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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
SQL Functions	- Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions - Single-row functions 1. Character, numeric, date functions
Subqueries and Advanced SQL	- Correlated subqueries and nested queries - Single-row and multi-row subqueries
SQL Retrieval	- SELECT statements and filtering data 1. ORDER BY and row limiting 2. WHERE clause and conditions - Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS
Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints

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Oracle Database SQL Sample Questions (Q179-Q184):

NEW QUESTION # 179
Examine the structure of the BOOKS_TRANSACTIONStable:

You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?
SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE FROM

A. FROM BOOKS_TRANSACTIONS;
SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE"
B. FROM BOOKS_TRANSACTIONS;
C. BOOKS_TRANSACTIONS;
SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM
D. BOOKS_TRANSACTIONS;
SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE"

Answer: A

NEW QUESTION # 180
Examine the structure of the SALES table. (Choose two.)

Examine this statement:

Which two statements are true about the SALES1 table? (Choose two.)

A. It will not be created because of the invalid WHERE clause.
B. It is created with no rows.
C. It will not be created because the column-specified names in the SELECT and CREATE TABLE clauses do not match.
D. It will have NOT NULL constraints on the selected columns which had those constraints in the SALES table.
E. It has PRIMARY KEY and UNIQUE constraints on the selected columns which had those constraints in the SALES table.

Answer: B,D

NEW QUESTION # 181
Examine the structure of the MEMBERS table: (Choose the best answer.)

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution?

A. It fails because a column alias cannot be used in the ORDER BY clause.
B. It displays all cities in ascending order, within which the last names are further sorted in descending order.
C. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
D. It displays all cities in descending order, within which the last names are further sorted in descending order.

Answer: B

NEW QUESTION # 182
Which three statements are true about performing DML operations on a view with no INSTEAD OF triggers defined?

A. The WITH CHECK clause has no effect when deleting rows from the underlying table through the view.
B. Views cannot be used to add or modify rows in an underlying table If the defining query of the view contains the DISTINCT keyword.
C. Delete statements can always be done on a table through a view.
D. Insert statements can always be done on a table through a view.
E. Views cannot be used to add rows to an underlying table If the table has columns with NOT NULL constraints lacking default values which are not referenced in the defining query of the view.
F. Views cannot be used to query rows from an underlying table if the table has a PRIMARY KEY and the primary key columns are not referenced in the defining query of the view.

Answer: B,E,F

NEW QUESTION # 183
View the Exhibit and examine the structure of the PROMOTION table.
You have to generate a report that displays the promo named start data for all promos that started after that last promo in the 'INTTERNET' category.

A. SELECT promo-name, promo-being _date FROM promotions
Where promo_being_data >ALL (SELECT MAX (promo_being-date)
FROM promotions ) AND
Promo-category ='INTERNET';
B. SELECT promo_neme, promo_being_date FROM promotions
WHERE promo_being_date > All (SELECT promo_beinjg-date
FROM promotions
WHERE promo_category ='INTERNET' );
C. Select promo_name, promo_being_date FROM promoptions
WHERE promo_being_data > ANY (SELCT promo_being-date
FROM promotions
WHERE promo_category = 'INTERNET'
D. SELECT promo-name, promo-being_date FROM promotion
WHERE promo-being-date IN (SELECT promo_biing_date
FROM promotions
WHERE promo_category='INTYERNET');

Answer: B

NEW QUESTION # 184
......

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