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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Topic 1: Foundations of Algebra	- Equations and Inequalities 1. Linear equations in one variable 2. Inequalities and interval notation - Algebraic Expressions 1. Simplifying expressions 2. Evaluating expressions 3. Order of operations
Topic 2: Polynomial and Rational Expressions	- Polynomials 1. Factoring techniques 2. Operations with polynomials - Rational Expressions 1. Restrictions on variables 2. Simplification
Topic 3: Linear Functions and Systems	- Systems of Equations 1. Substitution method 2. Elimination method - Linear Equations 1. Slope-intercept form 2. Point-slope form
Topic 4: Functions and Graphs	- Function Concepts 1. Function notation 2. Domain and range - Graphing Functions 1. Transformations of graphs 2. Coordinate plane interpretation
Topic 5: Exponential and Logarithmic Concepts	- Exponential Functions 1. Exponential equations 2. Growth and decay models - Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q74-Q79):

NEW QUESTION # 74
The function P(t)represents the weekly profit, in thousands of dollars, for a rental store since opening. The graph of P(t)is shown.

When did the store have its maximum weekly profit?

A. Approximately 3 years after the store opened
B. Approximately 17 years after the store opened
C. Approximately 7 years after the store opened
D. Approximately 5.5 years after the store opened

Answer: D

Explanation:
The graph shows:
P(t)= " weekly profit in thousands of dollars "
where:
t= " years since opening "
The graph is a downward-opening curve, so it has a maximum value at its highest point. In Applied Algebra, the highest point of this kind of polynomial graph is called the vertex.
To answer the question, we need the t-value of the vertex because the question asks when the store had its maximum weekly profit.
From the graph, the highest point occurs between:
t=5
and
t=6
More specifically, it is approximately:
t=5.5
So the store had its maximum weekly profit approximately:
5.5 " years after opening "

NEW QUESTION # 75
As sacks are unloaded off a wagon, the total weight of the wagon and sacks changes. Each sack has the same weight. After 5 sacks are removed, the total weight of the wagon and remaining sacks is 135 pounds. After 9 sacks are removed, the total weight is 87 pounds. What is the weight of each sack?

A. 20 pounds
B. 12 pounds
C. 75 pounds
D. 27 pounds

Answer: B

Explanation:
This situation has a constant rate of change because each sack weighs the same amount. After 5 sacks are removed, the total weight is 135 pounds. After 9 sacks are removed, the total weight is 87 pounds. From 5 to
9 sacks removed is 4 more sacks. Over the same interval, the total weight decreases by 135#87=48 pounds.
Since 4 sacks account for a 48-pound decrease, each sack must weigh 48÷4=12 pounds. This uses the linear idea that equal changes in the input produce equal changes in the output. Therefore, the weight of each sack is
12 pounds, which is answer A.

NEW QUESTION # 76
The growth of an animal population is shown in the graph. The instantaneous rate of change at point Pis 3.74.

Which interpretation of the instantaneous rate of change is correct?

A. In 2012, the population was increasing by 3,740 animals per year.
B. In 2007, the population was increasing by 3.74 animals per year.
C. In 2007, the population was increasing by 3,740 animals per year.
D. In 2012, the population was increasing by 3.74 animals per year.

Answer: C

Explanation:
The graph shows population in thousands, and the horizontal axis represents:
" years since 1995 "
Point Pis located at approximately:
x=12
Since xrepresents years since 1995:
1995+12=2007
So point Pcorresponds to the year:
2007
The instantaneous rate of change at point Pis:
3.74
Because the vertical axis is measured in thousands, this means:
3.74 " thousand animals per year "
Convert thousands to actual animals:
3.74×1000=3740
So in 2007, the population was increasing by approximately:
3,740 " animals per year "

NEW QUESTION # 77
The logistic function f(x), whose graph is shown, models the number of registrants for an academic conference, where xrepresents the number of weeks since registration opened and f(x)represents the number of registrants.

How does the number of registrants change as time progresses from week 1 to week 7?

A. The number of registrants decreases faster and faster.
B. The number of registrants decreases slower and slower.
C. The number of registrants increases faster and faster.
D. The number of registrants increases slower and slower.

Answer: C

Explanation:
From week 1 to week 7, the graph is increasing and becoming steeper.
In Applied Algebra, when a graph is increasing and its slope is getting larger, the quantity is said to be:
" increasing faster and faster "
This interval is on the early increasing part of the logistic curve, before the graph begins to level off.
Therefore, the correct answer is:
# ( " B " )

NEW QUESTION # 78
A cart is being loaded with boxes, and each box has the same weight. After 4 boxes are loaded, the total weight of the boxes and cart is 116 pounds. After 9 boxes are loaded, the total weight is 161 pounds.
What is the weight of each box?

A. 9 pounds
B. 29 pounds
C. 80 pounds
D. 18 pounds

Answer: A

Explanation:
This situation can be modeled with a linear relationship because each box has the same weight.
We are given:
4 " boxes " #116 " pounds "
and
9 " boxes " #161 " pounds "
The weight increases because more boxes are added.
First, find the change in total weight:
161-116=45
Then find the change in the number of boxes:
9-4=5
Since 5 additional boxes increased the total weight by 45 pounds, the weight of each box is:
45/5=9
So each box weighs:
9 " pounds "
Check:
If each box weighs 9 pounds, then adding 5 more boxes adds:
5(9)=45
116+45=161
This matches the given information.

NEW QUESTION # 79
......

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