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| Section | Objectives |
|---|---|
| Topic 1: Asynchronous JavaScript | - Promises and async/await - Event loop and concurrency model - Error handling in async workflows |
| Topic 2: Browser and DOM Interaction | - Browser APIs (fetch, storage, timers) - Event handling and propagation - DOM manipulation and traversal |
| Topic 3: Testing and Debugging | - Debugging techniques and tools - Unit testing principles |
| Topic 4: Salesforce Platform Integration | - Calling Apex methods from JavaScript - Lightning Web Components (LWC) JavaScript usage - Security considerations in Salesforce JavaScript |
| Topic 5: JavaScript Language Fundamentals | - Functions, scope, and closures - Data types, variables, and operators - ES6+ syntax and features |
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NEW QUESTION # 28 
Which code change should be done for the console to log the following when 'Click me!' is clicked'
> Row log
> Table log
Answer: B
NEW QUESTION # 29
Refer to the following code:
01 let obj = {
02 foo: 1,
03 bar: 2
04 }
05 let output = []
06
07 for (let something of obj) {
08 output.push(something);
09 }
10
11 console.log(output);
What is the value of output on line 11?
Answer: D
Explanation:
The key line is:
for (let something of obj) {
In JavaScript:
* for...of is used to iterate over iterable objects, such as:
* Arrays
* Strings
* Maps
* Sets
* Other objects that implement a [Symbol.iterator] method.
Plain JavaScript objects created with object literal {} are not iterable by default . They do not have [Symbol.
iterator], so using for...of directly on them causes a runtime error.
Specifically:
for (let something of obj) { ... }
will throw a TypeError similar to:
obj is not iterable
Therefore, the loop body never executes, and console.log(output); is never reached without an error.
Why other options are incorrect:
* B. [1, 2]
* To get [1, 2], you could use Object.values(obj) and iterate that array.
* But here, for...of obj never yields values because it throws an error.
* C. [ " foo " , " bar " ]
* To get property names, you could use Object.keys(obj) with for...of.
* Again, the code does not do that; it incorrectly tries to iterate the object directly.
* D. [ " foo:1 " , " bar:2 " ]
* You would need both keys and values, combining them manually.
* The given code does not implement such logic and fails before pushing anything into output.
Hence, the correct answer is:
The answer: A
Study Guide / Concept References (no links):
* Difference between for...of and for...in
* Iterables in JavaScript and [Symbol.iterator]
* Plain objects {} are not iterable by default
* Correct patterns to iterate object keys/values (Object.keys, Object.values, Object.entries)
NEW QUESTION # 30
is below:
<input type="file" onchange="previewFile()">
<img src="" height="200"alt="Image Preview..."/>
The JavaScript portion is:
01 functionpreviewFile(){
02 const preview = document.querySelector('img');
03 const file = document.querySelector('input[type=file]').files[0];
04 //line 4 code
05 reader.addEventListener("load", () => {
06 preview.src = reader.result;
07 },false);
08 //line 8 code
09 }
In lines 04 and 08, which code allows the user to select an image from their local computer , and to display the image in the browser?
Answer: D
NEW QUESTION # 31
Which statement accurately describes an aspect of promises?
Answer: C
Explanation:
Evaluate each option:
A). Arguments for .then() are optional.
This is correct.
then() has the signature:
promise.then(onFulfilled?, onRejected?)
Both arguments (onFulfilled and onRejected) are optional.
If a callback is not supplied, JavaScript provides a default pass-through handler.
B). .then() cannot be added after a catch.
Incorrect.
Promises support chaining in any order:
promise
catch(...)
then(...);
After a catch, the chain continues normally.
C). .then() manipulates and returns the original promise.
Incorrect.
then() always returns a new promise , not the original one.
This is fundamental to promise chaining behavior.
D). Returning values in .then() is not necessary.
Incorrect.
If you want the next .then() in the chain to receive a value, the current .then() must explicitly return it:
then(value = > {
return value * 2; // passes to next .then()
})
If nothing is returned, the next .then() receives undefined.
Why A is correct
It is the only statement that accurately describes built-in Promise behavior:
then() accepts optional arguments.
JavaScript Knowledge References (text-only)
* .then(onFulfilled?, onRejected?) accepts optional handlers.
* Promise chaining creates new promises for each .then().
* catch() can be followed by additional .then() calls.
* Returning inside .then() passes values to the next step in the chain.
NEW QUESTION # 32
Given the JavaScript below:
Which code should replace the placeholder comment on line 05 to highlight accounts that match the search string'
Answer: B
NEW QUESTION # 33
......
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