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Salesforce JavaScript-Developer-I Certification Exam is an excellent opportunity for developers looking to demonstrate their expertise in using JavaScript to develop custom applications on the Salesforce platform. Passing the exam requires a strong understanding of JavaScript fundamentals, as well as a solid understanding of the Salesforce architecture and development best practices.
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Salesforce Certified JavaScript Developer I credential is highly valued by employers and is recognized as a mark of excellence in the industry. Salesforce Certified JavaScript Developer (JS-Dev-101) certification demonstrates that an individual has the skills and knowledge required to build custom applications on the Salesforce platform using JavaScript. It is an excellent way for developers to differentiate themselves in a competitive job market and advance their careers.
Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q28-Q33):
NEW QUESTION # 28
Refer to the code:

Given the code above, which three properties are set pet1?
Choose 3 answers:
- A. Name
- B. Size
- C. Owner
- D. Type
- E. canTalk
Answer: B,D,E
NEW QUESTION # 29
const str = ' Salesforce ' ;
Which two statements result in the word " Sales " ?
- A. str.substring(0, 5);
- B. str.substr(s, 5);
- C. str.substr(0, 5);
- D. str.substring(0, 5);
Answer: A,C
Explanation:
Comprehensive and Detailed Explanation:
* " Salesforce " indices: S(0) a(1) l(2) e(3) s(4) f(5) ...
A / C (substring(0, 5)):
* substring(start, end) returns characters from start up to but not including end.
* str.substring(0, 5) # characters at indices 0,1,2,3,4 # " Sales " .
D (substr(0, 5)):
* substr(start, length) returns length characters starting at start.
* str.substr(0, 5) # 5 chars from index 0 # " Sales " .
B is invalid because s is not defined; it should be 0. So the two correct statements are A and D.
NEW QUESTION # 30
Corrected code:
let a = " * " ;
let b = " ** " ;
// x = 3;
console.log(a);
What is displayed when the code executes?
- A. undefined
- B. *
- C. ReferenceError: a is not defined
- D. null
Answer: B
Explanation:
The correct answer is B because variable a is declared and initialized before it is printed.
let a = " * " ;
This creates a block-scoped variable named a and assigns it the string value:
" * "
The line:
// x = 3;
is a comment. JavaScript ignores comments during execution, so this line has no effect.
Then this line runs:
console.log(a);
Since a already exists and contains " * " , the console displays:
* Option A is incorrect because a is defined.
Option C is incorrect because a has an assigned value, so it is not undefined.
Option D is incorrect because a was never assigned null.
Therefore, the verified answer is B .
NEW QUESTION # 31
Refer to the code below:
01 const exec = (item, delay) =>{
02newPromise(resolve => setTimeout( () => resolve(item), delay)),
03 async function runParallel() {
04 Const (result1, result2, result3) = await Promise.all{
05 [exec ('x', '100') , exec('y', 500), exec('z', '100')]
06 );
07 return `parallel is done: $(result1)$(result2)$(result3)`;
08 }
}
}
Which two statements correctly execute the runParallel () function?
Choose 2 answers
- A. runParallel () .then(data);
- B. runParallel ( ). done(function(data){return data;});
- C. Async runParallel () .then(data);
- D. runParallel () .then(function(data)return data
Answer: B,D
NEW QUESTION # 32
A developer needs to test this functions:

Which two assert statements are valid tests for this function?
- A. Console.assert(sum3 (['hello' 2, 3, 4]) NaN);
- B. Console.assert(sum3 ([-3, 2]) -1) ;
- C. Console.assert(sum3([0]) 0) ;
- D. Console.assert(sum3((1, '2' ]) 12 );
Answer: B,D
NEW QUESTION # 33
......
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