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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Functions and Graphs	- Function Concepts 1. Domain and range 2. Function notation - Graphing Functions 1. Coordinate plane interpretation 2. Transformations of graphs
Exponential and Logarithmic Concepts	- Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties - Exponential Functions 1. Growth and decay models 2. Exponential equations
Linear Functions and Systems	- Linear Equations 1. Slope-intercept form 2. Point-slope form - Systems of Equations 1. Elimination method 2. Substitution method
Polynomial and Rational Expressions	- Polynomials 1. Factoring techniques 2. Operations with polynomials - Rational Expressions 1. Restrictions on variables 2. Simplification
Foundations of Algebra	- Algebraic Expressions 1. Order of operations 2. Simplifying expressions 3. Evaluating expressions - Equations and Inequalities 1. Inequalities and interval notation 2. Linear equations in one variable

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Applied-Algebra Study Materials & Applied-Algebra Certification Training & Applied-Algebra Best Questions

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q18-Q23):

NEW QUESTION # 18
A researcher collected data on the average number of product returns per month to a company over time. The results are shown in the scatterplot. The graphed regression function has an r
2
value of 0.45.

Which range of x-values is appropriate for extrapolation?

A. Extrapolation is not appropriate because r
2
< 0.7.
B. x=3 to x=21
C. Extrapolation is not appropriate because r
2
< 1.
D. x=0 to x=24

Answer: A

Explanation:
The coefficient of determination, r
2
, measures how well a regression model fits the data. A value close to 1 indicates a strong fit, while a lower value indicates that the model does not explain the data as reliably. Here, r
2
=0.45, which is below 0.7. That means the model does not have a strong enough fit for reliable extrapolation in this question. Extrapolation means using the model to predict values outside the observed data range, which is riskier than interpolation. Because the model fit is not strong, choosing an extended range of x-values would not be appropriate. The correct reason is that extrapolation is not appropriate because r
2
< 0.7. Therefore, the answer is D.

NEW QUESTION # 19
The function d(x)=14+65xrepresents the distance, in meters, from a tower to an object at time x, in seconds.
What is the value of d(1.5)?

A. 0
B. 0.19
C. 1
D. 111.5

Answer: D

Explanation:
We are given the function:
d(x)=14+65x
This is a linear function because it has the form:
d(x)=mx+b
where 65is the rate of change and 14is the starting value.
We need to find:
d(1.5)
That means substitute x=1.5into the function:
d(1.5)=14+65(1.5)
Now multiply:
65(1.5)=97.5
Then add:
d(1.5)=14+97.5
d(1.5)=111.5
So the distance from the tower to the object at 1.5seconds is:
111.5 " meters "

NEW QUESTION # 20
The exponential function
f(t)=2900(1.13)
t
represents the size of a bacteria population, where t is the time in hours.
How many bacteria are in the population when t=18?

A. 23,160
B. 29,573
C. 26,170
D. 20,495

Answer: C

Explanation:
This is an exponential growth problem because the base 1.13 is greater than 1. The function starts with 2,900 bacteria and grows by a factor of 1.13 each hour, which represents a 13% hourly increase. To find the population after 18 hours, substitute t=18 into the function: f(18)=2900(1.13)
18
Evaluating the exponent and multiplying by 2900 gives approximately 26,170.38. Since bacteria are counted as whole organisms, this rounds to about 26,170 bacteria. The other answer choices do not match the exponential model at t=18. Therefore, the correct answer is C.

NEW QUESTION # 21
The graph shows the value, O, in dollars, of an investment account over time.

What represents the value of the account after 8 years?

A. $700.19
B. $1,028.81
C. $2,221.12
D. $476.54

Answer: C

Explanation:
The graph shows the total value of an investment account as time increases.
The horizontal axis represents:
" Time in years "
The vertical axis represents:
" Total value in dollars "
We need to find the value of the account after:
8 " years "
From the graph, when t=8, the curve is slightly above $2,200. The closest answer choice is:
$2,221.12
So the value of the account after 8 years is approximately:
$2,221.12
Therefore, the correct answer is:
# ( " D " )

NEW QUESTION # 22
The population of fish in a lake is changing according to the function
P(t)=24t+185
where tis the number of months since the beginning of the year and P(t)is the fish population at time t.
Which interpretation of the rate of change is correct?

A. The number of fish in the lake is increasing at a constant rate of 24 fish per month.
B. The number of fish in the lake is decreasing at a constant rate of 24 fish per month.
C. The number of fish in the lake is decreasing at a constant rate of 185 fish per month.
D. The number of fish in the lake is increasing at a constant rate of 185 fish per month.

Answer: A

Explanation:
The function is:
P(t)=24t+185
This is a linear function in the form:
P(t)=mt+b
where:
m= " rate of change "
and
b= " initial value "
In the function:
P(t)=24t+185
the coefficient of tis:
24
So the rate of change is:
24 " fish per month "
Because 24is positive, the fish population is increasing.
The number 185is not the rate of change. It represents the starting fish population at the beginning of the year, when t=0:
P(0)=24(0)+185=185
Therefore, the correct interpretation is:
" The number of fish in the lake is increasing at a constant rate of 24 fish per month. " So the correct answer is:
# ( " B " )

NEW QUESTION # 23
......

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