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WGU Foundations-of-Computer-Science Exam Syllabus Topics:

SectionObjectives
Computer Science Fundamentals- Core CS Concepts
  • 1. Basic programming logic and algorithms
    • 2. Computational thinking and problem solving
      • 3. Algorithm efficiency and Big-O basics
        - Data Structures Introduction
        • 1. Basic sorting and searching concepts
          • 2. Arrays and lists
            Data & Security Basics- Data Handling
            • 1. Data profiling concepts
              • 2. Basic database concepts overview
                - Security Fundamentals
                • 1. Basic cybersecurity threats and mitigation
                  • 2. Encryption basics (at rest vs in transit)
                    Operating Systems & Architecture- OS Fundamentals
                    • 1. Memory management concepts
                      • 2. Process states and scheduling basics
                        - System Architecture
                        • 1. Von Neumann architecture basics
                          • 2. Hardware vs software abstraction
                            Programming Foundations- Language Concepts Overview
                            • 1. Compiled vs interpreted languages
                              • 2. Programming paradigms overview
                                - Programming Concepts
                                • 1. Variables, data types, expressions
                                  • 2. Control flow (if/else, loops)
                                    • 3. Basic pseudocode interpretation

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                                      WGU Foundations of Computer Science Sample Questions (Q30-Q35):

                                      NEW QUESTION # 30
                                      How does the data type of a variable get set in Python?

                                      Answer: B

                                      Explanation:
                                      Python usesdynamic typing, a core concept emphasized in programming language textbooks. In dynamically typed languages, a variable name does not permanently "own" a type. Instead, theobjectcreated by an expression has a type, and the variable becomes a reference to that object. Therefore, the type associated with a variable at any moment is determined by the value assigned to it. For example, after x = 7, x refers to an integer object. After x = "seven", the same name now refers to a string object. The type changes because the binding changes, not because the variable's type declaration was edited.
                                      Option A describesstatic typingsystems (common in languages like Java, C, or C++), where programmers declare types and compilers enforce them. Python does not require such declarations for ordinary variables.
                                      Option B is incorrect because type assignment is deterministic, not random. Option C is incorrect because Python does not default variables to strings; it assigns whatever type results from the right-hand-side expression.
                                      This model is closely tied to Python's runtime behavior: type checks occur during execution, and functions can accept values of different types as long as the operations used are valid (often discussed as
                                      "duck typing"). This flexibility supports rapid development, but also motivates careful testing and, in larger systems, optional type hints for documentation and tool support.


                                      NEW QUESTION # 31
                                      m = 30
                                      n = 30
                                      What will be the output of print(id(m), id(n)) after executing the following code?

                                      Answer: A

                                      Explanation:
                                      In Python, id(x) returns the "identity" of an object, which in CPython (the most common implementation) is typically the object's memory address. When you write m = 30 and n = 30, both names may refer to thesame integer objectbecause CPython caches a range of small integer objects for efficiency. This optimization means that commonly used small integers are pre-created and reused, so repeated occurrences of the same small integer literal often point to the same object, producing identical id() values. As a result, print(id(m), id (n)) will most likely displaytwo identical numbersin standard CPython builds when 30 falls within the cached range. (Real Python) This behavior is an implementation detail, but it is widely discussed in Python education because it illustrates the difference between object identity (whether two variables reference the same object) and value equality (whether two objects have the same value). Even if id(m) and id(n) were different in some edge environment, m == n would still be True because the values are equal; id() is about identity, not value. The options "0 0" and "Error" are not consistent with how id() works for valid objects.


                                      NEW QUESTION # 32
                                      What is the expected output of calling .shape on a NumPy 2D array?

                                      Answer: C

                                      Explanation:
                                      In NumPy, every ndarray has a shape attribute that describes the size of the array along each dimension. For a
                                      2D array, shape returns a tuple with two integers: (number_of_rows, number_of_columns). For example, if a
                                      = np.array([[1, 2, 3], [4, 5, 6]]), then a.shape is (2, 3), meaning 2 rows and 3 columns. This is a fundamental idea in matrix and array computing, because shape governs how indexing, slicing, broadcasting, and linear algebra operations behave.
                                      Option A describes the dtype, which can be accessed with a.dtype, not a.shape. Option C is incorrect because shape provides per-dimension sizes, not their sum. Option D refers to the total number of elements, which NumPy provides via a.size (or equivalently np.prod(a.shape)).
                                      Textbooks emphasize shape because many errors in numerical computing come from mismatched dimensions. For example, matrix multiplication requires compatible inner dimensions, and broadcasting rules depend on dimension sizes. By checking .shape, programmers can verify their data layout before applying algorithms, ensuring rows represent observations and columns represent features (or vice versa). Thus, for a 2D NumPy array, .shape indicates the number of rows and columns.


                                      NEW QUESTION # 33
                                      How is a NumPy array named data with 6 elements reshaped into a 2x3 array?

                                      Answer: B

                                      Explanation:
                                      Reshaping is the operation of changing the "view" of an array so that the same elements are arranged with new dimensions. In NumPy, reshaping is possible when the total number of elements stays the same. A 2x3 array contains 6 elements, so a 1D array data of length 6 can be reshaped into shape (2, 3) without adding or removing values. Textbooks stress this invariant: the product of the dimensions must equal the original size.
                                      NumPy provides two standard reshaping interfaces: the function np.reshape(data, (2, 3)) and the method data.
                                      reshape(2, 3) (or data.reshape((2, 3))). Option A is correct because it uses the official NumPy function with the proper arguments: the original array and the target shape. The shape is passed as a tuple describing rows and columns.
                                      Option B is incorrect because np_reshape is not the correct NumPy function name, and it references an unrelated identifier list. Option C is incorrect because NumPy arrays do not provide a set_shape method like that. Option D is not valid NumPy syntax for reshaping.
                                      Reshaping is fundamental in data analysis and machine learning: it converts flat vectors into matrices, prepares batches of samples, and aligns dimensions for matrix multiplication and broadcasting.


                                      NEW QUESTION # 34
                                      What is the only content that will display if the List folder contents permission is not enabled for a particular folder in Windows 11?

                                      Answer: D

                                      Explanation:
                                      In Windows file security (NTFS permissions), "List folder contents" controls whether a user cansee the names of files and subfoldersinside a folder. If a user does not have permission to list a folder, Windows prevents directory enumeration: the user cannot browse the folder and view what is inside. (2BrightSparks) This is a key concept in access control: it separates "being able to traverse to a location" from "being able to see what is stored there." When "List folder contents" is not enabled, the user typically cannot view the list of files regardless of whether individual files might have separate permissions. In standard user-facing behavior, what remains visible in the folder's properties and metadata is limited; among the choices given, the only item that is reliably a folder-level metadata attribute (and not a listing of contents) is the folder'screation date. The
                                      "author" is not a universal, reliably displayed NTFS folder property, and options C and D talk about files (contents), which cannot be listed without the list permission. (2BrightSparks) This reflects a broader textbook principle: operating systems enforce access control both on objects (files/folders) and on operations (read data, write data, list directory). Removing the list operation blocks visibility of contents, even if other permissions exist elsewhere.


                                      NEW QUESTION # 35
                                      ......

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