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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Topic 1: Managing Views		- Create, modify and drop views - Updatable and read-only views
Topic 2: Controlling User Access		- Roles, granting and revoking privileges - System and object privileges
Topic 3: Conversion Functions and Conditional Expressions	10%	- TO_CHAR, TO_NUMBER, TO_DATE functions - Implicit and explicit data type conversion - NVL, NULLIF, COALESCE and CASE expressions
Topic 4: Managing Indexes, Synonyms and Sequences		- Create and use sequences - Create and use synonyms - Create and maintain indexes
Topic 5: Manipulating Data and Managing Transactions		- Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements - Multi-table inserts
Topic 6: Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins
Topic 7: Using Subqueries to Solve Queries		- Single-row and multi-row subqueries - Correlated subqueries for update/delete
Topic 8: Aggregating Data Using Group Functions	10%	- SUM, AVG, COUNT, MAX, MIN functions - GROUP BY and HAVING clauses - Handling NULLs in group functions
Topic 9: Using Data Dictionary Views		- Retrieve metadata and object information
Topic 10: Using SET Operators		- UNION, UNION ALL, INTERSECT, MINUS operators - Ordering results with set operations
Topic 11: Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Topic 12: Retrieving Data Using SQL SELECT Statement	20%	- SELECT statement syntax and usage - Column aliases, concatenation, literals and DISTINCT - Arithmetic operations and NULL handling
Topic 13: Relational Database Concepts	10%	- Relationship between database and SQL - Theoretical and physical aspects of relational databases - ERD and SQL statement mapping
Topic 14: Managing Tables and Constraints		- Constraints: primary key, foreign key, unique, check, not null - Temporary and external tables - Data types, creating/altering/dropping tables
Topic 15: Working with Time Zones and Date/Time Data		- TIMESTAMP, INTERVAL data types - Time zone conversion functions
Topic 16: Restricting and Sorting Data	15%	- WHERE clause and filtering conditions - Operator precedence - Substitution variables, DEFINE and VERIFY commands - ORDER BY clause and sorting rules

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Oracle Database SQL Sample Questions (Q416-Q421):

NEW QUESTION # 416
View the exhibit and examine the ORDERS table.
ORDERS
Name
Null?
Type
ORDER ID
NOT NULL
NUMBER(4)
ORDATE DATE
DATE
CUSTOMER ID
NUMBER(3)
ORDER TOTAL
NUMBER(7,2)
The ORDERS table contains data and all orders have been assigned a customer ID. Which statement would add a NOT NULL constraint to the CUSTOMER_ID column?

A. ALTER TABLE ordersMODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
B. ALTER TABLE ordersADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
C. ALTER TABLE ordersADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
D. ALTER TABLE ordersMODIFY CONSTRAINT orders_cust_id_nn NOT NULL
(customer_id);

Answer: A

NEW QUESTION # 417
Examine the structure of the MEMBERStable.

Which query can be used to display the last names and city names only for members from the states MO and MI?

A. SELECT last_name, city FROM members WHERE state ='MO' AND state ='MI';
B. SELECT last_name, city FROM members WHERE state LIKE 'M%';
C. SELECT DISTINCT last_name, city FROM members WHERE state ='MO' OR state
='MI';
D. SELECT last_name, city FROM members WHERE state IN ('MO', 'MI');

Answer: D

NEW QUESTION # 418
Which two tasks require subqueries?

A. Display the minimum PROD_LIST_PRICE for each product status.
B. Display the total number of products supplied by supplier 102 which have a product status of obsolete.
C. Display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICE.
D. Display products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products, and whose status is orderable.
E. Display suppliers whose PROD_LIST_PRICE is less than 1000.

Answer: C,D

Explanation:
C: True. To display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICE, you would need to use a subquery to first calculate the average PROD_LIST_PRICE and then use that result to compare each product's list price to the average.
E: True. Displaying products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products and whose status is orderable would require a subquery. The subquery would be used to determine the average PROD_LIST_PRICE, and then this average would be used in the outer query to filter the products accordingly.
Subqueries are necessary when the computation of a value relies on an aggregate or a result that must be obtained separately from the main query, and cannot be derived in a single level of query execution.
Reference:
Oracle's SQL documentation provides guidelines for using subqueries in scenarios where an inner query's result is needed to complete the processing of an outer query.

NEW QUESTION # 419
View the Exhibit and examine the structure of CUSTOMERStable.

Evaluate the following query:

Which statement is true regarding the above query?

A. It executes successfully.
B. It produces an error because the condition on the CUST_CITY column is not valid.
C. It produces an error because the condition on the CUST_FIRST_NAME column is not valid.
D. It produces an error because conditions on the CUST_CREDIT_LIMIT column are not valid.

Answer: A

NEW QUESTION # 420
Examine the types and examples of relationships that follow:

Which option indicates correctly matched relationships? (Choose the best answer.)

A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c

Answer: A

NEW QUESTION # 421
......

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