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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Exam Format: | Multiple Choice Questions, Multiple Select Questions |
| Passing Score: | 65% |
| Exam Price: | $200 USD |
| Real Exam Qty: | 60 (multiple choice) |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Related Certifications: | Salesforce Platform Developer II Salesforce Platform Developer I |
| Available Languages: | English |
| Exam Duration: | 105 minutes |
| Recommended Training: | MDN Web Docs - JavaScript Guide Salesforce Trailhead - JavaScript Developer I |
| Exam Registration: | Kryterion Webassessor (Exam Delivery) Salesforce Certification Registration |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
>> Latest JS-Dev-101 Questions <<
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NEW QUESTION # 30
Refer to the code:
const pi = 3.1415926;
What is the data type of pi?
Answer: A
Explanation:
JavaScript has one numeric data type for all real numbers, whether integers or decimals.
This type is simply called:
Number
It follows the IEEE 754 double-precision floating-point standard internally, but JavaScript does not expose separate types like float, double, or decimal.
Therefore:
It is not Float → JavaScript does not have float primitives.
It is not Double → this refers to the underlying IEEE 754 representation, but JavaScript's type is still just "Number." It is not Decimal → JavaScript has no built-in decimal type.
The correct answer is Number.
JavaScript Knowledge Reference (text-only)
JavaScript has a single numeric type: Number.
All numbers-integers, fractions, floating point-use the Number type.
NEW QUESTION # 31
A developer creates a class that represents a news story based on the requirements that a Story should have a body, author, and view count. The code is shown below:
01 class Story {
02 // Insert code here
03 this.body = body;
04 this.author = author;
05 this.viewCount = viewCount;
06 }
07 }
Which statement should be inserted in the placeholder on line 02 to allow for a variable to be set to a new instance of a Story with the three attributes correctly populated?
Answer: A
Explanation:
In ES6 class syntax, the special method used to initialize a new instance is called constructor.
A class definition syntax:
class ClassName {
constructor(param1, param2) {
this.prop1 = param1;
this.prop2 = param2;
}
}
The constructor method:
Is called automatically when you create a new instance with new ClassName(...).
Receives the arguments passed in the new expression.
Assigns values to this to set instance properties.
Applying this to Story
We want to be able to write:
const article = new Story('Some body', 'Author Name', 100);
and have:
article.body === 'Some body'
article.author === 'Author Name'
article.viewCount === 100
To achieve this, the class must have:
class Story {
constructor(body, author, viewCount) {
this.body = body;
this.author = author;
this.viewCount = viewCount;
}
}
So the correct line 02 is:
constructor(body, author, viewCount) {
Why the other options are incorrect
A . constructor() {
This defines a constructor with no parameters.
The lines inside the constructor use body, author, and viewCount, which would be undefined unless they exist in an outer scope (they normally do not).
This would lead to the instance properties being set to undefined in normal usage.
B . super(body, author, viewCount) {
super(...) is used inside a constructor of a subclass to call the parent class constructor.
You cannot use super(...) { as a method definition; this is invalid syntax in a class body.
Additionally, Story as given is not shown extending any class, so super is inappropriate here.
C . function Story(body, author, viewCount) {
Inside a class definition, you do not use the function keyword to define methods.
function Story(...) here would be invalid syntax in a class body.
Even if it were allowed, the special constructor method for a class is named constructor, not the class name.
Therefore, only:
constructor(body, author, viewCount) {
correctly declares the constructor for the Story class and ensures instances created with new Story(body, author, viewCount) have all three properties populated.
Reference / Study Guide concepts (no links):
ES6 class syntax
constructor method in classes
this and instance properties in classes
Difference between class constructors and regular functions
Invalid use of super and function inside class bodies
NEW QUESTION # 32
Refer tofollowing code:
class Vehicle {
constructor(plate) {
This.plate =plate;
}
}
Class Truck extends Vehicle {
constructor(plate, weight) {
//Missing code
This.weight = weight;
}
displayWeight() {
console.log('The truck ${this.plate} has a weight of${this.weight} lb.');}} Let myTruck = new Truck('123AB', 5000); myTruck.displayWeight(); Which statement should be added to line 09 for the code to display 'The truck 123AB has a weight of 5000lb.'?
