1z1-071熱門證照 & 1z1-071最新考古題

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Oracle 1z1-071 Exam Syllabus Topics:
| Section | Objectives |
|---|
| Subqueries and Advanced SQL | - Single-row and multi-row subqueries - Correlated subqueries and nested queries
|
| SQL Retrieval | - Joins and set operations
- 1. INNER, OUTER, CROSS joins
- 2. UNION, INTERSECT, MINUS
- SELECT statements and filtering data
- 1. ORDER BY and row limiting
- 2. WHERE clause and conditions
|
| Data Manipulation and Schema Objects | - DML operations
- 1. INSERT, UPDATE, DELETE, MERGE
- DDL operations
- 1. CREATE, ALTER, DROP tables and constraints
|
| SQL Functions | - Conversion and conditional functions
- 1. TO_CHAR, TO_NUMBER, CASE expressions
- Single-row functions
- 1. Character, numeric, date functions
|
| Relational Database Concepts | - Data types and database objects overview - Tables, rows, columns, and relational model basics
|
>> 1z1-071熱門證照 <<
1z1-071最新考古題 & 最新1z1-071考證
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最新的 Oracle PL/SQL Developer Certified Associate 1z1-071 免費考試真題 (Q37-Q42):
問題 #37
Examine the description of the CUSTOMERS table:

You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?
- A. SELECT * FROM customers WHERE city LIKE'D_';
- B. SELECT * FROM customers WHERE city LIKE'D %';
- C. SELECT * FROM customers WHERE city ='D_%';
- D. SELECT * FROM customers WHERE city ='%D_';
答案:B
問題 #38
Examine the description of the transactions table:

Which two SQL statements execute successfully?
- A. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount+100 "DUES" from transactions;
- B. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount+100 DUES FROM transactions;
- C. SELECT customer_id AS 'CUSTOMER-ID',transaction_date AS DATE, amount+100 'DUES' from transactions;
- D. SELECT customer id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount+100 "DUES AMOUNT" FROM transactions;
- E. SELECT customer_id CUSTID, transaction_date TRANS_DATEamount+100 DUES FROM transactions;
答案:A,E
解題說明:
A). True, this statement will execute successfully. In Oracle SQL, column aliases can be given in double quotes which allows the use of special characters like a hyphen. Additionally, you can perform arithmetic operations such as amount+100 directly in the SELECT clause to return increased values of amount.
C). True, this statement is also valid. It does not use any special characters or reserved keywords as aliases that would require double quotes. The arithmetic operation is the same as in option A, which is permissible.
For B, D, and E, the reasons for failure are: B. In Oracle SQL, single quotes are used for string literals, not for column aliases. Therefore, using single quotes around 'CUSTOMER-ID' and 'DUES' will result in an error. D.
The word "DATE" is a reserved keyword in Oracle SQL. When used as a column alias without double quotes, it will lead to an error. In this statement, although "DATE" is in double quotes, it's a best practice to avoid using reserved keywords as aliases.
E). There are syntax errors in the statement. "customer id" should be "customer_id", and the alias "CUSTOMER-ID" should be enclosed in double quotes if special characters are used. Also, "DUES AMOUNT" as an alias should be in double quotes to be valid because it contains a space.
References:
* Oracle documentation on column aliases: Oracle Database SQL Language Reference
* Oracle reserved words: Oracle Database SQL Language Reserved Words
問題 #39
Examine the SQL statement used to create the TRANSACTION table. (Choose the best answer.) SQL > CREATE TABLE transaction (trn_id char(2) primary key, Start_date date DEFAULT SYSDATE, End_date date NOT NULL); The value 'A1' does not exist for trn_id in this table.
Which SQL statement successfully inserts a row into the table with the default value for START_DATE?
- A. INSERT INTO transaction VALUES ('A1', DEFAULT, TO_DATE('SYSDATE+10'))
- B. INSERT INTO transaction VALUES ('A1', DEFAULT, TO_DATE(DEFAULT+10))
- C. INSERT INTO transaction (trn_id, start_date, end_date) VALUES ('A1', , '10-DEC-2014')
- D. INSERT INTO transaction (trn_id, end_date) VALUES ('A1', '10-DEC-2014')
答案:D
問題 #40
View the Exhibit and examine the description for the PRODUCTS and SALES table.

PROD_ID is a primary key in the PRODUCTS table and foreign key in the SALES table.
You want to remove all the rows from the PRODUCTS table for which no sale was done for the last three years.
Which is the valid DELETE statement?
- A. DELETE FROM products
WHERE prod_id = (SELECT prod_id FROM sales
WHERE SYSDATE >= time_id - 3*365 ); - B. DELETE FROM products
WHERE prod_id IN (SELECT prod_id FROM sales
WHERE time_id >= SYSDATE - 3*365 ); - C. DELETE FROM products
WHERE prod_id = (SELECT prod_id FROM sales
WHERE time_id - 3*365 = SYSDATE ); - D. DELETE FROM products
WHERE prod_id IN (SELECT prod_id FROM sales
WHERE SYSDATE - 3*365 >= time_id);
答案:D
問題 #41
View the exhibit and examine the structure of ORDERSand CUSTOMERStables.

Which INSERT statement should be used to add a row into the ORDERStable for the customer whose CUST_LAST_NAMEis Robertsand CREDIT_LIMITis 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.
INSERT INTO (SELECT o.order_id, o.order_date, o.order_mode, c.customer_id,
- A. (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), order_total)
VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
INSERT INTO orders - B. VALUES (1,'10-mar-2007', 'direct',
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
INSERT INTO orders (order_id, order_date, order_mode, - C. o.order_total
FROM orders o, customers c
WHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND
c.credit_limit=600)
VALUES (1,'10-mar-2007', 'direct', (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
INSERT INTO orders (order_id, order_date, order_mode, - D. (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), order_total)
VALUES (1,'10-mar-2007', 'direct', &&customer_id, 1000);
答案:B
解題說明:
Explanation/Reference:
問題 #42
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