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| Section | Objectives |
|---|---|
| Xcode Developer Tools | - Demonstrate how to build and run an app
|
| View Building with SwiftUI | - Extract Subviews to simplify the structure of an overlarge View - Use List Views to iterate through collections - Use @State, @Binding, @Environment, and/or Observable to share data between Views - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Create multiple Views to implement app logic - Position and/or layout a single SwiftUI View with standard Views and modifiers |
| Swift Programming Language | - Declare and use basic Swift types
- Demonstrate proper use of structs, classes
|
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질문 # 30
You have created a view which includes some formatted text:
You decide to extract this formatted text into a subview so that you can reuse the formatting for other texts.
You highlight the Text and choose Extract subview.
You refactor ExtractedView to BigGreenTextView.
You add the line let text: String to the extracted view above the body.
You replace " That ' s all folks " with a reference to text
How should you call this extracted View from the original View?
정답：B
설명：
This question belongs to View Building with SwiftUI , specifically the domain on extracting subviews to simplify the structure of an overlarge View .
When you create a custom SwiftUI view and add a stored property like:
let text: String
that property becomes part of the view's initializer. Since the property name is text, Swift expects you to pass the value using the parameter label text: when creating the view. So the correct call is:
BigGreenTextView(text: " That ' s all folks " )
That makes B the correct answer.
Why the others are wrong:
* A is incorrect because this is not using the expected parameter label.
* C would only be correct if there were already another variable named text in the calling scope and you wanted to pass that variable instead of the literal string shown in the question.
* D is incorrect because it omits the parameter label.
This is a standard SwiftUI pattern: extract reusable formatting into a separate custom View, give it an input property, and then pass the needed value through the initializer using the property label.
질문 # 31
If View A calls View B, which Swift Property Wrapper would you use in View B in order to return the value of a state to View A?
정답：D
설명：
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , specifically the objective on using @State,
@Binding, @Environment, and observable data to share data between views.
The correct answer is @Binding because @Binding creates a two-way connection to a value that is owned by another view. In this scenario, View A owns the state, and View B needs to read and modify that value so the change is reflected back in View A. Apple's SwiftUI documentation describes a binding as a reference to a mutable value that is owned elsewhere, which is exactly the pattern used when a child view needs to update a parent view's state. ( developer.apple.com )
@State is not correct for View B here because @State is used for local state owned by that specific view. If View B used @State, it would manage its own separate copy rather than updating the parent's value.
@Environment is used to access values provided by the system or ancestor views, not for directly returning a specific parent state value in this pattern. @Observable is related to observable model objects and is not the direct property wrapper used in a child view for two-way parent-child state passing. ( developer.apple.com ) So when View A passes a state value into View B and expects updates to flow back, View B should use
@Binding .
질문 # 32
You are creating or updating human resource records for your employees. For each identifier, select whether it is a Constant or a Variable Note: You will receive partial credit for each correct answer.
정답：
설명：
Explanation:
* age - Variable
* birthDate - Constant
* socialSecurityNumber - Constant
* salary - Variable
* currentDepartment - Variable
This question belongs to Swift Programming Language , specifically the objective on demonstrating when to use constants and variables . In Swift, a constant is declared with let and is used for values that should not change after they are set. A variable is declared with var and is used for values that may change over time.
Birth date is a constant because a person's date of birth does not change. Social security number is also a constant because it is intended to be a fixed identifier for that employee record. By contrast, age is a variable because it changes over time. Salary is a variable because compensation can be adjusted. Current department is also a variable because an employee may transfer to another department.
This matches Swift best practice: use let for fixed data and var for mutable data. So in a human resources record, identifiers that are permanent should be constants, while values that can change during employment should be variables.
질문 # 33
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
정답：B,D
설명：
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
질문 # 34
Review the code snippet.
Which statement completes the code snippet so that:
* The lastReleaseDate remains the same when nextApplePhone.releaseDate is nil.
* The lastReleaseDate updates to the nextApplePhone.releaseDate when nextApplePhone.releaseDate is NOT nil.
정답：A
설명：
This question is from Swift Programming Language , especially the domains for Optional types , safe and unsafe unwrapping , and control flow . The code uses the ternary conditional operator :
nextApplePhone.releaseDate != nil ? _____
In Swift, the ternary operator follows this structure:
condition ? valueIfTrue : valueIfFalse
So if nextApplePhone.releaseDate != nil is true, the expression must return the new release date. If it is false, it must keep lastReleaseDate unchanged. That means the missing part must be:
nextApplePhone.releaseDate! : lastReleaseDate
which is option D .
This works because nextApplePhone.releaseDate is declared as String?, so it is an optional. Once the condition confirms it is not nil, the code force-unwraps it with ! to access the underlying String value. If the optional is nil, the expression returns lastReleaseDate instead. Apple's Swift documentation describes the ternary conditional operator as a shortcut for choosing one of two expressions based on a condition, and it explains that force unwrapping with ! accesses an optional's wrapped value when you know it is not nil.
The other options are incorrect because they reverse the true/false logic, omit the needed unwrap, or contain invalid identifiers. Therefore, the correct completion is D .
질문 # 35
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