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Salesforce JS-Dev-101 Exam Overview:

Certification Vendor:Salesforce
Exam Name:Salesforce Certified JavaScript Developer - Multiple Choice
Exam Number:JS-Dev-101
Real Exam Qty:60 scored + up to 5 unscored
Related Certifications:Salesforce Certified Developer
Salesforce Certified Platform Developer I
Exam Format:Multiple choice, Multiple select
Passing Score:65%
Exam Price:USD 200
Certificate Validity Period:Does not expire; requires maintenance updates
Available Languages:Japanese, English
Exam Duration:105 minutes
Recommended Training:Trailhead JavaScript Developer I Certification Prep
Exam Registration:Salesforce Certification Registration
Sample Questions:Salesforce JS-Dev-101 Sample Questions
Exam Way:Online proctored or onsite at authorized testing centers
Pre Condition:No formal prerequisites; recommended: strong JavaScript fundamentals, ES6+ experience, web development familiarity
Official Syllabus URL:https://trailheadacademy.salesforce.com/certificate/exam-javascript-dev---JS-Dev-101

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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 2
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 3
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 4
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 5
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.

Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q48-Q53):

NEW QUESTION # 48
Console logging methods that allow string substitution:

Answer: A,B,D


NEW QUESTION # 49
Universal Containers (UC) notices that its application that allows users to search for accounts makes a network request each time a key is pressed. This results in too many requests for the server to handle.
* Address this problem, UC decides to implement a debounce function on string change handler.
What are three key steps to implement this debounce function?
Choose 3 answers:

Answer: A,B,D


NEW QUESTION # 50
Given the code below:
01 setCurrentUrl();
02 console.log("The current URL is: " + url);
03
04 function setCurrentUrl() {
05 url = window.location.href;
06 }
What happens when the code executes?

Answer: D

Explanation:
Inside setCurrentUrl, url is assigned without var, let, or const:
url = window.location.href;
In non-strict mode, this implicitly creates a global variable url on window.
Execution order:
setCurrentUrl(); creates/sets global url to window.location.href.
console.log("The current URL is: " + url); has access to url in global scope and prints correctly.
Thus:
url has global scope.
Line 02 runs without error and logs a valid string.
So B is correct.
________________________________________


NEW QUESTION # 51
A developer creates a genericfunction to log custom messages in the console. To do this, the function below is implemented.
01 function logStatus(status){
02 console./*Answer goes here*/{'Item status is: %s', status};
03 }
Which three console logging methods allow the use of string substitution in line 02?

Answer: A,C,D


NEW QUESTION # 52
Refer to the following code block:
01 let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
02 let output = 0;
03
04 for (let num of array) {
05 if (output > 10) {
06 break;
07 }
08 if (num % 2 == 0) {
09 continue;
10 }
11 output += num;
12 }
What is the value of output after the code executes?

Answer: A

Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
This code uses:
A for...of loop to iterate over values in array.
break to exit the loop entirely when output > 10.
continue to skip even numbers.
It sums only certain numbers into output.
Let's walk through the loop step by step.
Initial values:
array = [1,2,3,4,5,6,7,8,9,10,11]
output = 0
Loop: for (let num of array) { ... }
First iteration: num = 1
Line 05: if (output > 10) → 0 > 10 is false → no break.
Line 08: if (num % 2 == 0) → 1 % 2 == 1, not 0, so false → no continue.
Line 11: output += num → output = 0 + 1 = 1.
Second iteration: num = 2
output > 10 → 1 > 10 is false → no break.
num % 2 == 0 → 2 % 2 == 0, so true → continue.
Because of continue, line 11 is skipped.
output remains 1.
Third iteration: num = 3
output > 10 → 1 > 10 is false.
num % 2 == 0 → 3 % 2 == 1, false → no continue.
output += num → output = 1 + 3 = 4.
Fourth iteration: num = 4
output > 10 → 4 > 10 is false.
num % 2 == 0 → 4 % 2 == 0, true → continue.
Skip sum; output remains 4.
Fifth iteration: num = 5
output > 10 → 4 > 10 is false.
num % 2 == 0 → 5 % 2 == 1, false.
output += num → output = 4 + 5 = 9.
Sixth iteration: num = 6
output > 10 → 9 > 10 is false.
num % 2 == 0 → 6 % 2 == 0, true → continue.
output remains 9.
Seventh iteration: num = 7
output > 10 → 9 > 10 is false.
num % 2 == 0 → 7 % 2 == 1, false.
output += num → output = 9 + 7 = 16.
Eighth iteration would be num = 8, but:
At the top of the loop body, line 05 is checked again:
if (output > 10) → 16 > 10 is true, so break; is executed.
When break runs:
The loop terminates immediately.
No further iterations (for num = 8, 9, 10, 11) are executed.
Therefore, output stays at 16.
Final value of output after the loop ends is 16.
This matches option A.
Why other options do not match:
B . 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.
C . 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.
D . 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.
So:
Answe r: A
JavaScript knowledge / Study Guide references (concept names only, no links):
for...of loop over arrays
break statement in loops (terminating a loop early)
continue statement in loops (skipping to the next iteration)
Modulo operator % to test even and odd numbers
Step-by-step execution and control flow in loops


NEW QUESTION # 53
......

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