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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-101 |
| Available Languages: | English |
| Certificate Validity Period: | Lifetime (No renewal required) |
| Exam Format: | Multiple Select, Multiple Choice |
| Exam Price: | $200 USD |
| Related Certifications: | Lightning Web Components Specialist Superbadge Salesforce Certified JavaScript Developer I |
| Real Exam Qty: | 60 (plus up to 5 unscored pilot questions) |
| Exam Duration: | 105 minutes |
| Passing Score: | 65% |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online (Proctored) |
| Pre Condition: | Completion of the Lightning Web Components Specialist Superbadge is required to earn the full credential, though it can be completed before or after the exam. |
| Official Syllabus URL: | https://trailhead.salesforce.com/en/credentials/javascriptdeveloperi |
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NEW QUESTION # 72
Refer to the code below:
01 let sayHello = () => {
02 console.log('Hello, World!');
03 };
Which code executes sayHello once, two minutes from now?
Answer: C
Explanation:
To schedule a function for later execution in JavaScript, the standard built-in method is:
setTimeout(functionReference, delayInMilliseconds)
Characteristics of setTimeout():
Executes only once.
Delay is specified in milliseconds.
Requires passing the function reference, not calling the function.
Two minutes is:
2 minutes = 120 seconds = 120,000 milliseconds
Now evaluate each option:
Option A: delay(sayHello, 120000);
Incorrect.
There is no built-in delay() function in JavaScript.
Option B: setTimeout(sayHello, 120000);
Correct.
sayHello is passed as a function reference, so it will execute once after 120,000 ms.
Option C: setTimeout(sayHello(), 120000);
Incorrect.
sayHello() calls the function immediately, and the return value (undefined) is passed to setTimeout.
This executes the function right away instead of after two minutes.
Option D: setInterval(sayHello, 120000);
Incorrect.
setInterval() repeats execution every 120,000 ms.
The question requires executing the function once, so this cannot be correct.
JavaScript Knowledge Reference (text-only)
setTimeout() schedules a function to run once after a specified delay.
Passing functionName gives a reference; passing functionName() invokes it immediately.
setInterval() repeats indefinitely, unlike setTimeout().
NEW QUESTION # 73
A developer needs to debug a Node.js web server because a runtime error keeps occurring at one of the endpoints.
The developer wants to test the endpoint on a local machine and make the request against a local server to look at the behavior. In the source code, the server.js file will start the server. The developer wants to debug the Node.js server only using the terminal.
Which command can the developer use to open the CLI debugger in their current terminal window?
(With corrected typing errors: node_inspect → node inspect, node_start_inspect → node start inspect.)
Answer: B
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Node.js includes a built-in command-line (CLI) debugger. To use it directly in the terminal, the standard command is:
node inspect server.js
This:
Starts server.js under the Node.js inspector.
Opens the CLI debugger right in the terminal window where you ran the command.
Lets you interactively:
Step through code
Set breakpoints
Inspect variables
Continue execution, etc.
Why B is correct:
Option B (corrected to node inspect server.js) is exactly the standard Node.js command to run a script under the CLI debugger in the current terminal.
It does not rely on any external GUI tools.
You stay entirely in the terminal to debug.
Why the other options are incorrect:
A . node start inspect server.js
There is no start subcommand like this in standard Node.js CLI.
This is not a valid Node.js debugging command.
C . node server.js --inspect
This starts Node.js with the Inspector protocol enabled and is typically used to connect external tools like Chrome DevTools or VS Code.
It does not open the CLI debugger in the current terminal. Instead, it opens a debugging port that other tools attach to.
The question specifically says "only using the terminal" and "open the CLI debugger in their current terminal window", which points to node inspect, not --inspect.
D . node -i server.js
-i starts Node in interactive REPL mode, optionally after running a script.
This is for an interactive shell, not the Node debugger.
It does not provide breakpoint/step/next/continue debugging features like the CLI debugger.
Therefore, the only option that opens the Node.js CLI debugger in the current terminal is:
JavaScript / Node.js knowledge / Study Guide references (concept names only, no links):
Node.js CLI debugger: node inspect <script>
Node.js inspector protocol: node --inspect
Difference between CLI debugger and DevTools-based debugging
Node.js command-line options and subcommands
________________________________________
NEW QUESTION # 74
Universal Containers (UC) just launched a new landing page, but users complain that the website is slow. A developer found some functions that might cause this problem. To verify this, the developer decides to execute everything and log the time each of these three suspicious functions consumes.
