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Salesforce JS-Dev-101 Exam Syllabus Topics:

Section	Objectives
Salesforce Platform Integration	- Lightning Web Components (LWC) Basics - Working with Salesforce Data Models
Object-Oriented JavaScript	- Classes and Inheritance - Objects and Prototypes
Asynchronous Programming	- Callbacks, Promises, and Async/Await - API Calls and Data Fetching
Browser and DOM Interaction	- Events and Event Handling - DOM Manipulation
JavaScript Fundamentals	- Variables, Data Types, and Operators - Control Flow and Error Handling - Functions and Scope

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JS-Dev-101考證，JS-Dev-101認證考試解析

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最新的 Salesforce Developers JS-Dev-101 免費考試真題 (Q39-Q44):

問題 #39
A developer has two ways to write a function:
Option A:
01 function Monster() {
02 this.growl = () => {
03 console.log("Grr!");
04 }
05 }
Option B:
01 function Monster() {};
02 Monster.prototype.growl = () => {
03 console.log("Grr!");
04 }
After deciding on an option, the developer creates 1000 monster objects. How many growl methods are created with Option A and Option B?

A. 1 growl method is created regardless of which option is used.
B. 1 growl method is created for Option A. 1000 growl methods are created for Option B.
C. 1000 growl methods are created regardless of which option is used.
D. 1000 growl methods are created for Option A. 1 growl method is created for Option B.

答案：D

解題說明：
Option A:
this.growl = () => { ... } inside the constructor creates a new function per instance.
For 1000 new Monster(), you get 1000 distinct growl functions, each stored on the instance itself.
Option B:
Monster.prototype.growl = () => { ... } attaches growl to the prototype.
All instances share the same single growl function via the prototype chain.
For 1000 instances, only 1 growl method exists in memory.
So: Option A → 1000; Option B → 1.
________________________________________

問題 #40
Why does second have access to variable a?

A. Prototype Chain
B. Inner function's scope
C. Hoisting
D. Outer function's scope

答案：D

解題說明：
The variable a is declared in the outer function's scope. An inner function (second) forms a closure over its outer lexical scope, so it can access a. The reason is the scope chain / outer function's scope, not prototypes or hoisting.

問題 #41
Given the code below:
let numValue = 1982;
Which three code segments result in a correct conversion from number to string?

A. let strValue = numValue.toString();
B. let strValue = String(numValue);
C. let strValue = numValue.toText();
D. let strValue = '' + numValue;
E. let strValue = (String)numValue;

答案：A,B,D

解題說明：
This is not valid JavaScript casting syntax; it is more like a C/Java-style cast.
In JavaScript, that is parsed as a grouping expression (String) and then numValue; it does not convert numValue to a string.
Thus the correct answers are:
B . String(numValue);
C . '' + numValue;
D . numValue.toString();
Relevant concepts: primitive type conversion, String() casting, .toString(), coercion via + with strings.
Explanation:
We want to convert the number 1982 to a string.
Check each option:
A . numValue.toText()
There is no standard toText() method on numbers.
This will result in TypeError: numValue.toText is not a function.
B . String(numValue);
String() as a function converts its argument to a string.
String(1982) returns "1982".
This is correct.
C . '' + numValue;
'' is a string; + with a string operand performs string concatenation.
'' + 1982 → "1982".
This is a common shorthand for number-to-string conversion.
D . numValue.toString();
Number.prototype.toString() converts the number to its string representation.
1982..toString() or (1982).toString() returns "1982".
For the variable, numValue.toString() is valid: "1982".

問題 #42
Refer to the code snippet:
Function getAvailabilityMessage(item) {
If (getAvailability(item)){
Var msg ="Username available";
}
Return msg;
}
A developer writes this code to return a message to user attempting to register a new username. If the username is available, variable.
What is the return value of msg hen getAvailabilityMessage ("newUserName" ) is executed and getAvailability("newUserName") returns false?

A. "newUserName"
B. "Msg is not defined"
C. "Username available"
D. undefined

答案：D

問題 #43
Refer to the code below:

Line 05 causes an error. What are the values of greeting and salutation once code completes?

A. Greeting is Goodbye and salutation is I say Hello.
B. Greeting is Hello and salutation is Hello, Hello.
C. Greeting is Hello and salutation is I say hello.
D. Greeting is Goodbye and salutation is Hello, Hello.

答案：B

問題 #44
......

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