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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Loops and Iteration | 20% | - Iterating over sequences - For loops and while loops - Break, continue, and pass statements |
| Topic 2: Functions and Modular Programming | 20% | - Variable scope and code reuse - Defining and calling functions - Parameters, arguments, and return values |
| Topic 3: Variables, Data Types, and Basic Operations | 20% | - Variables and assignment - Arithmetic operations and type conversion - Data types: integers, floats, strings, booleans |
| Topic 4: Control Flow and Decision Making | 20% | - If, elif, else statements - Comparisons and logical operators - Conditional expressions |
| Topic 5: Data Structures and Input/Output | 20% | - Lists, tuples, dictionaries, sets - Basic file handling - User input and output operations |
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質問 # 35
Fix the logic error in this function that should return the larger of two numbers.
def find_maximum(a, b):
if a < b:
return a
else:
return b
正解：
解説：
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function should return the larger number.
Step 2: The condition a < b means b is larger than a.
Step 3: In the original code, when a < b is true, it incorrectly returns a.
Step 4: The return values need to be corrected.
Correct code:
def find_maximum(a, b):
if a < b:
return b
else:
return a
Alternative correct code:
def find_maximum(a, b):
if a > b:
return a
else:
return b
Example:
print(find_maximum(10, 20))
print(find_maximum(30, 15))
Output:
20
30
質問 # 36
A program uses this while loop to count down:
count = 5
while count > 0:
print(count)
Which issue is preventing the loop from working correctly?
正解：A
解説：
The loop condition is:
while count > 0:
At the start, count is 5, so the condition is true. The program prints the value of count.
However, inside the loop, the value of count is never changed. That means count always stays 5, so the condition count > 0 is always true. As a result, the loop runs forever.
A corrected version would be:
count = 5
while count > 0:
print(count)
count = count - 1
This decreases count by 1 during each loop iteration. Eventually, count becomes 0, and the condition count >
0 becomes false.
Therefore, the correct answer isB. It runs infinitely because count is never modified.
質問 # 37
How can the first four characters be extracted from the string ' computer ' ?
正解：D
解説：
Python strings are sequences, and sequence values can be accessed using indexing and slicing.
The first character in a Python string has index 0. To extract the first four characters from ' computer ' , the slice should start at index 0 and stop at index 4.
Example:
' computer ' [0:4]
Result:
' comp '
In Python slicing, the start index is included, but the stop index is excluded. So [0:4] includes characters at indexes 0, 1, 2, and 3.
The official Python documentation explains that slicing with a[start:stop] selects items from the start index up to, but not including, the stop index.
Therefore, the correct answer is A. ' computer ' [0:4].
質問 # 38
Complete the function add_item(numeric_list, new_number) that takes a list of numbers and a new number, and returns a new list that appends the new number to the end of the list.
For example, add_item([1, 2, 3], 4) should return [1, 2, 3, 4] .
正解：D
解説：
The correct function uses the list method append() to add new_number to the end of numeric_list.
Correct code:
def add_item(numeric_list, new_number):
numeric_list.append(new_number)
return numeric_list
Example:
add_item([1, 2, 3], 4)
Result:
[1, 2, 3, 4]
Python's data structures documentation explains that list.append(x) adds an item to the end of the list.
Therefore, the correct answer isA.
質問 # 39
Write a complete function reverse_string(text) that takes a string and returns it reversed.
For example, reverse_string( " hello " ) should return " olleh " .
def reverse_string(text):
# TODO: Return the reversed string
pass
正解：
解説：
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one string parameter named text.
Step 2: Python slicing can be used to reverse a string.
Step 3: The slice [::-1] means start at the end of the string and move backward by one character at a time.
Step 4: Return text[::-1].
Correct code:
def reverse_string(text):
return text[::-1]
Example:
print(reverse_string( " hello " ))
Output:
olleh
質問 # 40
......
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