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WGU Introduction-to-Cryptography Exam Syllabus Topics:

SectionObjectives
Symmetric Cryptography- Key Management
- Stream Ciphers
- Block Ciphers (AES, DES, 3DES)
- Initialization Vectors (IV)
Cryptography Fundamentals- Cryptographic Terminology
- Symmetric vs Asymmetric Encryption
- History and Evolution of Cryptography
Applied Cryptography- SSL/TLS Protocols
- VPN Security
- Cryptographic Best Practices
- PGP and Email Encryption
Cryptanalysis and Attacks- Common Attack Vectors
- Brute Force and Dictionary Attacks
- Social Engineering Prevention
Asymmetric Cryptography- Elliptic Curve Cryptography (ECC)
- RSA Algorithm
- Public Key Infrastructure (PKI)
- Diffie-Hellman Key Exchange
Hashing and Digital Signatures- Message Authentication Codes (MAC)
- Hash Functions (MD5, SHA-1, SHA-256)
- Digital Signature Standards

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WGU Introduction to Cryptography HNO1 Sample Questions (Q37-Q42):

NEW QUESTION # 37
(Which attack maps hashed values to their original input data?)

Answer: C

Explanation:
A rainbow table attack uses large, precomputed tables that link hash outputs back to likely original inputs (typically passwords). Instead of storing every password#hash pair directly (which would be huge), rainbow tables store chains created by alternating hash operations with reduction functions, allowing attackers to reconstruct candidate plaintexts that produce a given hash. This makes cracking fast , if the target hashes are unsalted and use a known, fast hash function. Salt defeats rainbow tables because the attacker would need separate tables for each salt value, which becomes infeasible when salts are unique and sufficiently large. A dictionary at tack is related but typically computes hashes on the fly from a wordlist rather than using precomputed chain structures. A birthday attack targets collisions, not mapping to original data. Brute-force tries all candidates without precomputation. Because th e question explicitly describes mapping hashed values back to original data via a precomputed approach, the correct choice is Rainbow table.


NEW QUESTION # 38
(Why should a forensic investigator create a hash of a victim's hard drive and of the bitstream copy of the hard drive?)

Answer: C

Explanation:
In digital forensics, investigators must preserve evidence integrity and demonstrate an unbroken chain of custody. Creating a cryptographic hash (such as SHA-256) of the original drive and then hashing the forensic bitstream image provides a strong mathematical assurance that the copy is an exact, bit-for-bit replica.
Because secure hash functions are designed so that any tiny change in data produces a dramatically different digest, matching hashes indicate the image contains identical data to the source at the time of acquisition. This is critical in legal and investigative contexts: analysis is performed on the copy, not the original, to avoid altering evidence. If the hashes match, the investigator can testify that the evidence examined is identical to what was collected, supporting admissibility and credibility. Hashing does not prove who created files, nor does it directly show whether someone "opened the drive"; it specifically validates the integrity and equivalence of the captured image. Therefore, hashing both artifacts is done to verify that the original and the bitstream copy are identical.


NEW QUESTION # 39
(Which symmetric encryption technique uses a 112-bit key size and a 64-bit block size?)

Answer: B

Explanation:
3DES (Triple DES) is a symmetric block cipher that retains DES's 64-bit block size while increasing effective security by applying DES multiple times. The common "two-key 3DES" variant uses two independent 56-bit DES keys (K1 and K2) in an Encrypt-Decrypt-Encrypt (EDE) sequence: Encrypt with K1, Decrypt with K2, then Encrypt again with K1. Because each DES key is 56 bits (ignoring parity bits), the total keying material is 112 bits. This matches the question's "112-bit key size and 64-bit block size." Plain DES uses only a 56-bit effective key and a 64-bit block size, so it does not match the 112-bit key size. AES has a 128-bit block size and key sizes of 128/192/256. IDEA uses a 64-bit block size but has a 128-bit key.
Therefore, the correct algorithm is 3DES. Although 3DES improved on DES, it is now considered legacy due to its small 64-bit block size (birthday-bound issues for large data volumes) and performance overhead compared to AES.


NEW QUESTION # 40
(A security engineer is implementing device authentication as a form of two-factor authentication in a Public Key Infrastructure (PKI) environment. What should be used as a second form of authentication?)

Answer: D

Explanation:
In a PKI environment, a digital certificate is the standard credential used to bind an identity (user, device, service) to a public key, with that binding vouched for by a Certificate Authority. For device authentication, the device typically proves possession of the private key corresponding to the certificate' s public key (for example, during a TLS handshake). As a second factor in a two-factor model, a certificate (often stored in a TPM, smart card, or secure enclave) represents "something you have"-a cryptographic credential anchored to hardware or a managed endpoint. The other listed options (symmetric encryption, asymmetric encryption, digital signature) are cryptographic operations or algorithm classes, not stand-alone authentication factors. A digital signature is a mechanism used within authentication flows, but it is not itself the credential that establishes an enrolled device identity within PKI. In practice, a certificate-based device factor is commonly paired with a knowledge factor (password/PIN) or a biometric factor to achieve true 2FA, but among these choices, the appropriate second form of authentication in PKI terms is the digital certificate.


NEW QUESTION # 41
(A company wants to use certificates issued by a root CA to demonstrate to customers that it is a legitimate company being hosted by a cloud provider. Who needs to trust the root CA public key?)

Answer: C

Explanation:
In a public key infrastructure, trust in a certificate ultimately depends on the relying party's trust anchor set-typically the root CA certificates preinstalled in a customer's browser/OS trust store. For customers to accept the company's certificate as legitimate, the buyer (customer) must trust the root CA public key (or an intermediate chained to it) so they can validate the certificate chain and signatures. The seller (the company) also must trust and rely on the root CA public key to build and present a valid chain and to make operational decisions based on that CA's issuance and revocation mechanisms; practically, the seller selects a CA whose root is widely trusted by customers. The cloud provider's trust is not what makes the certificate valid to customers; the provider may terminate TLS or pass traffic through, but customer validation is based on the chain to a trusted root. Government agencies like the FTC are not part of the cryptographic trust path for TLS certificate validation.
Therefore, among the given options, the correct pairing is the seller and the buyer, reflecting both the issuer selection/usage by the company and the relying-party validation by customers.


NEW QUESTION # 42
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