Answer: A
NEW QUESTION # 33
Refer to the code below:
let productSKU = '8675309';
A developer has a requirement to generate SKU numbers that are always 19 characters long, starting with 'sku', and padded with zeros.
Which statement assigns the value sku000000008675309?
Answer: D
Explanation:
We start with:
let productSKU = '8675309';
The requirement:
Final SKU string:
Length: 19 characters.
Starts with 'sku'.
Remaining characters are digits padded with zeros on the left (to reach total length).
We can use String.prototype.padStart and String.prototype.padEnd:
str.padStart(targetLength, padString)
If str.length < targetLength, it adds padString to the start until the length is targetLength.
str.padEnd(targetLength, padString)
Similar, but adds padString to the end.
We want a pattern like:
First, pad the numeric part out to a fixed length with zeros.
Then, pad to total length with 'sku' at the start.
Analyze Option B
productSKU = productSKU.padStart(16, '0').padStart(19, 'sku');
Step 1: productSKU.padStart(16, '0')
Initial productSKU is '8675309' (length 7).
After padStart(16, '0'), we pad zeros on the left to reach length 16.
We need 16 − 7 = 9 zeros:
Result after step 1:
productSKU === '0000000008675309' // length 16
Step 2: .padStart(19, 'sku')
Now productSKU has length 16.
We call padStart(19, 'sku'):
We need 19 − 16 = 3 extra characters.
The pad string 'sku' is exactly 3 characters, so it is added as-is at the start.
Result after step 2:
productSKU === 'sku0000000008675309' // length 19
This satisfies:
Length 19.
Starts with 'sku'.
Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.
While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:
3 characters of 'sku'
Numeric part padded with zeros to make 16 characters total for the numeric part
3 + 16 = 19 total characters
Option B matches the intended logic using padStart and padEnd.
Why the other options are incorrect
Option A:
productSKU = productSKU.padEnd(16, '0').padStart('sku');
padEnd(16, '0') produces '8675309000000000' (original number followed by zeros).
padStart('sku') is invalid usage:
padStart takes a numeric target length as the first argument, not a string.
Passing 'sku' as the first argument leads to type coercion that does not achieve the intended behavior.
This will not reliably produce the desired SKU.
Option C:
productSKU = productSKU.padEnd(16, '0').padStart(19, 'sku');
First padEnd(16, '0') from '8675309' gives '8675309000000000' (length 16, zeros at the end).
Then padStart(19, 'sku') adds 3 chars 'sku' at the front:
Result: 'sku8675309000000000'.
This string starts with 'sku', but the zeros are at the end of the digits, not padding the numeric part on the left as desired.
Option D:
productSKU = productSKU.padStart(19, '0').padStart('sku');
First padStart(19, '0') pads zeros at the left to make the length 19.
Then padStart('sku') again incorrectly uses a string where a numeric targetLength is required.
This will not produce the correct SKU format.
Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with 'sku' is:
Answe r: B
Reference / Study Guide concepts (no links):
String.prototype.padStart(targetLength, padString)
String.prototype.padEnd(targetLength, padString)
String length calculations
Left-padding numeric strings with zeros
Building prefixed identifiers with fixed total length
NEW QUESTION # 34
A developer initiates a server with the file server.js and adds dependencies in the source code's package.json that are required to run the server.
Which command should the developer run to start the server locally?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From JavaScript/Node.js Knowledge:
In a Node.js project that uses package.json, you typically define a "start" script:
{
"scripts": {
"start": "node server.js"
}
}
Then you start the app with:
npm start
npm start:
Looks up the "start" script in package.json.
Runs the command defined there (commonly node server.js).
This is the standard way to start a Node.js app with npm-managed dependencies.
Why others are incorrect:
A . node start
Tries to run a file named start with Node; does not use package.json scripts.
C . npm start server.js
npm start does not take the script filename as an argument in this way; it just runs the start script as defined.
D . start server.js
Not an npm or node command; on some shells it just tries to "start" a process but is not the standard Node/npm workflow.
Relevant concepts: package.json, npm scripts, npm start, Node entry file execution.
________________________________________
NEW QUESTION # 35
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