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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Restricting and Sorting Data	15%	- Substitution variables, DEFINE and VERIFY commands - ORDER BY clause and sorting rules - WHERE clause and filtering conditions - Operator precedence
Relational Database Concepts	10%	- Relationship between database and SQL - ERD and SQL statement mapping - Theoretical and physical aspects of relational databases
Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins
Aggregating Data Using Group Functions	10%	- GROUP BY and HAVING clauses - SUM, AVG, COUNT, MAX, MIN functions - Handling NULLs in group functions
Conversion Functions and Conditional Expressions	10%	- TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions - Implicit and explicit data type conversion
Using Data Dictionary Views		- Retrieve metadata and object information
Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and maintain indexes - Create and use sequences
Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Retrieving Data Using SQL SELECT Statement	20%	- Arithmetic operations and NULL handling - SELECT statement syntax and usage - Column aliases, concatenation, literals and DISTINCT
Managing Views		- Updatable and read-only views - Create, modify and drop views
Managing Tables and Constraints		- Constraints: primary key, foreign key, unique, check, not null - Temporary and external tables - Data types, creating/altering/dropping tables
Manipulating Data and Managing Transactions		- Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements - Multi-table inserts
Using SET Operators		- UNION, UNION ALL, INTERSECT, MINUS operators - Ordering results with set operations
Controlling User Access		- Roles, granting and revoking privileges - System and object privileges

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Oracle Database SQL Sample Questions (Q252-Q257):

NEW QUESTION # 252
View the Exhibit and examine the details of the PRODUCT_INFORMATION table.

You have the requirement to display PRODUCT_NAME and LIST_PRICE from the table where the CATEGORYJD column has values 12 or 13, and the SUPPLIER_ID column has the value
102088. You executed the following SQL statement:
SELECT product_name, list_price
FROM product_information
WHERE (category_id = 12 AND category_id = 13)
AND supplier_id = 102088;
Which statement is true regarding the execution of the query?

A. It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.
B. It would execute and the output would display the desired result.
C. It would execute but the output would return no rows.
D. It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.

Answer: C

NEW QUESTION # 253
Examine this description of the PRODUCTS table:

Rows exist in this table with data in all the columns. You put the PRODUCTS table in read-only mode.
Which three commands execute successfully on PRODUCTS? (Choose three.)

A. DROP TABLE products;
B. CREATE INDEX price_idx ON products (price);
C. ALTER TABLE products DROP UNUSED COLUMNS;
D. ALTER TABLE products DROP COLUMN expiry_date;
E. ALTER TABLE products SET UNUSED (expiry_date);
F. TRUNCATE TABLE products;

Answer: A,B,F

NEW QUESTION # 254
You must write a query that prompts users for column names and conditions every time it is executed.
The user must be prompted only once for the table name.
Which statement achieves those objectives?

A. SELECT &col1, &col2
FROM &&table
WHERE &condition = &&cond
B. SELECT &col1, '&col2'
FROM &table
WHERE &&condition = '&cond';
C. SELECT &col1, &col2
FROM &&table
WHERE &condition = &cond;
D. SELECT &col1, &col2
FROM "&table"
WHERE &condition = &cond;

Answer: C

Explanation:
Explanation/Reference:

NEW QUESTION # 255
Examine these statements which execute successfully:

Both statements display departments ordered by their average salaries.
Which two are true?

A. Both statements will execute successfully If you add e.avg_sal to the select list.
B. Only the first statement will display departments with no employees.
C. Only the second statement will display departments with no employees.
D. Only the first statement will execute successfully if you add E.AVG_SAK to the select list.
E. Both statements will display departments with no employees.
F. Only the second statement will execute successfully if you add E.AVG_SAL to the select list.

Answer: A,C

Explanation:
A . Only the second statement will display departments with no employees. This is true because the second statement uses a LEFT JOIN to include all departments from the departments table, even those without matching entries in the employees table. When there are no employees in a department, the AVG(salary) will be NULL, and the department will still be displayed1.
C . Both statements will execute successfully if you add e.avg_sal to the select list. This is correct. Both statements calculate e.avg_sal as an average salary, either through a subquery or a join operation. Adding e.avg_sal to the select list will display the average salary alongside the departments. However, it's important to note that the first statement will not display departments with no employees because it does not use a join that would allow for NULL values from the employees table2.
Reference:
Understanding SQL JOINs - Stack Overflow1.
Oracle Documentation on JOIN Operations2.
Note: The other options are incorrect because:
B . The first statement will not display departments with no employees since it does not use a join that includes departments without matching employee records.
D . As explained, the first statement will not display departments with no employees.
E . There is a typo in the option; it should be E.AVG_SAL. Even if corrected, the first statement alone would not execute successfully because it does not include a join to bring in the avg_sal value.
F . The second statement will display departments with no employees, but the first statement will not, so this option is incorrect.

NEW QUESTION # 256
View the exhibit and examine the structure of the CUSTOMERStable.

Which two tasks would require subqueries or joins to be executed in a single statement?

A. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
B. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
C. finding the average credit limit of male customers residing in 'Tokyo'or 'Sydney'
D. listing of customers who do not have a credit limit and were born before 1980
E. finding the number of customers, in each city, who's marital status is 'married'.

Answer: A,B

NEW QUESTION # 257
......

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