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The Oracle 1z1-071 exam covers a wide range of topics, including SQL fundamentals, SQL data manipulation, SQL data control, and SQL queries. It is designed to assess the candidate's ability to work with SQL language in Oracle databases. 1z1-071 Exam is conducted online and consists of a total of 73 questions. 1z1-071 exam duration is 105 minutes, and the passing score for the exam is 66%.

Oracle Database SQL Sample Questions (Q392-Q397):

NEW QUESTION # 392
Examine the description of the ENPLYEES table:

Which two queries return all rows for employees whose salary is greater than the average salary in their department?

A. SELECT.
FROM
SELECT e.", AVG (salary) OVER (PARTITION BY department id) avg_ sal
FROM employees e
WHERE salary > avg_ sal;
B. SELECT"
FROM employees
WHERE salary >
( SELECT AVG
(salary) FROM
employees
GROUP BY department _ id
C. SELECT
FROM employees
WHERE salary > AVG (salary) OVER (PARTITION BY department _ id);
D. SELECT "
FROM employees
WHERE salary > ANY
SELECT AVG (salary)
EROM employees
GROUP BY department_ id);
E. SELECT"
FROM employees e1
WHERE salary >!
SELECT AVG (salary)
FROM employees e2
WHERE e1. Department _id = e2, department_ id

Answer: A,E

NEW QUESTION # 393
Examine this statement which returns the name of each employee and their manager:

You want to extend the query to include employees with no manager. What must you add before JOINto do this?

A. LEFT OUTER
B. CROSS
C. FULL OUTER
D. RIGHT OUTER

Answer: B

NEW QUESTION # 394
Sales data of a company is stored in two tables, SALES1and SALES2, with some data being duplicated across the tables. You want to display the results from the SALES1table, which are not present in the SALES2table.

Which set operator generates the required output?

A. SUBTRACT
B. INTERSECT
C. MINUS
D. PLUS
E. UNION

Answer: C

Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/queries004.htm

NEW QUESTION # 395
View the exhibit and examine the description of the DEPARTMENTS and EMPLOYEES tables.

The retrieve data for all the employees for their EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, the following SQL statement was written:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?

A. The EMPLOYEES and DEPARTMENTS tables have more than one column with the same column name and data type.
B. The DEPARTMENTS table is not used before the EMPLOYEES table in the FROM clause.
C. The table prefix is missing for the column names in the SELECT clause.
D. The NATURAL JOIN clause is missing the USING clause.

Answer: A

Explanation:
Explanation
Natural join needs only one column to be the same in each table. The EMPLOYEES and DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID)

NEW QUESTION # 396
View the Exhibit and examine the structure of the CUSTOMERS and CUST_HISTORY tables.

The CUSTOMERS table contains the current location of all currently active customers.
The CUST_HISTORY table stores historical details relating to any changes in the location of all current as well as previous customers who are no longer active with the company.
You need to find those customers who have never changed their address.
Which SET operator would you use to get the required output?

A. INTERSECT
B. MINUS
C. UNION
D. UNION ALL

Answer: B

NEW QUESTION # 397
......

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