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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Topic 1: Conversion Functions and Conditional Expressions	10%	- NVL, NULLIF, COALESCE and CASE expressions - Implicit and explicit data type conversion - TO_CHAR, TO_NUMBER, TO_DATE functions
Topic 2: Managing Tables and Constraints		- Constraints: primary key, foreign key, unique, check, not null - Temporary and external tables - Data types, creating/altering/dropping tables
Topic 3: Retrieving Data Using SQL SELECT Statement	20%	- SELECT statement syntax and usage - Arithmetic operations and NULL handling - Column aliases, concatenation, literals and DISTINCT
Topic 4: Restricting and Sorting Data	15%	- ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands - WHERE clause and filtering conditions - Operator precedence
Topic 5: Displaying Data from Multiple Tables	15%	- Cartesian products - Equijoins and non-equijoins - Self-joins and outer joins
Topic 6: Managing Views		- Updatable and read-only views - Create, modify and drop views
Topic 7: Using Single-Row Functions to Customize Output	20%	- Character, number, and date functions - Nested functions usage
Topic 8: Manipulating Data and Managing Transactions		- INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - Multi-table inserts
Topic 9: Aggregating Data Using Group Functions	10%	- GROUP BY and HAVING clauses - SUM, AVG, COUNT, MAX, MIN functions - Handling NULLs in group functions
Topic 10: Relational Database Concepts	10%	- Relationship between database and SQL - ERD and SQL statement mapping - Theoretical and physical aspects of relational databases
Topic 11: Using Data Dictionary Views		- Retrieve metadata and object information
Topic 12: Using Subqueries to Solve Queries		- Single-row and multi-row subqueries - Correlated subqueries for update/delete
Topic 13: Working with Time Zones and Date/Time Data		- TIMESTAMP, INTERVAL data types - Time zone conversion functions
Topic 14: Using SET Operators		- UNION, UNION ALL, INTERSECT, MINUS operators - Ordering results with set operations
Topic 15: Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and maintain indexes - Create and use sequences
Topic 16: Controlling User Access		- System and object privileges - Roles, granting and revoking privileges

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Oracle Database SQL Sample Questions (Q239-Q244):

NEW QUESTION # 239
Examine these statements executed in a single Oracle session:
CREATE TABLE product (pcode NUMBER(2),pname VARCHAR2(20));
INSERT INTO product VALUES(1,'pen');
INSERT INTO product VALUES (2,'pencil');
INSERT INTO product VALUES(3,'fountain pen');
SAVEPOINT a;
UPDATE product SET pcode=10 WHERE pcode =1;
COMMIT;
DELETE FROM product WHERE pcode =2;
SAVEPOINT b;
UPDATE product SET pcode=30 WHERE pcode =3;
SAVEPOINT c;
DELETE FROM product WHERE pcode =10;
ROLLBACK TO SAVEPOINT b;
COMMIT;
Which three statements are true

A. The code for pen is 10.
B. There is no row containing pencil.
C. There is no row containing fountain pen.
D. There is no row containing pen
E. The code for fountain pen is 3
F. The code for pen is 1.

Answer: A,B,D

Explanation:
* After creation and initial inserts, the pcode for 'pen' is updated to 10, and then committed.
* The 'pencil' row is deleted and not yet committed.
* A savepoint b is set after the deletion of the 'pencil' row.
* The 'fountain pen' pcode is updated to 30, followed by setting savepoint c.
* The 'pen' row (now with pcode 10) is deleted.
* A rollback to savepoint b reverts the deletion of 'pen' and the update to 'fountain pen', but not the deletion of 'pencil', which was committed earlier due to the scope of the savepoint.
* Therefore, after the final commit:
* A: The code for 'pen' is 10, since the update was committed and the subsequent delete was rolled back.
* C: There is no row containing 'pencil' because its deletion was committed.
* F: There is a row containing 'pen' because the deletion was rolled back to savepoint b which was set after the deletion of 'pencil'.

NEW QUESTION # 240
Examine the structure of the MEMBERS table:

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution? (Choose the best answer.)

A. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
B. It displays all cities in descending order, within which the last names are further sorted in descending order.
C. It fails because a column alias cannot be used in the ORDER BY clause.
D. It displays all cities in ascending order, within which the last names are further sorted in descending order.

Answer: D

NEW QUESTION # 241
View the Exhibit and examine the structure of ORDERSand ORDER_ITEMStables.
ORDER_IDis the primary key in the ORDERStable. It is also the foreign key in the ORDER_ITEMStable wherein it is created with the ON DELETE CASCADEoption.
Which DELETEstatement would execute successfully?

DELETE orders o, order_items i

A. FROM orders
WHERE order_total < 1000;
B. FROM orders
WHERE (SELECT order_id
FROM order_items);
DELETE orders
C. WHERE order_total < 1000;
DELETE order_id
D. WHERE o.order_id = i.order_id;
DELETE

Answer: C

NEW QUESTION # 242
The ORDERS table a primary key constrain on the ORDER_ID column.
The ORDER_ITEMS table has a foreign key constraint on the ORDER_ID column, referencing the primary key of the ORDERS table.
The constraint is defined with ON DELETE CASCADS.
There are rows in the ORDERS table with an ORDER_TOTAL of less than 1000.
Which three DELETE statements execute successfully?

A. DELETE FROM orders WHERE order_total < 1000;
B. DELETE orders WHERE order_total < 1000;
C. DELETE FROM orders;
D. DELETE order_id FROM orders WHERE order_total < 1000;
E. DELETE * FROM orders WHERE order_total < 1000;

Answer: A,B,C

NEW QUESTION # 243
View the exhibit and examine the structures of the EMPLOYEESand DEPARTMENTStables.

You want to update EMPLOYEEStable as follows:
Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
Set department_idfor these employees to the department_idcorresponding to London (location_id 2100).
Set the employees' salary in location_id2100 to 1.1 times the average salary of their department.
Set the employees' commission in location_id2100 to 1.5 times the average commission of their department.
You issue the following command:

What is outcome?

A. It generates an error because multiple columns (SALARY, COMMISSION) cannot be specified together in an UPDATE statement.
B. It executes successfully but does not give the desired update
C. It executes successfully and gives the desired update
D. It generates an error because a subquery cannot have a join condition in a UPDATE statement.

Answer: B

NEW QUESTION # 244
......

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