BONUS!!! Download part of Pass4sureCert JS-Dev-101 dumps for free: https://drive.google.com/open?id=1vBkHekfMro3YR-qadyLXdwPQnB1w8C16
After you pass the test JS-Dev-101 certification, your working abilities will be recognized by the society and you will find a good job. If you master our JS-Dev-101 quiz torrent and pass the exam it proves that you have excellent working abilities and can be suitable for a good job. You will earn a high salary in a short time. Besides, you will get a quick promotion in a short period because you have excellent working abilities and can do the job well. You will be respected by your colleagues, your boss, your relatives, your friends and the society. All in all, buying our JS-Dev-101 Test Prep can not only help you pass the exam but also help realize your dream about your career and your future. So donโt be hesitated to buy our JS-Dev-101 exam materials and take action immediately.
| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Related Certifications: | Salesforce Platform Developer I Salesforce Platform Developer II |
| Real Exam Qty: | 60 (multiple choice) |
| Passing Score: | 65% |
| Exam Price: | $200 USD |
| Available Languages: | English |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Exam Duration: | 105 minutes |
| Exam Format: | Multiple Select Questions, Multiple Choice Questions |
| Recommended Training: | Salesforce Trailhead - JavaScript Developer I MDN Web Docs - JavaScript Guide |
| Exam Registration: | Salesforce Certification Registration Kryterion Webassessor (Exam Delivery) |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
>> Authorized JS-Dev-101 Certification <<
The Salesforce JS-Dev-101 desktop practice exam software is customizable and suits the learning needs of candidates. A free demo of the Salesforce Certified JavaScript Developer - Multiple Choice (JS-Dev-101) desktop software is available for sampling purposes. You can change Salesforce JS-Dev-101 Practice Exam's conditions such as duration and the number of questions. This simulator creates a Salesforce Certified JavaScript Developer - Multiple Choice (JS-Dev-101) real exam environment that helps you to get familiar with the original test.
| Topic | Details |
|---|---|
| Topic 1 |
|
| Topic 2 |
|
| Topic 3 |
|
NEW QUESTION # 79
Refer to the code below:
01 funetion Person() (
02 thie. fixsttane = "Zoha'y
os}
05 Perscn.prototype = [
06 jek: x => 'Developer'
onde
09 const myFather = new Peracn():
10 const result = myFather.firstiame + ' * + myFather.jeb()
What is the value of result after line 10 executes?
Answer: D
NEW QUESTION # 80
Which statement accurately describes the behavior of the async/await keywords?
Answer: B
Explanation:
When async is added to a function:
async function example() {}
JavaScript guarantees:
The function always returns a Promise, regardless of what is returned inside.
Inside the function, await pauses execution until a Promise resolves.
Code appears synchronous even though it uses asynchronous behavior.
Analysis of each option:
A incorrect:
Not "sometimes"-an async function always returns a Promise.
B incorrect:
Async functions can be called just like normal functions.
C incorrect:
Async/await has nothing to do with classes specifically.
D correct:
This is the standard description:
"Async functions behave asynchronously but allow writing code that looks synchronous." JavaScript Knowledge Reference (text-only) async functions always return Promises.
await pauses execution of the async function.
Async/await syntax creates synchronous-looking code on top of asynchronous operations.
NEW QUESTION # 81
Given the code below:
const delay = async delay =>{
return new Promise((resolve,reject)=>{
console.log(1);
setTimeout(resolve,deleay);
});
};
const callDelay =async ()=>{
console.log(2);
const yup = await delay(1000);
console.log(3);
}
console.log(4);
callDelay();
console.log(5);
What is logged to the console?
Answer:
Explanation:
4 2 1 5 3
NEW QUESTION # 82
Code:
01 const sayHello = (name) => {
02 console.log('Hello ', name);
03 };
04
05 const world = () => {
06 return 'World';
07 };
08
09 sayHello(world);
This does not print "Hello World".
What change is needed?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Currently:
sayHello expects a value name and prints it.
world is a function that returns 'World'.
sayHello(world); passes the function object itself, not the result of calling it.
So name inside sayHello is a function, not the string "World".
To keep the call sayHello(world) yet get "World", sayHello must call the function parameter:
const sayHello = (name) => {
console.log('Hello', name());
};
Now:
sayHello(world) passes the function.
Inside sayHello, name() calls world(), which returns "World".
The console logs "Hello World".
Why the others are wrong:
B: Changing line 7 to }(); would attempt to IIFE the function definition and break the declaration.
C: sayHello(world)() would try to call the return value of sayHello, which is undefined, causing an error.
D: Changing world to a function declaration does not change the fact that it is passed as a function reference; sayHello still prints the function object, not 'World'.
________________________________________
NEW QUESTION # 83
01 function Monster() { this.name = 'hello'; };
02 const m = Monster();
What happens due to the missing new keyword?
Answer: B
Explanation:
In JavaScript, when calling a constructor function without new:
const m = Monster();
the following happens:
The function executes as a normal function, not as a constructor.
Inside a regular function (in non-strict mode), this refers to the global object:
In a browser: window
So the line:
this.name = 'hello';
becomes:
window.name = 'hello';
Since Monster() does not return anything, its return value is undefined:
const m = undefined;
Therefore:
m is undefined
window.name becomes "hello"
This matches option B.
JavaScript Knowledge Reference (text-only)
Calling a function without new uses the global object as this in non-strict mode.
Constructor functions must use new to create a new object.
Functions without an explicit return return undefined.
NEW QUESTION # 84
......
Exam JS-Dev-101 Questions Pdf: https://www.pass4surecert.com/Salesforce/JS-Dev-101-practice-exam-dumps.html
BONUS!!! Download part of Pass4sureCert JS-Dev-101 dumps for free: https://drive.google.com/open?id=1vBkHekfMro3YR-qadyLXdwPQnB1w8C16