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| Section | Weight | Objectives |
|---|
| Exponents, Radicals, and Quadratic Relationships | 15% | - Simplifying radical expressions - Properties of exponents - Solving quadratic equations - Basic quadratic graphs
|
| Algebraic Expressions and Operations | 20% | - Simplifying and evaluating expressions - Operations with polynomials - Variables, constants, and coefficients - Order of operations
|
| Graphing and Functions | 25% | - Linear functions and their graphs - Coordinate plane and plotting points - Function notation and evaluation - Slope and equations of lines
|
| Systems of Equations and Inequalities | 15% | - Solving by substitution and elimination - Applications of systems - Graphical solutions
|
| Linear Equations and Inequalities | 25% | - Solving and graphing inequalities - Real-world applications - Solving single-variable equations
|
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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q107-Q112):
NEW QUESTION # 107
The data in the scatterplot represents the number of monthly train crossings at a particular intersection over time.

Which type of function should be used to model the data?
- A. Polynomial
- B. Exponential
- C. Linear
- D. Logistic
Answer: B
Explanation:
The scatterplot shows a decreasing pattern.
At first, the number of monthly crossings decreases quickly. Then the values begin to level off.
This type of pattern is characteristic of an exponential decay model.
A linear model would show points decreasing at a constant rate, forming an approximately straight line. Here, the decrease is not constant; it is steep at first and then slows down.
A logistic model usually has an S-shaped pattern, which is not shown here.
A polynomial model may curve, but the long-term leveling behavior shown in the scatterplot is best represented by an exponential decay function.
Therefore, the correct answer is:
# ( " D " )
NEW QUESTION # 108
The function f(n) represents the relationship between the distances traveled by two vehicles, where n is the distance traveled by vehicle A and f is the distance traveled by vehicle B. The distance traveled by vehicle B is 17 more than the distance traveled by vehicle A.
Which function represents this situation?
- A. f(n)=n/17
- B. f(n)=17n
- C. f(n)=n+17
- D. f(n)=n#17
Answer: C
NEW QUESTION # 109
The given function represents the price of a commodity, p, in dollars, based on the number of months, m, since the beginning of 2020.
p(m)=5m+5
What is the average rate of change of the price over the interval m=1to m=10?
Answer: D
Explanation:
The function is:
p(m)=5m+5
This is a linear function in the form:
p(m)=mx+b
For a linear function, the average rate of change over any interval is the same as the slope.
The slope is the coefficient of m:
5
So the price increases at a constant rate of:
$5 " per month "
We can also verify using the average rate of change formula:
(p(10)-p(1))/(10-1)
Find p(10):
p(10)=5(10)+5=55
Find p(1):
p(1)=5(1)+5=10
Now calculate:
(55-10)/(10-1)
=45/9
=5
NEW QUESTION # 110
A cart is being loaded with boxes, and each box has the same weight. After 4 boxes are loaded, the total weight of the boxes and cart is 116 pounds. After 9 boxes are loaded, the total weight is 161 pounds.
What is the weight of each box?
- A. 80 pounds
- B. 9 pounds
- C. 18 pounds
- D. 29 pounds
Answer: B
Explanation:
This situation can be modeled with a linear relationship because each box has the same weight.
We are given:
4 " boxes " #116 " pounds "
and
9 " boxes " #161 " pounds "
The weight increases because more boxes are added.
First, find the change in total weight:
161-116=45
Then find the change in the number of boxes:
9-4=5
Since 5 additional boxes increased the total weight by 45 pounds, the weight of each box is:
45/5=9
So each box weighs:
9 " pounds "
Check:
If each box weighs 9 pounds, then adding 5 more boxes adds:
5(9)=45
116+45=161
This matches the given information.
NEW QUESTION # 111
The number of acres affected by an invasive species can be modeled using the logistic function f(x), where xrepresents the number of months since the species was introduced and f(x)represents the number of affected acres. The graph of f(x)is shown.

What happens as time progresses from month 2 to month 6?
- A. The number of affected acres decreases faster and faster.
- B. The number of affected acres decreases slower and slower.
- C. The number of affected acres increases faster and faster.
- D. The number of affected acres increases slower and slower.
Answer: C
Explanation:
This is also a logistic growth curve.
Analyze the interval from month 2 to month 6:
The graph is increasing during this time.
The curve is becoming steeper, meaning the slope is increasing.
This indicates the rate of change is getting larger over time.
So, the number of affected acres is:
" increasing faster and faster "
This corresponds to the early-to-middle growth phase of a logistic function.
NEW QUESTION # 112
......
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