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Salesforce JS-Dev-101 認定試験の出題範囲:

トピック出題範囲
トピック 1
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
トピック 2
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
トピック 3
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
トピック 4
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
トピック 5
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
トピック 6
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.

>> JS-Dev-101最新な問題集 <<

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Salesforce Certified JavaScript Developer - Multiple Choice 認定 JS-Dev-101 試験問題 (Q141-Q146):

質問 # 141
Given:
const str = 'Salesforce';
Which two statements result in 'Sales'?

正解:A、D

解説:
str = 'Salesforce'
Index positions:
S(0) a(1) l(2) e(3) s(4) f(5) o(6) r(7) c(8) e(9)
substring(start, end)
Start index inclusive, end index exclusive.
str.substring(0, 5) → characters at indices 0-4 → "Sales"
str.substring(1, 5) → indices 1-4 → "ales"
substr(start, length)
Start index, then number of characters.
str.substr(0, 5) → 5 characters starting at index 0 → "Sales"
str.substr(1, 5) → 5 characters from index 1 → "alesf"
So the expressions that return "Sales" are A and C.


質問 # 142
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString && searchString.toLowerCase();
03 document.querySelectorAll('.account').forEach(account => {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?

正解:D

解説:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Line 05 uses the conditional (ternary) operator:
condition ? valueIfTrue : valueIfFalse
In this specific code:
account.style.display = accountName.includes(parsedSearchString)
? /* valueIfTrue */
: /* valueIfFalse */;
accountName.includes(parsedSearchString) returns:
true if the accountName string contains the parsedSearchString,
false otherwise.
The requirement is:
Hide accounts that do not match the search string.
That means:
If the account name includes the search string → it should be visible.
If the account name does not include the search string → it should be hidden.
The relevant property is:
account.style.display
For the display property:
Common values for showing elements:
'block', 'inline', 'inline-block', etc.
Common value for hiding elements:
'none' (element is not rendered and takes up no space).
So we want:
When accountName.includes(parsedSearchString) is true → show the element, e.g. display = 'block'.
When false → hide the element, display = 'none'.
Therefore the assignment should be:
account.style.display = accountName.includes(parsedSearchString) ? 'block' : 'none'; This matches option A:
'block' : 'none'
Why other options are incorrect:
B . 'none' : 'block'
This would hide matching accounts and show non-matching accounts, which is the opposite of the requirement.
C . 'hidden' : 'visible'
These are not valid values for the display property; they belong to the visibility property (visibility: 'hidden' | 'visible'), not display.
D . 'visible' : 'hidden'
Same issue as C: not valid for display, and reversed logic compared to requirement.
Thus, to correctly show matching accounts and hide non-matching ones, the ternary must be:
'block' : 'none'
Reference of JavaScript knowledge documents or Study Guide (concept names only):
Conditional (ternary) operator condition ? exprIfTrue : exprIfFalse
String.prototype.includes for substring checks
DOM APIs: document.querySelectorAll and forEach on NodeLists
Element styling via element.style.display
CSS display property: block vs none
________________________________________


質問 # 143
A developer wants to use a module named universalContainerslib and then call functions from it. How should a developer import every function from the module and then call the functions foo and bar?

正解:A

解説:
import * as lib from '...' imports all named exports from the module into the namespace object lib.
You then call:
lib.foo();
lib.bar();
Option D correctly imports only foo and bar, not every function. The question explicitly says "import every function... and then call foo and bar", so A best matches.
Options B and C are invalid syntax or reference the wrong identifier.


質問 # 144
Refer to the code below:
const pi = 3.1415926;
What is the data type of pi?

正解:D

解説:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
In JavaScript, there is only one numeric type for ordinary numbers: number.
JavaScript number is a double-precision 64-bit binary format (IEEE 754).
There is no separate float, double, or decimal type in core JavaScript.
So:
typeof pi === 'number';
Hence, the correct answer is:
A . Number
Options B, C, D are specific numeric types found in other languages (like C, Java, C#), not distinct types in JavaScript.
Study Guide Concepts:
JavaScript primitive types
typeof operator and number
Lack of separate float / double / decimal types in JS
________________________________________


質問 # 145
A developer writes the code below to return a message to a user attempting to register a new username. If the username is available, a variable named msg is declared and assigned a value on line 03.
```javascript
function getAvailabilityMessage(item) {
if (getAvailability(item)) {
var msg = "Username available";
return msg;
}
}

正解:C


質問 # 146
......

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