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Oracle Database Administration I Sample Questions (Q147-Q152):

NEW QUESTION # 147
Examine the description of the PROMOTIONS table:

You want to display the unique promotion costs in each promotion category.
Which two queries can be used? (Choose two.)

A. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions ORDER BY 2;
C. SELECT DISTINCT promo_category || ' has ' || promo_cost AS COSTS FROM promotions ORDER BY 1;
D. SELECT promo_cost, promo_category FROM promotions ORDER BY 1;
E. SELECT DISTINCT promo_cost || ' in ' || DISTINCT promo_category FROM promotions ORDER BY 1;

Answer: A,B

NEW QUESTION # 148
Which two are true about a SQL statement using SET operators such as UNION? (Choose two.)

A. The data type of each column returned by the second query must be implicitly convertible to the data type of the corresponding column returned by the first query.
B. The data type group of each column returned by the second query must match the data type of the corresponding column returned by the first query.
C. The data type of each column returned by the second query must exactly match the data type of the corresponding column returned by the first query.
D. The number, but not names, of columns must be identical for all SELECT statements in the query.
E. The names and number of columns must be identical for all SELECT statements in the query.

Answer: A,C

NEW QUESTION # 149
Which two statements are true about Enterprise Manager (EM) Express?

A. You cannot start up a database instance using EM Express.
B. By default, EM express is available for a database after database creation using DBCA.
C. You can shut down a database instance using EM Express.
D. You can use a single instance of EM Express to manage multiple database running on the same server.
E. EM Express uses a separate repository database to store target database metadata.

Answer: B,C

NEW QUESTION # 150
Examine the description of the CUSTOMERS table:

For customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

A. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level IS NOT NULL AND due_amount IS NOT NULL;
B. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level != NULL AND due_amount != NULL;
C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level IS NOT NULL AND cust_credit_limit IS NOT NULL;
D. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level != NULL AND cust_credit_level !=NULL;
E. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level <> NULL AND due_amount <> NULL;

Answer: C

NEW QUESTION # 151
View the Exhibits and examine the structure of the COSTS and PROMOTIONS tables.
You want to display PROD_IDS whose promotion cost is less than the highest cost PROD_ID in a promotion time interval.
Examine this SQL statement:

Exhibit 1.

Exhibit 2.

What will be the result?

A. It executes successfully and gives the required result
B. It gives an error because the GROUP BY clause is not valid
C. It gives an error because the ALL keyword is not valid
D. It executes successfully but does not give the required result

Answer: A

NEW QUESTION # 152
......

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