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| Section | Objectives |
|---|---|
| Topic 1: Review Event Logs and Mitigate Attacks | - Threat Mitigation
|
| Topic 2: Policy Maintenance and Optimization | - Performance Optimization
|
| Topic 3: Architecture, Design and Policy Creation | - Application Security Concepts
|
| Topic 4: Troubleshooting | - Problem Diagnosis
|
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NEW QUESTION # 498
Refer to the Exhibit.
An LTM Specialist notices that two members in a pool are overloaded. To relive the existing members a fourth member (10.128.20.14) is brought up.
How many member will receive and process new connections?
Answer: C
NEW QUESTION # 499
There are three servers in the pool: 172.16.20.1, 172.16.20.2, and 172.16.20.3, with the virtual IP address 10.0.20.88.
A user CANNOT connect to an HTTP application. To understand the problem and find a solution, the LTM Specialist runs two concurrent traces on the LTM device, with the following results:
Trace on client side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol
decode
listening on 0.0, link-type EN10MB (Ethernet), capture size 96 bytes
22:22:07.423759 IP 172.16.20.100.53875 > 10.0.20.88.80: S
998346084:998346084(0) win 5840 <mss 1460,sackOK,timestamp 67942058
0,nop,wscale 4>
22:22:07.424056 IP 10.0.20.88.80 > 172.16.20.100.53875: S
4671780:4671780(0) ack 998346085 win 4380 <mss 1460,nop,wscale
0,nop,nop,timestamp 2392362490 67942058,sackOK,eol>
22:22:07.424776 IP 172.16.20.100.53875 > 10.0.20.88.80: . ack 1 win 365
<nop,nop,timestamp 67942058 2392362490>
22:22:07.424790 IP 172.16.20.100.53875 > 10.0.20.88.80: P 1:149(148)
ack 1 win 365 <nop,nop,timestamp 67942058 2392362490>
22:22:07.424891 IP 10.0.20.88.80 > 172.16.20.100.53875: . ack 149 win
4528 <nop,nop,timestamp 2392362491 67942058>
22:22:12.024850 IP 10.0.20.88.80 > 172.16.20.100.53875: R 1:1(0) ack
149 win 4528
6 packets captured
6 packets received by filter
0 packets dropped by kernel
Trace on server side:
tcpdump: verbose output suppressed, use -v or -vv for full protocol
decode
listening on internal, link-type EN10MB (Ethernet), capture size 96
bytes
22:22:07.424881 IP 172.16.20.100.53875 > 172.16.20.2.80: S
51116678:51116678(0) win 4380 <mss 1460,nop,wscale 0,nop,nop,timestamp
2392362491 0,sackOK,eol>
22:22:08.424893 IP 172.16.20.100.53875 > 172.16.20.2.80: S
51116678:51116678(0) win 4380 <mss 1460,nop,wscale 0,nop,nop,timestamp
2392363491 0,sackOK,eol>
22:22:09.625082 IP 172.16.20.100.53875 > 172.16.20.2.80: S
51116678:51116678(0) win 4380 <mss 1460,nop,wscale 0,nop,nop,timestamp
2392364691 0,sackOK,eol>
22:22:10.825194 IP 172.16.20.100.53875 > 172.16.20.2.80: S
51116678:51116678(0) win 4380 <mss 1460,sackOK,eol>
4 packets captured
4 packets received by filter
0 packets dropped by kernel
What should the LTM Specialist do to solve the problem?
Answer: D
NEW QUESTION # 500
An organization's development team creates an application to put behind the F5LTM device. The application can be quite load intensive at first, and then evens out over time. The team's load balancing method needs to select a pool after taking into account the pool member's response over the time to avoid landing on a busy pool member.
Which of the following load balancing methods meets this requirement?
Answer: B
NEW QUESTION # 501
Which two alerting capabilities can be enabled from within an application visibility reporting (AVR) analytics profile? (Choose two.)
Answer: A,D
NEW QUESTION # 502
An LTM Specialist configures two LTM devices in a high-availability pair with trusts established and device groups configured properly using network failover. After several months, the LTM Specialist notices that changes made to one LTM device do NOT cause the synchronization status to update to "changes pending," and this device does NOT synchronize with the device group.
Which two steps should the LTM Specialist take to identify the issue? (Choose two.)
Answer: B,C
NEW QUESTION # 503
......
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