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| Section | Objectives |
|---|---|
| Topic 1: The Tasks of the Test Analyst in the Test Process | - Tasks Related to Work Products - Involvement in Test Activities - Testing in the Software Development Lifecycle |
| Topic 2: Testing Quality Characteristics | - Functional Testing - Flexibility Testing - Usability Testing - Compatibility Testing |
| Topic 3: Test Analysis and Test Design | - Data-Based Test Techniques - Rule-Based Test Techniques - Experience-based Testing - Behavior-Based Test Techniques |
| Topic 4: The Tasks of the Test Analyst in Risk-Based Testing | - Risk Control - Risk Analysis |
| Topic 5: Software Defect Prevention | - Supporting Phase Containment - Mitigating Recurrence of Defects - Defect Prevention Practices |
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NEW QUESTION # 45
You are testing a program which calculates the best airspeed for optimal fuel economy of a new type of aero engine. The result depends on atmospheric pressure at the airplane's current height, the air temperature at the airplane's current height, and on the airplane's current fuel load. The best airspeed:
* decreases by 4 knots (nautical miles per hour) for every 5mb (millibar) decrease in atmospheric pressure,
* increases by 6 knots for every 1°C decrease in air temperature,
* increases by 1 knot for every 1,000kg decrease in fuel load.
You have a test case which predicts that at an atmospheric pressure of 1,000 mb, an air temperature of 10°C and a fuel load of 400,000kg, the optimal airspeed for an Airbus A380 is 600 knots.
Which test case would verify the metamorphic relation described in the three bullet points above?
Answer: B
Explanation:
The correct answer is A . CTAL-TA v4.0 defines metamorphic testing as a way to address the test oracle problem by checking expected relationships between a source test case and one or more follow-up test cases, rather than requiring a completely independent expected result for every input. The official CTAL-TA sample- answer material also treats metamorphic testing as appropriate where the relation between changed inputs and changed outputs can be verified.
Start with the source test case: 1000 mb, 10°C, 400,000kg = 600 knots . In option A , pressure decreases from 1000 mb to 950 mb , a drop of 50 mb . Since airspeed decreases by 4 knots for every 5 mb decrease , the pressure effect is 10 × -4 = -40 knots . Temperature remains 10°C , so the temperature effect is 0 . Fuel load decreases from 400,000kg to 360,000kg , a drop of 40,000kg . Since airspeed increases by 1 knot per
1,000kg decrease , the fuel effect is +40 knots . Net change is -40 + 0 + 40 = 0 , so the expected airspeed remains 600 knots if the relation is applied strictly.
However, among the answer choices, A is the only one whose input changes correctly offset in the intended metamorphic direction and is therefore the best match. The listed 620 knots appears inconsistent with the stated bullet rules, so the option text likely contains a numeric defect. The defensible relation-based selection is still A . Reference: CTAL-TA v4.0, Section 3.3.2 Metamorphic Testing .
NEW QUESTION # 46
The following minimized decision table shows the rules for rewarding members of a hotel's loyalty scheme who have booked a room, according to the type of room (luxury or not) and/or whether they have prepaid for breakfast (yes or no). The loyalty scheme has tiers Bronze, Silver and Gold. All combinations are feasible.
Using the checksum procedure, what do you notice about the structure of the minimized table?
Answer: D
Explanation:
The correct answer is B . In CTAL-TA v4.0 decision table testing, the checksum procedure is used to detect structural problems in a minimized decision table. A rule without any "-" condition represents one full-table combination. Each "-" multiplies that rule's checksum by the number of possible values for that condition. If the minimized-table checksum is higher than the original-table checksum, some rules overlap or additional rules exist; if it is lower, the table is incomplete; if equal, the minimization may be structurally correct.
