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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Browser and Events | 17% | - Browser-specific APIs - Browser Developer Tools usage - Event propagation (bubbling and capturing) - Interacting with forms and user input - Event handling and listeners - DOM manipulation |
| Topic 2: Testing | 7% | - Test coverage and reliability - Writing and modifying unit tests - Unit testing concepts - Test effectiveness evaluation |
| Topic 3: Objects, Functions, and Classes | 25% | - Modules and decorators - ES6 classes and inheritance - Function declarations and expressions - Object creation and manipulation - Execution flow and context - Higher-order functions - Arrow functions - Prototypal inheritance - Variable scope and closures |
| Topic 4: Debugging and Error Handling | 7% | - Custom error types - Console methods for debugging - Breakpoints and code inspection - Error handling techniques (try/catch/finally) |
| Topic 5: Server Side JavaScript | 8% | - Package management (npm) - CLI commands - Server-side JavaScript implementations - Core Node.js modules - Node.js fundamentals |
| Topic 6: Variables, Types, and Collections | 23% | - Primitive and complex data types - Type coercion and conversion - Arrays and collections - Variable declarations and initialization - Truthy and falsy evaluations - Strings, numbers, and dates - JSON parsing and manipulation |
| Topic 7: Asynchronous Programming | 13% | - Callbacks - Promises (creation, chaining, error handling) - Event loop and execution flow - Asynchronous patterns for business requirements - Async/Await syntax |
>> JavaScript-Developer-I시험패스 가능한 공부자료 <<
지금 같은 정보시대에, 많은 IT업체 등 사이트에Salesforce JavaScript-Developer-I인증관련 자료들이 제공되고 있습니다, 하지만 이런 사이트들도 정확하고 최신 시험자료 확보는 아주 어렵습니다. 그들의Salesforce JavaScript-Developer-I자료들은 아주 기본적인 것들뿐입니다. 전면적이지 못하여 응시자들의 관심을 쌓지 못합니다.
질문 # 114
Which three browser specific APIs are available for developer to persist data between page loads?
Choose 3 answers
정답：B,C,E
질문 # 115
Refer to the following array:
Let arr1 = [1, 2, 3, 4, 5];
Which two lines of codes result in a second array, arr2, being created such that arr2 is not a reference to arr1? Choose 2 answers
정답：A,B
질문 # 116
Refer to the following code:
What is the value of output on line 11?
정답：C
질문 # 117
Refer to the code below:
What are the value of objBook and newObBook respectively?
정답：A
질문 # 118
Refer to the code below:
let productSKU = ' 8675309 ' ;
A developer has a requirement to generate SKU numbers that are always 19 characters long, starting with ' sku ' , and padded with zeros.
Which statement assigns the value sku000000008675309?
정답：D
설명：
We start with:
let productSKU = ' 8675309 ' ;
The requirement:
* Final SKU string:
* Length: 19 characters.
* Starts with ' sku ' .
* Remaining characters are digits padded with zeros on the left (to reach total length).
We can use String.prototype.padStart and String.prototype.padEnd:
* str.padStart(targetLength, padString)
* If str.length < targetLength, it adds padString to the start until the length is targetLength.
* str.padEnd(targetLength, padString)
* Similar, but adds padString to the end.
We want a pattern like:
* First, pad the numeric part out to a fixed length with zeros.
* Then, pad to total length with ' sku ' at the start.
* Analyze Option B
productSKU = productSKU.padStart(16, ' 0 ' ).padStart(19, ' sku ' );
Step 1: productSKU.padStart(16, ' 0 ' )
* Initial productSKU is ' 8675309 ' (length 7).
* After padStart(16, ' 0 ' ), we pad zeros on the left to reach length 16.
* We need 16 # 7 = 9 zeros:
Result after step 1:
productSKU === ' 0000000008675309 ' // length 16
Step 2: .padStart(19, ' sku ' )
* Now productSKU has length 16.
* We call padStart(19, ' sku ' ):
* We need 19 # 16 = 3 extra characters.
* The pad string ' sku ' is exactly 3 characters, so it is added as-is at the start.
Result after step 2:
productSKU === ' sku0000000008675309 ' // length 19
This satisfies:
* Length 19.
* Starts with ' sku ' .
* Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.
While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:
* 3 characters of ' sku '
* Numeric part padded with zeros to make 16 characters total for the numeric part
* 3 + 16 = 19 total characters
Option B matches the intended logic using padStart and padEnd.
* Why the other options are incorrect
Option A:
productSKU = productSKU.padEnd(16, ' 0 ' ).padStart( ' sku ' );
* padEnd(16, ' 0 ' ) produces ' 8675309000000000 ' (original number followed by zeros).
* padStart( ' sku ' ) is invalid usage:
* padStart takes a numeric target length as the first argument, not a string.
* Passing ' sku ' as the first argument leads to type coercion that does not achieve the intended behavior.
* This will not reliably produce the desired SKU.
Option C:
productSKU = productSKU.padEnd(16, ' 0 ' ).padStart(19, ' sku ' );
* First padEnd(16, ' 0 ' ) from ' 8675309 ' gives ' 8675309000000000 ' (length 16, zeros at the end).
* Then padStart(19, ' sku ' ) adds 3 chars ' sku ' at the front:
* Result: ' sku8675309000000000 ' .
* This string starts with ' sku ' , but the zeros are at the end of the digits, not padding the numeric part on the left as desired.
Option D:
productSKU = productSKU.padStart(19, ' 0 ' ).padStart( ' sku ' );
* First padStart(19, ' 0 ' ) pads zeros at the left to make the length 19.
* Then padStart( ' sku ' ) again incorrectly uses a string where a numeric targetLength is required.
* This will not produce the correct SKU format.
Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with ' sku ' is:
The answer: B
References / Study Guide concepts (no links):
* String.prototype.padStart(targetLength, padString)
* String.prototype.padEnd(targetLength, padString)
* String length calculations
* Left-padding numeric strings with zeros
* Building prefixed identifiers with fixed total length
질문 # 119
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