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NEW QUESTION # 130
A developer wrote a fizzbuzz function that when passed in a number, returns the following:
* 'Fizz' if the number is divisible by 3.
* 'Buzz' if the number is divisible by 5.
* 'Fizzbuzz' if the number is divisible by both 3 and 5.
* Empty string if the number is divisible by neither 3 or 5.
Which two test cases will properly test scenarios for the fizzbuzz function?
Choose 2 answers
Answer: A,C,D
NEW QUESTION # 131
Refer to the code below:
let productSKU = ' 8675309 ' ;
A developer has a requirement to generate SKU numbers that are always 19 characters long, starting with ' sku ' , and padded with zeros.
Which statement assigns the value sku000000008675309?
Answer: B
Explanation:
We start with:
let productSKU = ' 8675309 ' ;
The requirement:
* Final SKU string:
* Length: 19 characters.
* Starts with ' sku ' .
* Remaining characters are digits padded with zeros on the left (to reach total length).
We can use String.prototype.padStart and String.prototype.padEnd:
* str.padStart(targetLength, padString)
* If str.length < targetLength, it adds padString to the start until the length is targetLength.
* str.padEnd(targetLength, padString)
* Similar, but adds padString to the end.
We want a pattern like:
* First, pad the numeric part out to a fixed length with zeros.
* Then, pad to total length with ' sku ' at the start.
* Analyze Option B
productSKU = productSKU.padStart(16, ' 0 ' ).padStart(19, ' sku ' );
Step 1: productSKU.padStart(16, ' 0 ' )
* Initial productSKU is ' 8675309 ' (length 7).
* After padStart(16, ' 0 ' ), we pad zeros on the left to reach length 16.
* We need 16 # 7 = 9 zeros:
Result after step 1:
productSKU === ' 0000000008675309 ' // length 16
Step 2: .padStart(19, ' sku ' )
* Now productSKU has length 16.
* We call padStart(19, ' sku ' ):
* We need 19 # 16 = 3 extra characters.
* The pad string ' sku ' is exactly 3 characters, so it is added as-is at the start.
Result after step 2:
productSKU === ' sku0000000008675309 ' // length 19
This satisfies:
* Length 19.
* Starts with ' sku ' .
* Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.
While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:
* 3 characters of ' sku '
* Numeric part padded with zeros to make 16 characters total for the numeric part
* 3 + 16 = 19 total characters
Option B matches the intended logic using padStart and padEnd.
* Why the other options are incorrect
Option A:
productSKU = productSKU.padEnd(16, ' 0 ' ).padStart( ' sku ' );
* padEnd(16, ' 0 ' ) produces ' 8675309000000000 ' (original number followed by zeros).
* padStart( ' sku ' ) is invalid usage:
* padStart takes a numeric target length as the first argument, not a string.
* Passing ' sku ' as the first argument leads to type coercion that does not achieve the intended behavior.
* This will not reliably produce the desired SKU.
Option C:
productSKU = productSKU.padEnd(16, ' 0 ' ).padStart(19, ' sku ' );
* First padEnd(16, ' 0 ' ) from ' 8675309 ' gives ' 8675309000000000 ' (length 16, zeros at the end).
* Then padStart(19, ' sku ' ) adds 3 chars ' sku ' at the front:
* Result: ' sku8675309000000000 ' .
* This string starts with ' sku ' , but the zeros are at the end of the digits, not padding the numeric part on the left as desired.
Option D:
productSKU = productSKU.padStart(19, ' 0 ' ).padStart( ' sku ' );
* First padStart(19, ' 0 ' ) pads zeros at the left to make the length 19.
* Then padStart( ' sku ' ) again incorrectly uses a string where a numeric targetLength is required.
* This will not produce the correct SKU format.
Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with ' sku ' is:
The answer: B
References / Study Guide concepts (no links):
* String.prototype.padStart(targetLength, padString)
* String.prototype.padEnd(targetLength, padString)
* String length calculations
* Left-padding numeric strings with zeros
* Building prefixed identifiers with fixed total length
NEW QUESTION # 132
Refer to the HTML below:
<div id="main">
<ul>
<li>Leo</li>
<li>Tony</li>
<li>Tiger</li>
</ul>
</div>
Which JavaScript statement results in changing " Tony" to "Mr. T."?
Answer: A
NEW QUESTION # 133
Refer to the following code block (with corrected template literals using backticks):
01 class Animal {
02 constructor(name) {
03 this.name = name;
04 }
05
06 makeSound() {
07 console.log(`${this.name} is making a sound.`);
08 }
09 }
10
11 class Dog extends Animal {
12 constructor(name) {
13 super(name);
14 this.name = name;
15 }
16 makeSound() {
17 console.log(`${this.name} is barking.`);
18 }
19 }
20
21 let myDog = new Dog( ' Puppy ' );
22 myDog.makeSound();
What is the console output?
Answer: A
Explanation:
* Animal class:
* Has a constructor that sets this.name.
* Has a makeSound method that logs a message using this.name.
* Dog class:
* Extends Animal.
* Its constructor calls super(name) to run the parent constructor, which sets this.name.
* It overrides makeSound() to log:
* console.log(`${this.name} is barking.`);
* Instantiation:
let myDog = new Dog( ' Puppy ' );
myDog.makeSound();
* new Dog( ' Puppy ' ):
* Calls Dog constructor with name = ' Puppy ' .
* Inside, super(name) sets this.name = ' Puppy ' in the Animal constructor.
* Then this.name = name; in the Dog constructor keeps it as ' Puppy ' .
* myDog.makeSound():
* Calls the overridden makeSound() in Dog.
* Logs: " Puppy is barking. "
No reference errors, no undefined; the output is:
Puppy is barking.
Study Guide Concepts:
* ES6 classes and inheritance (extends)
* super() in subclass constructors
* Method overriding in subclasses
* Template literals: `${this.name} ...`
NEW QUESTION # 134
A developer initiates a server with the file server.js and adds dependencies in the source code ' s package.json that are required to run the server.
Which command should the developer run to start the server locally?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From JavaScript/Node.js Knowledge:
In a Node.js project that uses package.json, you typically define a " start " script:
{
" scripts " : {
" start " : " node server.js "
}
}
Then you start the app with:
npm start
npm start:
* Looks up the " start " script in package.json.
* Runs the command defined there (commonly node server.js).
* This is the standard way to start a Node.js app with npm-managed dependencies.
Why others are incorrect:
* A. node start
* Tries to run a file named start with Node; does not use package.json scripts.
* C. npm start server.js
* npm start does not take the script filename as an argument in this way; it just runs the start script as defined.
* D. start server.js
* Not an npm or node command; on some shells it just tries to "start" a process but is not the standard Node/npm workflow.
Relevant concepts: package.json, npm scripts, npm start, Node entry file execution.
NEW QUESTION # 135
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