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Salesforce JavaScript-Developer-I 시험에 합격한 후, 후보자들은 Salesforce Certified JavaScript Developer I 자격증을 받게 됩니다. 이 자격증은 JavaScript를 사용하여 Salesforce 플랫폼에서 맞춤 애플리케이션을 개발하는 능력을 검증하는 것으로, JavaScript 개발에서 최상의 실천 방법과 디자인 패턴을 구현하는 능력을 증명합니다. 이 자격증은 전 세계적으로 인정되며 Salesforce 개발에서 새로운 경력 기회로 이어질 수 있습니다.

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최신 Salesforce Developer JavaScript-Developer-I 무료샘플문제 (Q113-Q118):

질문 # 113
Refer to the code below:
01 const server = require('server');
02 /* Insert code here */
A developer imports a library that creates a web server. The imported library uses events and
callbacks to start the servers
Which code should be inserted at the line 03 to set up an event and start the web server ?

A. serve(( port) => (
B. Server.start ();
C. server.on(' connect ' , ( port) => {
console.log('Listening on ' , port) ;})
D. console.log( 'Listening on ', port) ;
E. server()

정답：C

질문 # 114
Refer to the code below:

What is the value of result when Promise. race executes?

A. Race is cancelled.
B. Car 2 completed the race
C. Car 3 completed the race
D. Car 1 crashed the race

정답：D

질문 # 115
Refer to code below:
Let productSKU = '8675309' ;
A developer has a requirement to generate SKU numbers that are always 19 characters lon, starting with 'sku', and padded with zeros.
Which statement assigns the values sku0000000008675309 ?

A. productSKU = productSKU .padEnd (16. '0').padstart('sku');
B. productSKU = productSKU .padStart (16. '0').padstart(19, 'sku');
C. productSKU = productSKU .padEnd (16. '0').padstart(19, 'sku');
D. productSKU = productSKU .padStart (19. '0').padstart('sku');

정답：B

질문 # 116
developer creates a new web server that uses Node.js. It imports a server library that
uses events and callbacks for handling server functionality.
The server library is imported with require and is made available to the code by a
variable named server. The developer wants to log any issues that the server has while booting
up.
Given the code and the information the developer has, which code logs an error at boost
with an event?

A. Server.catch ((server) => {
console.log('ERROR', error);
});
B. Server.error ((server) => {
console.log('ERROR', error);
});
C. Try{
server.start();
} catch(error) {
D. Server.on ('error', (error) => {
console.log('ERROR', error);
});

정답：D

설명：
console.log('ERROR', error);
}

질문 # 117
Refer to the code below:
01 function myFunction(reassign) {
02 let x = 1;
03 var y = 1;
04
05 if (reassign) {
06 let x = 2;
07 var y = 2;
08 console.log(x);
09 console.log(y);
10 }
11
12 console.log(x);
13 console.log(y);
14 }
What is displayed when myFunction(true) is called?

A. 2 2 1 2
B. 2 2 1 1
C. 2 2 2 2
D. 2 2 undefined undefined

정답：A

설명：
This question tests understanding of let (block scope) and var (function scope) in JavaScript.
* Initial declarations in the function:
let x = 1; // line 2
var y = 1; // line 3
Here:
* x is declared with let, so it is block-scoped to the function body.
* y is declared with var, so it is function-scoped to the entire function.
* Inside the if (reassign) block (and since reassign is true, we enter it):
if (reassign) {
let x = 2; // line 6
var y = 2; // line 7
console.log(x); // line 8
console.log(y); // line 9
}
Detailed behavior:
* let x = 2; on line 6 creates a new block-scoped variable x that exists only inside the if block. It does not change the outer x declared on line 2.
* var y = 2; on line 7 declares y with var again, but var is function-scoped. This effectively reassigns the same y defined on line 3 for the entire function. After this line, y is 2 everywhere in the function.
Now, inside the if block:
* console.log(x); (line 8) logs the inner block-scoped x, which is 2.
* console.log(y); (line 9) logs y, which is the function-scoped y that was set to 2.
So the first two outputs are:
* 2
* 2
* After the if block, execution continues:
console.log(x); // line 12
console.log(y); // line 13
Outside the if block:
* The block-scoped let x = 2; no longer exists; it was only visible inside the if block.
* The outer let x = 1; (line 2) is still in scope and has not been changed.
Thus:
* console.log(x); (line 12) logs the outer x, which is still 1.
* console.log(y); (line 13) logs y which, due to var y = 2; inside the if, is now 2 for the whole function.
Therefore, when myFunction(true) is called, the output in order is:
* 2 (inner x in if)
* 2 (function-scoped y after reassignment)
* 1 (outer x after if)
* 2 (function-scoped y remains 2)
This corresponds to:
The answer: B (2 2 1 2)
JavaScript knowledge / study guide reference concepts:
* let declarations and block scope
* var declarations and function scope
* Shadowing of variables with let inside a block
* Re-declaration and reassignment of var within a function
* Execution order of statements and console output

질문 # 118
......

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