1z1-071テストトレーニング & 1z1-071受験記

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Oracle 1z1-071 Exam Syllabus Topics:

SectionObjectives
Topic 1: SQL Functions- Conversion and conditional functions
  • 1. TO_CHAR, TO_NUMBER, CASE expressions
    - Single-row functions
    • 1. Character, numeric, date functions
      Topic 2: SQL Retrieval- SELECT statements and filtering data
      • 1. ORDER BY and row limiting
        • 2. WHERE clause and conditions
          - Joins and set operations
          • 1. INNER, OUTER, CROSS joins
            • 2. UNION, INTERSECT, MINUS
              Topic 3: Relational Database Concepts- Data types and database objects overview
              - Tables, rows, columns, and relational model basics
              Topic 4: Data Manipulation and Schema Objects- DML operations
              • 1. INSERT, UPDATE, DELETE, MERGE
                - DDL operations
                • 1. CREATE, ALTER, DROP tables and constraints
                  Topic 5: Subqueries and Advanced SQL- Single-row and multi-row subqueries
                  - Correlated subqueries and nested queries

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                  Oracle Database SQL 認定 1z1-071 試験問題 (Q291-Q296):

                  質問 # 291
                  View the exhibit for the structure of the STUDENT and FACULTY tables.

                  You need to display the faculty name followed by the number of students handled by the faculty at the base location.
                  Examine the following two SQL statements:
                  Statement 1
                  SQL>SELECT faculty_name, COUNT(student_id)
                  FROM student JOIN faculty
                  USING (faculty_id, location_id)
                  GROUP BY faculty_name;
                  Statement 2
                  SQL>SELECT faculty_name, COUNT(student_id)
                  FROM student NATURAL JOIN faculty
                  GROUP BY faculty_name;
                  Which statement is true regarding the outcome?

                  正解：B


                  質問 # 292
                  Examine the data in the COLORS table:

                  Examine the data in the BRICKS table:

                  Which two queries return all the rows from COLORS?

                  正解：D、E

                  解説：
                  In SQL, to return all rows from one table in a join regardless of whether they match rows in the other table, a LEFT JOIN is used when we want all rows from the left table, or a RIGHT JOIN when we want all rows from the right table. Here's an explanation for each query provided in the context of the COLORS and BRICKS tables:
                  A : This query uses a LEFT JOIN and will return all the rows from the COLORS table (c) because it is on the left side of the join. Additionally, it joins the BRICKS table (b) on the condition that the color_rgb_hex_value matches. The condition in the WHERE clause (b.brick_id > 0) will not exclude any COLORS rows because it only filters the rows from the right table (BRICKS) after the join.
                  B : This query uses a RIGHT JOIN, and while it does return all rows from the COLORS table, it doesn't place it on the left side of the join, which is not what is typically expected from a RIGHT JOIN to return all rows from the right side table.
                  C : This query is a plain JOIN (also known as an inner join), which only returns rows that have matching values in both tables, so it will not return all the rows from the COLORS table if there is no match in the BRICKS table.
                  D :This query uses a FULL JOIN, which returns all rows when there is a match in one of the tables. Hence, it will return all the rows from both the COLORS and BRICKS tables. While this does return all rows from the COLORS table, it also includes all rows from the BRICKS table, which may not be desired if the requirement was only to return all rows from COLORS.
                  E : This query is similar to option A and uses the USING clause to specify the join condition. The USING clause is used when both tables have a column with the same name and is meant to simplify the syntax. However, in this case, the columns do not have the same name in both tables (RGB_HEX_VALUE in COLORS and COLOR_RGB_HEX_VALUE in BRICKS), so this query will not execute successfully.
                  Reference:
                  Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Joins"
                  Oracle Database SQL Language Reference, 12c Release 1 (12.1): "LEFT OUTER JOIN" Oracle Database SQL Language Reference, 12c Release 1 (12.1): "RIGHT OUTER JOIN" Oracle Database SQL Language Reference, 12c Release 1 (12.1): "FULL OUTER JOIN" Based on the explanations above, the correct answers that return all rows from the COLORS table are A and D. However, D includes all rows from BRICKS as well, which may not be the intended requirement if the question specifies only rows from COLORS should be returned. Thus, A is the most accurate answer to the question as it adheres to the standard expectation of a LEFT JOIN.


                  質問 # 293
                  Examine the description of the CUSTOMERS table:

                  Which three statements will do an implicit conversion?

                  正解：A、B、C


                  質問 # 294
                  Examine the data in the INVOICES table:

                  Examine the data in the CURRENCIES table:
                  CURRENCY_CODE
                  -------------
                  JPY
                  GPB
                  CAD
                  EUR
                  USD
                  Which query returns the currencies in CURRENCIES that are not present in INVOICES?

                  正解：A


                  質問 # 295
                  You execute this query:

                  What is the result?

                  正解：D


                  質問 # 296
                  ......

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