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Salesforce JS-Dev-101 Exam Syllabus Topics:

Section	Weight	Objectives
Asynchronous Programming	13%	- Event loop and execution flow - Callbacks, promises, async/await
Debugging and Error Handling	7%	- Error types and handling strategies - Console usage, breakpoints and debugging techniques
Variables, Types, and Collections	23%	- JSON parsing and manipulation - Data types, type coercion, truthy/falsy values - Variable declaration and scope - Strings, numbers, dates, arrays and methods
Server Side JavaScript	8%	- Node.js fundamentals and core modules - Package management and CLI tools
Browser and Events	17%	- Browser APIs and developer tools - DOM selection and manipulation - Event handling, propagation, listeners
Objects, Functions, and Classes	25%	- Object creation, properties, prototypes - Function types, scope, closures, arrow functions - ES6 classes, inheritance, modules, decorators
Testing	7%	- Test coverage and improvement - Unit test structure and effectiveness

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q108-Q113):

NEW QUESTION # 108
A class was written to represent items for purchase in an online store, and a second class representing items that are on sale at a discounted price. The constructor sets the name to the first value passed in. There is a new requirement for a developer to implement a description method that will return a brief description for Item and SaleItem.
01 let regItem = new Item('Scarf', 55);
02 let saleItem = new SaleItem('Shirt', 80, .1);
03 Item.prototype.description = function() { return 'This is a ' + this.name; }
04 console.log(regItem.description());
05 console.log(saleItem.description());
06
07 SaleItem.prototype.description = function() { return 'This is a discounted ' + this.name; } What is the output when executing the code above?

A. This is a Scarf
Uncaught TypeError: saleItem.description is not a function
This is a Scarf
This is a discounted Shirt
B. This is a Scarf
Uncaught TypeError: saleItem.description is not a function
This is a Shirt
This is a discounted Shirt
C. This is a Scarf
This is a Shirt
This is a discounted Scarf
This is a discounted Shirt
D. This is a Scarf
This is a Shirt
This is a Scarf
This is a discounted Shirt

Answer: D

Explanation:
Comprehensive and Detailed
Assuming SaleItem inherits from Item via prototype (e.g. SaleItem.prototype = Object.create(Item.prototype)):
Lines 01-02: create regItem and saleItem.
Line 03: define Item.prototype.description.
Now both regItem and saleItem (via inheritance) have a description method from Item.prototype.
Line 04: regItem.description() → 'This is a Scarf'.
Line 05: saleItem.description() → 'This is a Shirt' (same method, but this.name is 'Shirt').
Line 07: SaleItem.prototype.description = ... overrides description only for SaleItem instances going forward.
If we imagine calling regItem.description() and saleItem.description() again after line 07:
regItem.description() still uses Item.prototype.description → 'This is a Scarf'.
saleItem.description() now uses SaleItem.prototype.description → 'This is a discounted Shirt'.
Those four lines correspond to option B.
________________________________________

NEW QUESTION # 109
Refer to the code below:
Let str = 'javascript';
Str[0] = 'J';
Str[4] = 'S';
After changing the string indexvalues, the value of str is 'javascript'. What is the reason for this value:

A. Non-primitive values are immutable.
B. Non-primitive values are mutable.
C. Primitive values are mutable.
D. Primitive values are immutable.

Answer: D

NEW QUESTION # 110
Correct implementation of try...catch for countsDeep():

A. try {
setTimeout(function() {
countSheep();
}, 1000);
} catch (e) {
handleError(e);
}
B. try {
countsDeep();
} handleError (e){
catch(e);
}
C. setTimeout(function() {
try {
countsDeep();
} catch (e) {
handleError(e);
}
}, 1000);
D. try {
setTimeout(function() {
countsDeep();
}, 1000);
} catch (e) {
handleError(e);
}

Answer: C

Explanation:
Errors thrown inside a setTimeout callback are asynchronous.
A try...catch around setTimeout (options C and D) can't catch errors thrown inside the callback later.
You must put the try...catch inside the timeout callback (option B).
A is nonsense syntax, D also calls countSheep() instead of countsDeep().

NEW QUESTION # 111
Refer to the following array:
Let arr1 = [ 1,2, 3, 4, 5 ];

Which two lines of code result in a second array, arr2 being created such that arr2 is not a reference to arr1?

A. Let arr2 = arr1.slice(0, 5);
B. Let arr2 = arr1.sort();
C. Let arr2 = Array.from(arr1);
D. Let arr2 = arr1;

Answer: A,C

NEW QUESTION # 112
Refer to the following code:
01 class Ship {
02 constructor(size) {
03 this.size = size;
04 }
05 }
06
07 class FishingBoat extends Ship {
08 constructor(size, capacity){
09 //Missing code
10 this.capacity = capacity;
11 }
12 displayCapacity() {
13 console.log('The boat has a capacity of ${this.capacity} people.');
14 }
15 }
16
17 let myBoat = new FishingBoat('medium', 10);
18 myBoat.displayCapacity();
Which statement should be added to line 09 for the code to display
The boat has a capacity of 10 people?

A. ship.size = size;
B. super(size);
C. super.size = size;
D. this.size = size;

Answer: B

Explanation:
FishingBoat extends Ship, so it is a subclass. In ES6 classes:
When you define a constructor in a subclass, you must call super(...) before accessing this.
super(size) calls the parent class (Ship) constructor, which sets this.size = size.
So the correct constructor is:
class FishingBoat extends Ship {
constructor(size, capacity) {
super(size); // line 09
this.capacity = capacity;
}
displayCapacity() {
console.log(`The boat has a capacity of ${this.capacity} people.`);
}
}
Why others are incorrect:
B . ship.size = size;
ship is not defined; this would cause a ReferenceError.
C . super.size = size;
super is not an instance; you must call super(...) as a function to invoke the parent constructor.
D . this.size = size;
In a subclass constructor, you must call super() before using this, otherwise you get a ReferenceError. Also this bypasses the parent constructor logic.
Relevant concepts: ES6 class inheritance, extends, super() in subclass constructors, this initialization rules.

NEW QUESTION # 113
......

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