01 console.time('Performance');
02
03 maybeAHeavyFunction();
04
05 thisCouldTakeTooLong();
06
07 orMaybeThisOne();
08
09 console.endTime('Performance');
Which function can the developer use to obtain the time spent by every one of the three functions?
Answer: C
Explanation:
JavaScript consoles (browsers and Node) provide timing utilities:
console.time(label) - starts a timer with the given label.
console.timeEnd(label) - stops the timer and logs the total elapsed time.
console.timeLog(label) - logs the current elapsed time without stopping the timer.
To measure the time taken by each function separately while still using a single overall timer, you can log intermediate times:
console.time('Performance');
maybeAHeavyFunction();
console.timeLog('Performance', 'after maybeAHeavyFunction');
thisCouldTakeTooLong();
console.timeLog('Performance', 'after thisCouldTakeTooLong');
orMaybeThisOne();
console.timeLog('Performance', 'after orMaybeThisOne');
console.timeEnd('Performance');
Each console.timeLog('Performance') call prints the elapsed time since console.time('Performance') was started, so you can infer how long each function took.
Note: console.endTime in the original snippet is incorrect; the real method is console.timeEnd.
Why other options are incorrect:
B . console.trace()
Prints a stack trace, not timing information.
C . console.timeStamp()
Used with browser performance tools; it does not directly show elapsed times like timeLog or timeEnd.
D . console.getTime()
Not a standard console method.
Thus, the function that can be used to obtain timing between calls is:
Answe r: A
Study Guide Concepts:
console.time, console.timeLog, console.timeEnd
Measuring performance and intermediate timings
Standard console debugging API methods
NEW QUESTION # 75
A developer creates a class that represents a news story based on the requirements that a Story should have a body, author, and view count. The code is shown below:
01 class Story {
02 // Insert code here
03 this.body = body;
04 this.author = author;
05 this.viewCount = viewCount;
06 }
07 }
Which statement should be inserted in the placeholder on line 02 to allow for a variable to be set to a new instance of a Story with the three attributes correctly populated?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
In ES6 class syntax, the special method used to initialize a new instance is called constructor.
A class definition syntax:
class ClassName {
constructor(param1, param2) {
this.prop1 = param1;
this.prop2 = param2;
}
}
The constructor method:
Is called automatically when you create a new instance with new ClassName(...).
Receives the arguments passed in the new expression.
Assigns values to this to set instance properties.
Applying this to Story
We want to be able to write:
const article = new Story('Some body', 'Author Name', 100);
and have:
article.body === 'Some body'
article.author === 'Author Name'
article.viewCount === 100
To achieve this, the class must have:
class Story {
constructor(body, author, viewCount) {
this.body = body;
this.author = author;
this.viewCount = viewCount;
}
}
So the correct line 02 is:
constructor(body, author, viewCount) {
Why the other options are incorrect
A . constructor() {
This defines a constructor with no parameters.
The lines inside the constructor use body, author, and viewCount, which would be undefined unless they exist in an outer scope (they normally do not).
This would lead to the instance properties being set to undefined in normal usage.
B . super(body, author, viewCount) {
super(...) is used inside a constructor of a subclass to call the parent class constructor.
You cannot use super(...) { as a method definition; this is invalid syntax in a class body.
Additionally, Story as given is not shown extending any class, so super is inappropriate here.
C . function Story(body, author, viewCount) {
Inside a class definition, you do not use the function keyword to define methods.
function Story(...) here would be invalid syntax in a class body.
Even if it were allowed, the special constructor method for a class is named constructor, not the class name.
Therefore, only:
constructor(body, author, viewCount) {
correctly declares the constructor for the Story class and ensures instances created with new Story(body, author, viewCount) have all three properties populated.
Reference / Study Guide concepts (no links):
ES6 class syntax
constructor method in classes
this and instance properties in classes
Difference between class constructors and regular functions
Invalid use of super and function inside class bodies
________________________________________
NEW QUESTION # 76
Given the followingcode, what is the value of x?
let x = '15' + (10 * 2);
Answer: B
NEW QUESTION # 77
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