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WGU Foundations-of-Programming-Python Exam Syllabus Topics:

SectionObjectives
Topic 1: File Handling and Exceptions- Exception Handling (try, except, finally)
- Custom Exceptions
- Reading and Writing Files
Topic 2: Testing and Debugging- Debugging Techniques
- Unit Testing Concepts
- Trace Errors
Topic 3: Python Fundamentals- Variables and Data Types
- Type Conversion
- Input/Output Operations
- Operators and Expressions
Topic 4: Control Structures- Loops (for, while)
- Nested Conditionals and Loops
- Conditional Statements (if, elif, else)
- Loop Control (break, continue, pass)
Topic 5: Data Structures- Sets
- Dictionaries
- String Manipulation
- Tuples
- Lists and List Operations
Topic 6: Functions- Return Values
- Recursion
- Function Definition and Call
- Parameters and Arguments
- Scope (local and global)
Topic 7: Object-Oriented Programming- Attributes and Methods
- Classes and Objects
- Encapsulation
- Inheritance
- Constructors (__init__)

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WGU Foundations of Programming (Python) - E010 JIV1 Sample Questions (Q32-Q37):

NEW QUESTION # 32
Which loop structure processes every individual item in a list called grades?

Answer: B

Explanation:
The loop:
for grade in grades:
print(grade)
processes every individual item in the list grades.
The variable grade represents the current item being processed. Python's documentation explains that a for statement iterates over the items of a sequence in order.
Therefore, the correct answer isB. for grade in grades:.


NEW QUESTION # 33
Write a complete function word_count(text) that counts and returns the number of words in the given text.
Words are separated by spaces.
For example, word_count( " Hello world Python " ) should return 3.
def word_count(text):
# TODO: Count and return the number of words in text
pass

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one string parameter named text.
Step 2: Since words are separated by spaces, use the .split() method to split the string into a list of words.
Step 3: Use len() to count how many items are in the list.
Step 4: Return that count.
Correct code:
def word_count(text):
return len(text.split())
Example:
print(word_count( " Hello world Python " ))
Output:
3


NEW QUESTION # 34
Which components are required in every Python while loop?

Answer: A

Explanation:
A Python while loop needs a condition and an indented code block.
Example:
count = 1
while count < = 3:
print(count)
count += 1
The condition is count < = 3. The indented block contains the code that runs while the condition is true.
Python's compound statement documentation includes while as a control-flow statement.
Therefore, the correct answer isA. A condition and an indented code block.


NEW QUESTION # 35
Fix the logic error in this function that should return the larger of two numbers.
def find_maximum(a, b):
if a < b:
return a
else:
return b

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function should return the larger number.
Step 2: The condition a < b means b is larger than a.
Step 3: In the original code, when a < b is true, it incorrectly returns a.
Step 4: The return values need to be corrected.
Correct code:
def find_maximum(a, b):
if a < b:
return b
else:
return a
Alternative correct code:
def find_maximum(a, b):
if a > b:
return a
else:
return b
Example:
print(find_maximum(10, 20))
print(find_maximum(30, 15))
Output:
20
30


NEW QUESTION # 36
Fix the off-by-one error in this function that should return the first 3 characters of a string.
def first_three(text):
return text[0:2]

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: Python string slicing uses this format:
text[start:stop]
Step 2: The start index is included.
Step 3: The stop index is excluded.
Step 4: To return the first 3 characters, start at index 0 and stop at index 3.
Correct code:
def first_three(text):
return text[0:3]
Simplified correct code:
def first_three(text):
return text[:3]
Example:
print(first_three( " Python " ))
Output:
Pyt


NEW QUESTION # 37
......

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