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Oracle 1z0-071 Certification Exam is designed to test the skills of candidates in various areas such as SQL fundamentals, data retrieval using SQL, data manipulation, and database design. 1z1-071 exam comprises multiple-choice questions and requires candidates to have a thorough understanding of SQL concepts and Oracle Database management. 1z1-071 exam is based on the latest version of Oracle Database, which makes it highly relevant for current industry needs.

Oracle 1z0-071 exam is an intermediate-level certification exam that covers a broad range of SQL topics. 1z1-071 Exam requires candidates to have a deep understanding of SQL concepts and experience with the Oracle SQL database management system. 1z1-071 exam is 90 minutes long, and candidates need to answer 73 questions correctly to pass the exam.

Oracle Database SQL Sample Questions (Q163-Q168):

NEW QUESTION # 163
You must create a table EMPLOYEES in which the values in the columns EMPLOYEES_ID and LOGIN_ID must be unique and not null.
Which two SQL statements would create the required table? (Choose two.)

A. CREATE TABLE employees
(employee_id NUMBER,
Login_id NUMBER,
Employee_name VARCHAR2(100),
Hire_date DATE,
CONSTRAINT emp_id_uk UNIQUE (employee_id, login_id);
CONSTRAINT emp_id_nn NOT NULL (employee_id, login_id));
B. CREATE TABLE employees
(employee_id NUMBER,
login_id NUMBER,
employee_name VARCHAR2(25),
hire_date DATE,
CONSTRAINT emp_id_pk PRIMARY KEY (employee_id, login_id));
C. CREATE TABLE employees
(employee_id NUMBER,
Login_id NUMBER,
Employee_name VARCHAR2(100),
Hire_date DATE,
CONSTRAINT emp_id_ukUNIQUE (employee_id, login_id));
D. CREATE TABLE employees
(employee_id NUMBER CONSTRAINT emp_id_pk PRIMARY KEY,
Login_id NUMBER UNIQUE,
Employee_name VARCHAR2(25),
Hire_date DATE);
E. CREATE TABLE employees
(employee_id NUMBER CONSTRAINT emp_id_nn NOT NULL,
Login_id NUMBER CONSTRAINT login_id_nn NOT NULL,
Employee_name VARCHAR2(100),
Hire_date DATE,
CONSTRAINT emp_id_ukUNIQUE (employee_id, login_id));

Answer: B,E

NEW QUESTION # 164
Which statement fails to execute successfully?

Answer: C

Explanation:
In Oracle SQL, when performing a JOIN operation, the ON clause is used to specify the condition that relates the two tables being joined. The WHERE clause can be used to further filter the result set.
A) This is a valid join condition using the WHERE clause to filter the rows after the join has been made.
B) This statement will fail because the ON clause should only contain conditions that relate the two tables. The condition for filtering the departments table should be in the WHERE clause, not in the ON clause. This is a common mistake when writing JOIN statements.
C) This is a correct statement. The ON clause specifies how the tables are related and the WHERE clause specifies an additional filtering condition for the query.
D) This statement is also correct. It's similar to the first statement (A) and properly places the department_id filter in the ON clause, which is acceptable though not typically best practice as it can be less readable than using a WHERE clause for non-join conditions.
When the JOIN operation is executed, the database first pairs rows from the joined tables that meet the join condition specified by the ON clause. Then, it filters the result of the JOIN operation based on the condition specified in the WHERE clause.
References:
* Oracle Documentation on Joins:
https://docs.oracle.com/database/121/SQLRF/queries006.htm#SQLRF52359

NEW QUESTION # 165
Which two statements are true regarding the COUNT function? (Choose two.)

A. COUNT(cust_id) returns the number of rows including rows with duplicate customer IDs and NULL value in the CUST_ID column
B. COUNT(*) returns the number of rows including duplicate rows and rows containing NULL value in any of the columns
C. The COUNT function can be used only for CHAR, VARCHAR2 and NUMBER data types
D. A SELECT statement using COUNT function with a DISTINCT keyword cannot have a WHERE clause
E. COUNT(DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULL values in the INV_AMT column

Answer: B,E

Explanation:
Using the COUNT Function
The COUNT function has three formats:
COUNT(*)
COUNT(expr)
COUNT(DISTINCT expr)
COUNT(*) returns the number of rows in a table that satisfy the criteria of the SELECT
statement, including duplicate rows and rows containing null values in any of the columns.
If a WHERE clause is included in the SELECT statement, COUNT(*) returns the number of
rows that satisfy the condition in the WHERE clause.
In contrast,
COUNT(expr) returns the number of non-null values that are in the column identified by
expr.
COUNT(DISTINCT expr) returns the number of unique, non-null values that are in the
column identified by expr.

NEW QUESTION # 166
View the Exhibit and examine the structure in the EMPLOYEES tables.

Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=10;
What would be the outcome of the above SQL statement?

A. The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.
B. The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.
C. The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.
D. The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.

Answer: D

NEW QUESTION # 167
View the Exhibit and examine the description for the PRODUCTS and SALES table.

PROD_IDis a primary key in the PRODUCTStable and foreign key in the SALEStable with ON DELETE CASCADEoption. The SALEStable contains data for the last three years. You want to remove all the rows from the PRODUCTStable for which no sale was done for the last three years.
Which is the valid DELETEstatement?

A. DELETE
FROM products
WHERE prod_id = (SELECT prod_id
FROM sales
WHERE time_id - 3*365 = SYSDATE );
B. DELETE
FROM products
WHERE prod_id IN (SELECT prod_id
FROM sales
WHERE SYSDATE - 3*365 >= time_id);
C. DELETE
FROM products
WHERE prod_id = (SELECT prod_id
FROM sales
WHERE SYSDATE >= time_id - 3*365 );
D. DELETE
FROM products
WHERE prod_id IN (SELECT prod_id
FROM sales
WHERE time_id >= SYSDATE - 3*365 );

Answer: B

NEW QUESTION # 168
......

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