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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 2
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 3
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 4
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 5
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 6
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q119-Q124):

NEW QUESTION # 119
Given the code:
01 function GameConsole(name) {
02 this.name = name;
03 }
04
05 GameConsole.prototype.load = function(gamename) {
06 console.log('${this.name} is loading a game: ${gamename}....');
07 }
08
09 function Console16bit(name) {
10 GameConsole.call(this, name);
11 }
12
13 Console16bit.prototype = Object.create(GameConsole.prototype);
14
15 // insert code here
16 console.log('${this.name} is loading a cartridge game: ${gamename}....');
17 }
18
19 const console16bit = new Console16bit('SNEGeneziz');
20 console16bit.load('Super Monic 3x Force');
What should a developer insert at line 15?

Answer: A

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge A subclass created by:
Console16bit.prototype = Object.create(GameConsole.prototype);
inherits all prototype methods from GameConsole, including load.
To override the inherited method, the correct syntax is to assign a new function to the method name on the prototype:
Console16bit.prototype.load = function(gamename) {
console.log(`${this.name} is loading a cartridge game: ${gamename}....`);
};
Why the other options are wrong:
A assigns something to the constructor function itself, not to the prototype method. Invalid.
B attempts to call a function in the left-hand side of an assignment; invalid syntax.
C also uses invalid syntax-prototype methods cannot be defined this way.
D is the correct definition of a prototype method override.
________________________________________
JavaScript Knowledge Reference (text-only)
Methods are overridden by assigning functions to Subclass.prototype.methodName.
Object.create() establishes prototype inheritance.
Constructor functions require prototype method attachment using assignment syntax.


NEW QUESTION # 120
Refer to the code:
01 function execute() {
02 return new Promise((resolve, reject) => reject());
03 }
04 let promise = execute();
05
06 promise
07 .then(() => console.log('Resolved1'))
08 .then(() => console.log('Resolved2'))
09 .then(() => console.log('Resolved3'))
10 .catch(() => console.log('Rejected'))
11 .then(() => console.log('Resolved4'));
What is the result when the Promise in the execute function is rejected?

Answer: D

Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
execute() returns a Promise that immediately calls reject().
So promise starts in a rejected state.
When a Promise is rejected and you chain .then() calls without rejection handlers, all those .then() callbacks are skipped until a .catch() is encountered:
promise
.then(...) // skipped
.then(...) // skipped
.then(...) // skipped
.catch(...) // executed
.then(...); // executed after catch
Execution:
.then(() => console.log('Resolved1')) is skipped.
.then(() => console.log('Resolved2')) is skipped.
.then(() => console.log('Resolved3')) is skipped.
.catch(() => console.log('Rejected')) runs and logs Rejected.
The .catch() returns a resolved Promise (no explicit return, so undefined), so the next .then() runs:
.then(() => console.log('Resolved4')) logs Resolved4.
Final output:
Rejected
Resolved4
This matches option D.
________________________________________


NEW QUESTION # 121
myArraym can have one level, two levels, or more levels.
Which statement flattens myArray when it can be arbitrarily nested?

Answer: A


NEW QUESTION # 122
CRefer to the code below:
```javascript
let strNumber = '12345';
```
Which code snippet shows a correct way to convert this string to an integer?

Answer: C


NEW QUESTION # 123
Which actions can be done using the JavaScript browser console?

Answer: A,C,D

Explanation:
A: Yes. You can run arbitrary JS in the console (even if it doesn't touch the page).
B: Yes. You can inspect and modify DOM nodes via JS.
C: Performance reports are mainly in the Performance tab, not the console.
D: Yes. You can alter the DOM and redefine or override JS functions/variables at runtime.
E: You can read and set document.cookie, but HttpOnly "security cookies" cannot be read or changed from JS.


NEW QUESTION # 124
......

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