programming. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is intended to demonstrate the candidate's ability to design, develop and test custom applications on the Salesforce platform.
NEW QUESTION # 114
A developer wrote the following code:
01 let x = object.value;
02
03 try {
04 handleObjectValue(x);
05 } catch(error) {
06 handleError(error);
07 }
The developer has a getNextValue function to execute after handleObjectValue(), but does not want to execute getNextValue() if an error occurs. How can the developer change the code to ensure this behavior?
Answer: A
Explanation:
Requirement:
* getNextValue() should run only if handleObjectValue(x) does not throw an error.
* If an error occurs, handleError(error) should run, and getNextValue() should be skipped.
Option B:
try {
handleObjectValue(x);
getNextValue();
} catch (error) {
handleError(error);
}
Behavior:
* If handleObjectValue(x) succeeds (no error):
* Execution continues to getNextValue();.
* If handleObjectValue(x) throws:
* Control jumps directly to catch, getNextValue() is skipped.
* handleError(error); is called.
This matches the requirement perfectly.
Why others are incorrect:
* A: } then { is invalid JavaScript syntax.
* C:
try {
handleObjectValue(x);
} catch (error) {
handleError(error);
}
getNextValue();
* getNextValue() is called after the try...catch regardless of whether an error occurred. Not acceptable.
* D: finally always runs:
try {
handleObjectValue(x);
} catch (error) {
handleError(error);
} finally {
getNextValue();
}
* getNextValue() will execute in both success and error cases.
Therefore, the correct approach is B.
Concepts: try/catch control flow, finally semantics, placing code inside vs outside try/catch blocks.
NEW QUESTION # 115
01 function Animal(size, type) {
02 this.type = type || ' Animal ' ;
03 this.canTalk = false;
04 }
05
06 Animal.prototype.speak = function() {
07 if (this.canTalk) {
08 console.log( " It spoke! " );
09 }
10 };
11
12 let Pet = function(size, type, name, owner) {
13 Animal.call(this, size, type);
14 this.size = size;
15 this.name = name;
16 this.owner = owner;
17 }
18
19 Pet.prototype = Object.create(Animal.prototype);
20 let pet1 = new Pet();
Given the code above, which three properties are set for pet1?
Answer: B,D,E
Explanation:
When pet1 = new Pet(); is created:
* Inside Pet constructor:
Animal.call(this, size, type);
this.size = size;
this.name = name;
this.owner = owner;
* Animal.call(this, size, type):
* Sets this.type = type || ' Animal ' # ' Animal ' (because type is undefined).
* Sets this.canTalk = false.
* Then this.size, this.name, this.owner are set (to undefined since no args passed), but they do exist as properties .
So as own properties, pet1 has: type, canTalk, size, name, owner.
* speak is defined on Animal.prototype, so pet1.speak exists by inheritance, but is not an own data property created in the constructor.
From the listed options, three important properties directly set by constructor logic and clearly used in behavior are:
* canTalk
* name
* type
Thus, C, D, E.
NEW QUESTION # 116
01 function changeValue(obj) {
02 obj.value = obj.value / 2;
03 }
04 const objA = {value: 10};
05 const objB = objA;
06
07 changeValue(objB);
08 const result = objA.value;
What is the value of result after the code executes?
Answer: C
Explanation:
* objA is { value: 10 }.
* objB = objA; # both variables reference the same object .
* changeValue(objB);:
obj.value = obj.value / 2; // modifies the shared object
So:
* objA.value becomes 10 / 2 = 5.
Thus result is 5.
NEW QUESTION # 117
Refer to the string below.
Const str='Salesforce';
Which two statements results in the word 'Sales'?
Answer:
Explanation:
See the Answer below in explanation:
Explanation
Str.substring(0,5);
Str.substr(0,5);
NEW QUESTION # 118
Refer to the expression below:
Let x = ('1' + 2) == (6 * 2);
How should this expression be modified to ensure that evaluates to false?
Answer: D
NEW QUESTION # 119
......
Positive JavaScript-Developer-I Feedback: https://www.braindumpsit.com/JavaScript-Developer-I_real-exam.html
What's more, part of that BraindumpsIT JavaScript-Developer-I dumps now are free: https://drive.google.com/open?id=1mqWxNCGLvvS1Mb8pJxuyugYUdGktnq54