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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
Topic 1: Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
Topic 2: SQL Functions	- Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions - Single-row functions 1. Character, numeric, date functions
Topic 3: SQL Retrieval	- Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS - SELECT statements and filtering data 1. ORDER BY and row limiting 2. WHERE clause and conditions
Topic 4: Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints
Topic 5: Subqueries and Advanced SQL	- Correlated subqueries and nested queries - Single-row and multi-row subqueries

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1z0-071 Prüfungs-Guide - 1z0-071 Fragen&Antworten

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Oracle Database SQL 1z0-071 Prüfungsfragen mit Lösungen (Q83-Q88):

83. Frage
Examine this query:
SELECT SUBSTR (SYSDATE,1,5) 'Result' FROM DUAL
Which statement is true?

A. It fails unless the expression is modified to TO-CHAR(SUNBSTR(SYSDATE,1,5)
B. It fails unless the expression is modified to SUBSTR (TO_ CHAR(TRUNC(SYSDATE)),1,5)
C. It executes successfully with an implicit data type conversion
D. It fails unless the expression is modified to SUBSTR (TO_ CHAR(SYSDATE),1,5)

Antwort: D

Begründung:
In Oracle Database 12c, the SYSDATE function returns a date value in the current session's date format. The SUBSTR function is used to extract a substring from a string. However, SYSDATE is a DATE data type and not a string, so you cannot directly use SUBSTR on it. Therefore, SYSDATE must first be converted to a character data type using the TO_CHAR function before applying the SUBSTR function.
Therefore, the correct form of the query should be:
SELECT SUBSTR(TO_CHAR(SYSDATE), 1, 5) AS "Result" FROM DUAL;
This converts the current date and time to a string using the default date format and then extracts the first 5 characters from it.

84. Frage
Choose the best answer.
Examine the description of the EMPLOYEES table:

Which query is valid?

A. SELECT dept_id,AVG(MAX(salary)) FROM employees GROUP BY dapt_id;
B. SELECT dept_id,MAX(AVG(salary)) FROM employees GROUP BY dept_id;
C. SELECT depe_id,join_date,SUM(salary) FROM employees GROUP BY dept_id:
D. SELECT dept_id, join_date,SUM(salary) FROM employees GROUP BY dept_id, join_date;

Antwort: D

Begründung:
In Oracle 12c SQL, the GROUP BY clause is used to arrange identical data into groups with the GROUP BY expression followed by the SELECT statement. The SUM() function is then used to calculate the sum for each grouped record on a specific column, which in this case is the salary column.
Option A is valid because it correctly applies the GROUP BY clause. Both dept_id and join_date are included in the SELECT statement, which is a requirement when using these columns in conjunction with the GROUP BY clause. This means that the query will calculate the sum of salaries for each combination of dept_id and join_date. It adheres to the SQL rule that every item in the SELECT list must be either an aggregate function or appear in the GROUP BY clause.
Option B is invalid due to a typo in SELECT depe_id and also because it ends with a colon rather than a semicolon.
Option C is invalid because you cannot nest aggregate functions like MAX(AVG(salary)) without a subquery.
Option D is invalid for the same reason as option C, where it tries to nest aggregate functions AVG(MAX(salary)), which is not allowed directly in SQL without a subquery.
For further reference, you can consult the Oracle 12c documentation, which provides comprehensive guidelines on how to use the GROUP BY clause and aggregate functions like SUM():
Oracle Database SQL Language Reference, 12c Release 1 (12.1): GROUP BY Clause Oracle Database SQL Language Reference, 12c Release 1 (12.1): Aggregate Functions

85. Frage
Examine this data in the EMPLOYERS table:

Which statement will execute successfully?

A. SELECT dept_id, MAX (Last_name), SUM (salary) FROM employees GROUP BY dept_id
B. SELECT dept_id, STDDEV (last_name), SUM (salary) FROM employees GROUP BY dept_id
C. SELECT dept_id, LENGTH (last_name), SUM (salary) FROM employees GROUP BY dept_id
D. SELECT dept_id, INSTR (last_name,'A'), SUM (salary) FROM employees GROUP BY dept_id

Antwort: A

86. Frage
Examine the description of the PRODUCT_STATUS table:

The STATUS column contains the values 'IN STOCK' or 'OUT OF STOCK' for each row Which two queries will execute successfully?

A. SELECT prod_id || q'('s not available)' FROM product_status WHERE status = 'OUT OF STOCK';
B. SELECT prod_id || q"'s not available" FROM product_status WHERE status = 'OUT OF STOCK';
C. SELECT prod_id || q'('s not available)' "CURRENT AVAILABILITY" FROM product_status WHERE status = 'OUT OF STOCK';
D. SELECT prod_id || q'('s not available)' 'CURRENT AVAILABILITY' FROM product_status WHERE status = 'OUT OF STOCK';
E. SELECT prod_id "CURRENT AVAILABILITY" || q'('s not available)' FROM product_status WHERE status = 'OUT OF STOCK';
F. SELECT prod_id || q's not available'' FROM product_status WHERE status='OUT OF STOCK';

Antwort: A,C

Begründung:
Queries that will execute successfully given the PRODUCT_STATUS table:
* C. SELECT prod_id || q'('s not available)' "CURRENT AVAILABILITY" FROM product_status WHERE status = 'OUT OF STOCK';This query will execute successfully because it uses the q quote operator correctly to handle the inclusion of single quotes in the string.
* D. SELECT prod_id || q'('s not available)' FROM product_status WHERE status = 'OUT OF STOCK';Similar to the previous query, it uses the q quote operator correctly and will execute without syntax errors.
Options A, B, E, and F are incorrect because of the incorrect or incomplete use of the quote operator:
* A is incorrect because it has an additional single quote before the FROM clause.
* B is incorrect because of a missing ending single quote after the q quote operator.
* E and F are incorrect because they both use the q quote operator incorrectly; q'('s not available)' is not a valid use of the quote operator, and q"'s not available" incorrectly uses double quotes instead of single quotes.

87. Frage
Examine the structure of the EMPLOYEES table.

You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?

A. (SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180;
B. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000;
C. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100)UNION ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000);
D. SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180;

Antwort: B

88. Frage
......

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