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| Section | Objectives |
|---|
| Topic 1: Layer 2 Switching and VLANs | - Ports and VLAN tagging - Bridging components - Inter-VLAN routing - Frame processing - Native VLANs and voice VLANs
|
| Topic 2: BGP | - Attributes and path selection - BGP basic operations and message types - EBGP and IBGP peer interactions
|
| Topic 3: IS-IS | - Link-state database and PDUs - Adjacencies and troubleshooting - Levels, areas and metrics
|
| Topic 4: Spanning Tree | - Convergence and reconvergence - Bridge Protocol Data Units (BPDUs) - STP and RSTP concepts, roles and states
|
| Topic 5: Layer 2 Security | - BPDU, loop and root protection - Layer 2 firewall filters - MACsec and storm control - Port security (MAC limiting, DHCP snooping, DAI, IP source guard)
|
| Topic 6: Protocol-Independent Routing | - Static, aggregate, generated routes - Martian addresses and RIB groups - Load balancing and filter-based forwarding
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| Topic 7: OSPF | - Areas and LSA types - Router ID, adjacencies and neighbors - Link-state database and packet types
|
| Topic 8: High Availability | - VRRP, NSR, NSB and BFD - Link Aggregation Groups and RTG - Virtual chassis and graceful restart
|
| Topic 9: Tunnels | - GRE and IP-IP configuration and troubleshooting - IP tunneling concepts
|
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Juniper Enterprise Routing and Switching, Specialist (JNCIS-ENT) Sample Questions (Q194-Q199):
NEW QUESTION # 194
Which two types of tunnels are able to be created on all Junos devices? (Choose two.)
- A. IPsec
- B. IP-IP
- C. STP
- D. GRE
Answer: B,D
NEW QUESTION # 195
What is a purpose of using a spanning tree protocol?
- A. to look up MAC addresses
- B. to tunnel Ethernet frames
- C. to eliminate broadcast storms
- D. to route IP packets
Answer: C
Explanation:
A broadcast storm is a network condition where a large number of broadcast packets are sent and received by multiple devices, causing congestion and performance degradation. A broadcast storm can occur when there are loops in the network topology, meaning that there are multiple paths between two devices.
A spanning tree protocol is a network protocol that prevents loops from being formed when switches or bridges are interconnected via multiple paths. It does this by creating a logical tree structure that spans all the devices in the network, and disabling or blocking the links that are not part of the tree, leaving a single active path between any two devices.
By eliminating loops, a spanning tree protocol also eliminates broadcast storms, as broadcast packets will not be forwarded endlessly along the looped paths. Instead, broadcast packets will be sent only along the tree structure, reaching each device once and avoiding congestion.
NEW QUESTION # 196
Referring to the exhibit, which two statements are correct? (Choose two.)

- A. The ge-0/0/10 interface will be part of the RSTP topology but will block incoming BPDUs.
- B. This device must be selected as the root bridge.
- C. The ge-0/0/13 interface will be selected as the forwarding interface.
- D. The ge-0/0/10 interface will not participate in the RSTP topology.
Answer: C,D
NEW QUESTION # 197
Click the Exhibit button. You have three Juniper Networks EX Series Switches in an STP domain as shown in the exhibit. Which statement describes the switch that will be elected as the root bridge?

- A. EX-2, because its priority is the lowest.
- B. EX-1, because its priority is the highest.
- C. EX-2, because its MAC address is the lowest.
- D. EX-1, because its MAC address is the highest.
Answer: A
Explanation:
Root bridge election in Spanning Tree Protocol is governed entirely by the Bridge Identifier, an 8- byte value formed by concatenating the configured bridge priority (the higher-order, more significant portion of the comparison) with the switch's MAC address (used strictly as a tiebreaker when priorities are identical). Every participating switch compares Bridge IDs, and the switch advertising the numerically lowest Bridge ID is elected root. In this exhibit, the three switches have distinctly different priority values -- EX-1 at the Junos/IEEE default of 32768, EX-2 at 8192, and EX-3 at 16384 -- meaning the comparison is decided entirely at the priority stage and never needs to proceed to a MAC address tiebreak at all. Since 8192 is numerically the lowest of the three priority values, EX-2 is elected root bridge purely on the strength of its lower priority, regardless of what its MAC address happens to be. This is precisely why the correct answer cites priority rather than MAC address as the deciding factor: MAC address only becomes relevant as a tiebreaker in the specific case where two or more switches share an identical priority value, which is not the situation presented here. Understanding that priority is evaluated first and is independently sufficient to decide the outcome whenever it differs is a foundational and heavily tested Spanning Tree concept on the JNCIS-ENT exam.
NEW QUESTION # 198
What is the default keepalive time for BGP?
- A. 90 seconds
- B. 30 seconds
- C. 10 seconds
- D. 60 seconds
Answer: B
Explanation:
The default hold-time is 90 seconds, meaning that the default frequency for keepalive messages is 30 seconds.
https://www.juniper.net/documentation/us/en/software/junos/bgp/topics/ref/statement/precision-timers-edit-protocols-bgp.html#:~:text=BGP%20on%20the%20local%20routing,keepalive%20messages%20is%2030
%20seconds
NEW QUESTION # 199
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