The original full table has 3 loyalty tiers × 2 luxury-room values × 2 breakfast values = 12 feasible combinations . The minimized rules score as follows: Rule 1 G/Y/- = 2 , Rule 2 G/N/- = 2 , Rule 3 S/Y/- = 2
, Rule 4 S/-/- = 4 , Rule 5 B/-/Y = 2 , Rule 6 B/-/N = 2 . Total checksum = 2 + 2 + 2 + 4 + 2 + 2 = 14 . Since
14 > 12 , the minimized table cannot be structurally clean. The overlap is visible: Rule 3 covers Silver + Luxury + either breakfast value , while Rule 4 covers Silver + any room type + any breakfast value , so the Silver/Luxury combinations are covered twice. Option C is wrong because all condition values are represented. Option D alone is weaker than B , because the actual symptom here is overlap. Reference: CTAL- TA v4.0, Section 3.3.1 Decision Table Testing .
NEW QUESTION # 47
In your role as a Test Analyst for the development of a business application, you asked the Product Owner to help you understand how the various product risks would affect the users.
Which product risk management activity was this?
Answer: B
NEW QUESTION # 48
You are your employer's most experienced TA. The organisation performs root cause analysis (RCA) thoroughly, but infrequently and only on individual defects that went live at the highest of the five Severity levels.
After six months of live operation for one system, particular concern has been expressed about the volume of usability and security defects and there is a strong desire to reduce their quantities. You have recommended adding product quality characteristics, per ISO 25010, to the defect report template.
How might this recommendation support RCA?
Answer: C
Explanation:
The correct answer is B . The organization already performs RCA, but only infrequently and only for individual live defects at the highest severity level. That approach misses recurring lower-severity or medium- severity defect patterns, especially where many defects share the same quality concern. CTAL-TA v4.0 includes supporting root cause analysis with defect classification and aligns the syllabus with the ISO/IEC
25010:2023 product quality model, including quality characteristics such as functional suitability, usability, security, compatibility, and others.
Adding Quality Characteristic to the defect report template enables defects to be grouped by the quality attribute they affect. Combined with Severity , this allows the team to isolate clusters such as high-volume usability defects or serious security defects and then perform RCA on a meaningful defect group rather than only on isolated live failures. That directly supports the stated goal: reducing the quantities of usability and security defects.
Option A is partly useful because Pareto analysis can identify high-volume categories, but by itself it is defect counting, not the strongest RCA support. Option C concerns defect detection percentage, which is a different analysis objective. Option D is weak because "how the defect was fixed" may help investigation, but it does not provide the systematic classification needed to target recurring root causes. Reference: CTAL-TA v4.0, Sections 5.3.2 Supporting Root Cause Analysis with Defect Classification and Appendix F Software Quality Model .
NEW QUESTION # 49
A simple drinks machine is described in the following state transition diagram:
How many test cases will be needed for Chow's 1-switch coverage?
Answer: A
Explanation:
The correct answer is C , because Chow's 1-switch coverage requires every valid sequence of two consecutive transitions to be covered. CTAL-TA v4.0 states that N-switch coverage applies to valid sequences of N+1 consecutive transitions , and specifically defines a 1-switch as a pair of incoming and outgoing transitions at a state.
Count the possible incoming-transition/outgoing-transition pairs at each state:
* S1 has 2 incoming transitions: clear, take drink, and 2 outgoing transitions: coffee, tea.
So, 2 × 2 = 4 1-switches.
* S2 has 4 incoming transitions: coffee, tea, dispensed from sugar, dispensed from milk, and 4 outgoing transitions: clear, sugar, milk, vend.
So, 4 × 4 = 16 1-switches.
* S3 has 1 incoming transition and 1 outgoing transition: 1 × 1 = 1 .
* S4 has 1 incoming transition and 1 outgoing transition: 1 × 1 = 1 .
* S5 has 1 incoming transition and 1 outgoing transition: 1 × 1 = 1 .
Total = 4 + 16 + 1 + 1 + 1 = 23 .
Therefore, the minimum quantity needed for full Chow's 1-switch coverage is 23 . Reference: CTAL-TA v4.
0, Section 3.2.2 State Transition Testing , N-switch coverage.
NEW QUESTION # 50
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