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The HCIP-Datacom-Advanced Routing certification is a comprehensive learning path that provides networking professionals with a deep understanding of advanced routing and switching concepts. HCIP-Datacom-Advanced Routing & Switching Technology V1.0 certification will help professionals stay competitive in the job market and demonstrate their expertise to employers, customers, and colleagues. Obtaining the Huawei H12-831_V1.0 certification can open up new job opportunities, provide greater job security and lead to higher pay.

To pass the Huawei H12-831_V1.0-ENU exam, candidates are required to have a deep understanding of advanced routing and switching technologies. They must also be familiar with Huawei's network devices and solutions. H12-831_V1.0 Exam consists of 60 questions and has a time limit of 90 minutes. Candidates must achieve a passing score of 600 out of 1000 to earn the HCIP-Datacom-Advanced Routing & Switching Technology certification.

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Huawei H12-831_V1.0-ENU exam covers a wide range of topics, including advanced IP routing technologies, MPLS VPN technologies, multicast routing technologies, advanced network security technologies, and more. Passing H12-831_V1.0 Exam will demonstrate that the candidate has a deep understanding of advanced routing and switching technologies, including their design, deployment, and troubleshooting.

Huawei HCIP-Datacom-Advanced Routing & Switching Technology V1.0 Sample Questions (Q171-Q176):

NEW QUESTION # 171
R1 and R2 use directly connected interfaces to establish an EBGP peer relationship. R1 imports 2000:: 1/128 to BGR By default, which of the following is the next hop of the route from R2 to 2000:: 1/128?

Answer: A


NEW QUESTION # 172
An enterprise deploys iBGP across three routers (R1, R2, R3) within the same AS. R1 learns a route from an eBGP neighbor and successfully advertises it to R2. However, R3 does not receive the route from R2. All BGP sessions are established and stable. What is the most likely cause?

Answer: C


NEW QUESTION # 173
On the IS-IS IPv6 network shown in the figure, after the network becomes stable:
* R1 can ping 2000:12::0, and
* The display ipv6 neighbors command can be used to display the MAC address corresponding to
2000:12::0.

Is this statement TRUE or FALSE?

Answer: A

Explanation:
Comprehensive and Detailed In-Depth Explanation:
Understanding the IPv6 Addressing and IS-IS Network
* IPv6 Addressing in the Figure:
* R1 has the address: 2000:12::1/64
* R2 has the address: 2000:12::0/127
* The link between them is using a /127 subnet (2000:12::0/127).
* Behavior of IPv6 /127 Subnet Mask
* In IPv6, a /127 prefix is commonly used on point-to-point links to avoid the issue of subnet- router anycast (::0).
* RFC 6164 recommends using /127 instead of /64 for point-to-point links to reduce unnecessary anycast behavior.
* 2000:12::0 is the network address (first address in the subnet) and is not assigned to an interface.
Analyzing the Two Statements in the Question
Statement 1: "R1 can ping 2000:12::0" # (Incorrect)
* In IPv6, the first address (::0) in a /127 subnet is typically reserved as a network address and not assigned to any router.
* R1 cannot ping 2000:12::0 because it is not assigned to R2 as an active IP.
* Correct ping targets would be:
* R1 pinging R2's actual address (2000:12::1 or 2000:12::2 depending on numbering).
Statement 2: "display ipv6 neighbors command can be used to display the MAC address corresponding to 2000:12::0" # (Incorrect)
* The display ipv6 neighbors command is used to show the MAC address of an active neighbor (i.e., a reachable device).
* Since 2000:12::0 is not assigned to a specific router, it will not have a MAC address in the neighbor table.
Final Conclusion:
# R1 cannot ping 2000:12::0 because it is the network address in a /127 subnet.# The display ipv6 neighbors command cannot show a MAC address for 2000:12::0 because it is not assigned to a router.
Thus, the correct answer is: B. FALSE.


NEW QUESTION # 174
On the OSPFv3 network shown in the figure, the LSDB (Link-State Database) of R2 contains ______ Router-LSAs. (Enter only digits.)

Answer:

Explanation:
3
Explanation:
1. Understanding Router-LSAs in OSPFv3
* Router-LSA (Type 1 LSA) is generated by every OSPFv3 router to describe its own links and connected networks within the same area.
* Each router in an OSPF area generates exactly one Router-LSA to advertise its own topology information.
* Router-LSAs are flooded throughout the area but do not cross area boundaries.
2. Analyzing the Given OSPFv3 Network
* The topology consists of three routers: R1, R2, and R3, all connected in OSPFv3 Area 0.
* Since all three routers participate in OSPFv3, each router generates its own Router-LSA (Type 1 LSA).
* R2, as an OSPF router, will have its own Router-LSA and also receive the Router-LSAs from R1 and R3.
3. Counting the Number of Router-LSAs in R2's LSDB
* R1 generates 1 Router-LSA (for itself).
* R2 generates 1 Router-LSA (for itself).
* R3 generates 1 Router-LSA (for itself).
* Total Router-LSAs in R2's LSDB = 3 (one from each router).
Final Answer:
HCIP-Datacom-Advanced Routing & Switching Technology References:
* OSPFv3 LSA Types and Their Roles
* Understanding Router-LSA (Type 1) and Its Function in LSDB


NEW QUESTION # 175
If display current-configuration can reach the setting of !JIS-IS, and display saved- There is no IS-IS setting in the configuration, so that means?

Answer: A


NEW QUESTION # 176
......

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