Salesforce JS-Dev-101 Lerntipps & JS-Dev-101 Praxisprüfung

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Salesforce JS-Dev-101 Prüfungsplan:

ThemaEinzelheiten
Thema 1
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
Thema 2
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Thema 3
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Thema 4
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Thema 5
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.

>> Salesforce JS-Dev-101 Lerntipps <<

JS-Dev-101 Übungsfragen: Salesforce Certified JavaScript Developer - Multiple Choice & JS-Dev-101 Dateien Prüfungsunterlagen

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Salesforce Certified JavaScript Developer - Multiple Choice JS-Dev-101 Prüfungsfragen mit Lösungen (Q29-Q34):

29. Frage
A developer is leading the creation of a new web server for their team that will fulfill API requests from an existing client.
The team wants a web server that runs on Node.Js, and they want to use the new web framework Minimalist.Js. The lead developer wants to advocate for a more seasoned back-end framework that already has a community around it.
Which two frameworks could the lead developer advocate for?
Choose 2 answers

Antwort: A,B


30. Frage
Refer to the code below
let inArray = [[1,2],[3,4,5]];
which two statements results in the array [1,2,3,4,5]?
choose 2 answer

Antwort: B,C


31. Frage
A developer removes the HTML class attribute from the checkout button, so now it is simply:
<button>Checkout</button>
There is a test to verify the existence of the checkout button, however it looks for a button with class="blue". The test fails because no such button is found.
Which type of test category describes this test?

Antwort: D

Begründung:
Definitions in testing context (treating "positive" as "test reports a bug/failure"):
True positive: System has a bug; test correctly fails.
False positive: System is correct; test fails (reports a bug that isn't actually a bug).
True negative: System has a bug; test correctly passes indicating "no success" in detection context (less common phrasing here).
False negative: System has a bug; test incorrectly passes (missed bug).
Here:
The real requirement, as stated, is to verify the existence of the checkout button.
The button still exists (<button>Checkout</button>), so the system behavior is correct regarding that requirement.
The test, however, is checking for an overly specific condition (class="blue"), which is not actually part of the stated requirement.
The test fails, saying there is a problem (no button with class="blue"), even though from the requirement standpoint, the checkout button is present.
So:
No real bug concerning presence of checkout button.
Test reports a failure → a false positive.
Therefore, the correct category is D, False positive.


32. Frage
static delay = async delay => {
return new Promise(resolve => {
setTimeout(resolve, delay);
});
};
static asyncCall = async () => {
await delay(1000);
console.log(1);
};
console.log(2);
asyncCall();
console.log(3);
Assume delay and asyncCall are in scope as functions.
What is logged to the console?

Antwort: D

Begründung:
The correct answer is D, because JavaScript executes synchronous code first, while the code after await runs later after the Promise resolves.
The execution order is:
console.log(2);
This runs first, so JavaScript logs:
2
Then this line runs:
asyncCall();
The asyncCall() function starts executing. Inside it, JavaScript reaches:
await delay(1000);
The delay(1000) function returns a Promise that resolves after 1000 milliseconds:
return new Promise(resolve => {
setTimeout(resolve, delay);
});
Because await pauses the rest of the asyncCall() function, this line does not run immediately:
console.log(1);
Instead, JavaScript continues executing the remaining synchronous code outside the async function:
console.log(3);
So JavaScript logs:
3
After approximately 1000 milliseconds, the Promise returned by delay(1000) resolves. Then the paused async function continues and runs:
console.log(1);
So JavaScript logs:
1
Final console output:
2
3
1
Important JavaScript concepts involved:
An async function always returns a Promise.
The await keyword pauses execution only inside the async function where it appears.
Code outside the async function continues running normally.
setTimeout() schedules its callback to run later, after the current synchronous code has finished.
Therefore, the verified answer is D. 2 3 1.


33. Frage
01 let a = "*";
02 let b = "**";
/ 7 x = 3;
04 console.log(a);
What is displayed when the code executes?

Antwort: B


34. Frage
......

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