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Salesforce JavaScript-Developer-I Certification Exam is designed to test the skills and knowledge of individuals who work with Salesforce’s Lightning Web Components (LWC) and Aura Components. JavaScript-Developer-I exam is intended for developers who have experience building custom applications on the Salesforce platform using JavaScript. Salesforce Certified JavaScript Developer (JS-Dev-101) certification demonstrates the ability to design, develop, and deploy scalable and maintainable custom applications that meet the requirements of businesses and organizations.

Topics of Salesforce JavaScript Developer I Exam

Aspirants must know the exam topics before they start of preparation. Because it will help them to prepare for the below conceptsSalesforce JavaScript-Developer-I exam will include the following topics:

1. Variable, Types, and Collection: 23%

Scenario based codingVariables Creation and InitializationJSON object understanding

2. Object, Functions, and Classes: 25%

Implementation of different functionsUnderstanding of different modules of JavascriptScope of variables and their execution flow

3. Browser and Events: 17%

Handling and propagation of eventsDevelopment tools of browsersUnderstanding of browser specific APIs

4. Asynchronous Programming: 13%

Asynchrounous programming different conceptsMonitoring and management of different loops

5. Server Side Javascript: 8%

Implementation of Node.jsUnderstanding of Node.js CLI commands

6. Testing: 7%

Unit Testingeffectiveness of different tests

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Salesforce JavaScript-Developer-I Certification Exam is a great way for developers to validate their skills and knowledge in using JavaScript with the Salesforce platform. It is a challenging exam that requires candidates to have a deep understanding of the platform and its capabilities, but those who pass the exam will have a valuable credential that can help advance their career in the Salesforce ecosystem.

Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q68-Q73):

NEW QUESTION # 68
Refer to the code below:
Let car1 = new Promise((_ , reject) =>
setTimeout(reject, 2000, "car 1 crashed in" =>
Let car2 =new Promise(resolve => setTimeout(resolve, 1500, "car 2 completed") Let car3 =new Promise(resolve => setTimeout(resolve, 3000, "car 3 completed") Promise.race(( car1, car2, car3))
.then (value => (
Let result = '$(value) the race.';)}
.catch(arr => {
console.log("Race is cancelled.", err);
});
What is the value of result when Promise.race executes?

A. Car 2 completed the race.
B. Race is cancelled.
C. Car 3 completes the race
D. Car 1 crashed in the race.

Answer: A

NEW QUESTION # 69
developer wants to use a module nameduniversalContainersLib and them callfunctions from it.
How should a developer import every function from the module and then call the functions foo and bar ?

A. import * ad lib from '/path/universalContainersLib.js';lib.foo();lib.bar();
B. import all from
'/path/universalContaineraLib.js';universalContainersLib.foo();universalContainersLib.bar();
C. import * from
'/path/universalContaineraLib.js';universalContainersLib.foo();universalContainersLib.bar();
D. import (foo,bar) from '/path/universalContainersLib.js';foo();bar();

Answer: A

NEW QUESTION # 70
static delay = async delay = > {
return new Promise(resolve = > {
setTimeout(resolve, delay);
});
};
static asyncCall = async () = > {
await delay(1000);
console.log(1);
};
console.log(2);
asyncCall();
console.log(3);
Assume delay and asyncCall are in scope as functions.
What is logged to the console?

A. 2 3 1
B. 1 3 2
C. 1 2 3
D. 2 1 3

Answer: A

Explanation:
The correct answer is D , because JavaScript executes synchronous code first, while the code after await runs later after the Promise resolves.
The execution order is:
console.log(2);
This runs first, so JavaScript logs:
2
Then this line runs:
asyncCall();
The asyncCall() function starts executing. Inside it, JavaScript reaches:
await delay(1000);
The delay(1000) function returns a Promise that resolves after 1000 milliseconds:
return new Promise(resolve = > {
setTimeout(resolve, delay);
});
Because await pauses the rest of the asyncCall() function, this line does not run immediately:
console.log(1);
Instead, JavaScript continues executing the remaining synchronous code outside the async function:
console.log(3);
So JavaScript logs:
3
After approximately 1000 milliseconds, the Promise returned by delay(1000) resolves. Then the paused async function continues and runs:
console.log(1);
So JavaScript logs:
1
Final console output:
2
3
1
Important JavaScript concepts involved:
An async function always returns a Promise.
The await keyword pauses execution only inside the async function where it appears.
Code outside the async function continues running normally.
setTimeout() schedules its callback to run later, after the current synchronous code has finished.
Therefore, the verified answer is D. 2 3 1 .

NEW QUESTION # 71
Which code statement correctly retrieves and returns an object from localStorage?

A. constretrieveFromLocalStorage = (storageKey) =>{return window.localStorage[storageKey];}
B. const retrieveFromLocalStorage = (storageKey) =>{return window.localStorage.getItem(storageKey);}
C. const retrieveFromLocalStorage = () =>{return
JSON.stringify(window.localStorage.getItem(storageKey));}
D. const retrieveFromLocalStorage = (storageKey) =>{return
JSON.parse(window.localStorage.getItem(storageKey));}

Answer: D

NEW QUESTION # 72
Given the code below:
01 setCurrentUrl();
02 console.log( " The current URL is: " + url);
03
04 function setCurrentUrl() {
05 url = window.location.href;
06 }
What happens when the code executes?

A. The url variable has local scope and line 02 executes correctly.
B. The url variable has local scope and line 02 throws an error.
C. The url variable has global scope and line 02 throws an error.
D. The url variable has global scope and line 02 executes correctly.

Answer: D

Explanation:
* Inside setCurrentUrl, url is assigned without var, let, or const :
url = window.location.href;
* In non-strict mode, this implicitly creates a global variable url on window.
Execution order:
* setCurrentUrl(); creates/sets global url to window.location.href.
* console.log( " The current URL is: " + url); has access to url in global scope and prints correctly.
Thus:
* url has global scope.
* Line 02 runs without error and logs a valid string.
So B is correct.

NEW QUESTION # 73
......

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