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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints
SQL Retrieval	- SELECT statements and filtering data 1. ORDER BY and row limiting 2. WHERE clause and conditions - Joins and set operations 1. UNION, INTERSECT, MINUS 2. INNER, OUTER, CROSS joins
Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
SQL Functions	- Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions - Single-row functions 1. Character, numeric, date functions
Subqueries and Advanced SQL	- Correlated subqueries and nested queries - Single-row and multi-row subqueries

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Oracle Database SQL Sample Questions (Q50-Q55):

NEW QUESTION # 50
Examine the description of the CUSTOMERS table:

You need to display last names and credit limits of all customers whose last name starts with A or B In lower or upper case, and whose credit limit is below 1000.
Examine this partial query:
SELECT cust_last_nare, cust_credit_limit FROM customers
Which two WHERE conditions give the required result?

A. WHERE UPPER(cust_last_name) IN ('A%', 'B%') AND cust_credit_limit < 1000:
B. WHERE (INITCAP(cust_last_name) LIKE 'A%' OR ITITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000
C. WHERE (UPPER(cust_last_name) like INITCAP ('A') OR UPPER(cust_last_name) like INITCAP('B')) AND ROUND(cust_credit_limit) < ROUND(1000) ;
D. WHERE UPPER(cust_last_name) BETWEEN UPPER('A%' AND 'B%') AND ROUND(cust_credit_limit) < 1000;
E. WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND ROUND(cust_credit_limit) < 1000;

Answer: B,E

NEW QUESTION # 51
Which statement is true regarding external tables?

A. The default REJECT LIMITfor external tables is UNLIMITED.
B. ORACLE_LOADERand ORACLE_DATAPUMPhave exactly the same functionality when used with an external table.
C. The CREATE TABLE AS SELECTstatement can be used to upload data into a normal table in the database from an external table.
D. The data and metadata for an external table are stored outside the database.

Answer: C

Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/cd/B28359_01/server.111/b28310/tables013.htm

NEW QUESTION # 52
View the Exhibit and examine the structure of the PRODUCTS table

Which two tasks would require subqueries? (Choose two.)

A. display suppliers whose PROD_LIST_PRICE is less than 1000
B. display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICE
C. display the minimum PROD_LIST_PRICE for each product status
D. display the total number of products supplied by supplier 102 and have a product status as
`OBSOLETE'
E. display all products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products, and whose status is orderable

Answer: B,E

NEW QUESTION # 53
Examine the description of the EMPLOYEES table:

Which statement will execute successfully, returning distinct employees with non-null first names?

A. SELECT DISTINCT * FROM employees WHERE first_name IS NOT NULL;
B. SELECT DISTINCT * FROM employees WHERE first_name <> NULL;
C. SELECT first_name, DISTINCT last_name FROM employees WHERE first_name IS NOT NULL;
D. SELECT first_name, DISTINCT last_name FROM employees WHERE first_name <> NULL;

Answer: D

NEW QUESTION # 54
View the Exhibit and examine the structure of the CUSTOMERS table.

Using the CUSTOMERS table, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?

A. SELECT NVL(cust_credit_limit*.15, 'Not Available') "NEW CREDIT" FROM customers;
B. SELECT NVL(TO_CHAR(cust_credit_limit*.15), 'Not Available') "NEW CREDIT" FROM customers;
C. SELECT NVL(cust_credit_limit, 'Not Available')*.15 "NEW CREDIT" FROM customers;
D. SELECT TO_CHAR(NVL(cust_credit_limit*.15, 'Not Available')) "NEW CREDIT" FROM customers;

Answer: A

NEW QUESTION # 55
......

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