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| Section | Objectives |
|---|---|
| WLAN Planning and Design | - Capacity and performance design considerations - Wireless coverage planning |
| Switching and Routing in Campus Networks | - Layer 2 and Layer 3 design principles - VLAN and segmentation design |
| Campus Network Fundamentals | - Enterprise campus network architecture principles - Typical campus network deployment models |
| Network Security Design | - Campus security architecture considerations - Access control strategies |
| Presales Solution Design | - Customer requirement analysis - Solution proposal and design methodology |
| Huawei Campus Network Solutions | - iMaster NCE-Campus management platform - CloudCampus solution architecture |
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NEW QUESTION # 13
Which of the following statements is true about MACsec?
Answer: C
NEW QUESTION # 14
Which of the following functions is supported by the AR6177?
Answer: B
Explanation:
The distinguishing function supported by the AR6177 is VDSL. VDSL, or Very-high-bit-rate Digital Subscriber Line, enables a branch router to obtain WAN connectivity over existing copper telephone infrastructure. It is appropriate for small branches and distributed sites where Ethernet private lines, fiber, or mobile connections are unavailable or commercially impractical.
The AR6177 can terminate the VDSL access circuit and provide routing, NAT, DHCP, VPN, and other branch-gateway functions for the connected LAN. In this single-answer question, Wi-Fi and PoE are not the defining integrated capabilities of the AR6177 model. Similarly, the complete combination of IPS, antivirus, and URL filtering belongs to a security-enhanced product profile rather than the function used to distinguish the AR6177.
Huawei's campus design material recognizes DSL links as a specific WAN-access category and notes that deployments involving complex or low-speed links, including DSL, may require an appropriate branch-device deployment method. The model is therefore selected when direct VDSL-based WAN access is required.
Consequently, VDSL is the supported capability intended by this question, and option C is correct.
NEW QUESTION # 15
Which of the following can be determined through a survey of the terminal types on a customer's network?
Answer: B
Explanation:
A terminal-type survey primarily determines the appropriate network admission control solution. Different terminal categories have different authentication capabilities and security requirements. Corporate laptops may support 802.1X authentication, guests may require Portal authentication, and printers, cameras, sensors, and other dumb terminals commonly require MAC-address authentication or automatic terminal identification.
Huawei recommends selecting authentication technologies according to the terminal type and usage scenario.
For example, access switches can serve as authentication points for wired dumb terminals, while APs or other access devices can perform authentication for wireless users. After terminal identification is enabled, iMaster NCE-Campus can automatically assign VLANs, ACLs, security groups, QoS parameters, and other authorization policies according to terminal category.
The survey therefore establishes which endpoints support interactive authentication, which require non- interactive admission, and which must receive special isolation or compliance policies. It does not independently determine the complete physical network architecture or the overall O & M platform.
Consequently, the terminal survey is used to formulate the network admission control solution, making option C correct.
NEW QUESTION # 16
Which of the following parameters is not mandatory for GRE configuration?
Answer: A
Explanation:
Enabling the GRE checksum is optional. A functional point-to-point GRE tunnel requires a tunnel interface, GRE as the tunnel protocol, and reachable source and destination tunnel endpoints. The source identifies the local interface or IP address used to construct the delivery header, while the destination identifies the remote GRE endpoint. Without these endpoint parameters, the device cannot correctly encapsulate and deliver packets to the peer.
The checksum field is controlled by the Checksum Present bit in the GRE header. When checksum processing is enabled, the sender includes a checksum covering the GRE header and payload, and the receiver verifies it.
This can provide additional corruption detection, but it increases processing and is not required for basic GRE operation. RFC 2784 explicitly labels the checksum field as optional and states that it is present only when the Checksum Present bit is set.
Huawei SD-WAN uses GRE or GRE over IPsec to establish data channels between edge devices. The essential tunnel and transport-network information is distributed through the control system, while optional GRE functions such as checksum validation may be enabled according to operational requirements.
NEW QUESTION # 17
In hierarchical networking, which of the following devices is used for communication between different areas?
Answer: A
Explanation:
A border device, or more precisely a device at a border site, provides communication between different areas in a hierarchical SD-WAN topology. The hierarchical model divides a large WAN into multiple areas. Each area can independently use a hub-spoke or full-mesh topology, while selected border sites connect the local area to a centralized backbone area.
When a non-border site receives a route originating in another area, the route's next-hop site ID is changed to the border site in its own area. The local border device then forwards traffic toward the border site in the destination area or toward an interconnected hub site. Ordinary edge devices provide connectivity for their own sites but do not automatically perform cross-area transit.
Huawei describes border sites as members of both the level-2 area network and the level-1 backbone network.
These sites collectively implement interconnection between areas. Huawei further explains that inter-area routes point to border sites and recommends two border sites operating in active/standby mode for reliability.
Therefore, the correct answer is B.
NEW QUESTION # 18
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