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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Development Environment | 15% | - Xcode interface and tools
|
| Topic 2: SwiftUI Basics | 25% | - Layout and navigation
|
| Topic 3: App Design and Best Practices | 15% | - Code organization
|
| Topic 4: Swift Programming Fundamentals | 30% | - Control flow
|
| Topic 5: Data Handling and Logic | 15% | - Basic data processing
|
>> App-Development-with-Swift-Certified-User考試備考經驗 <<
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問題 #29
Review the code snippet.
Move each item from the list on the left to the correct code segment on the right. You may use each item only once.
Note: You will receive partial credit for each correct response.
答案：
解題說明：
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, properties, methods, and initializers .
A computed property does not store a value directly. Instead, it returns a value calculated from other data.
That is why description is a computed property: it returns a string based on content.
A memberwise initializer is automatically provided by Swift for structs when their stored properties are initialized through parameters. So Document(content: " Greetings! " ) is using the struct's memberwise initializer.
A type property belongs to the type itself rather than to an instance. In Swift, static var docCount = 0 is a type property because it is declared with static.
An instance method is a function that belongs to an instance of the struct or class. The display() method uses the instance's content, so it is an instance method.
A type method is a method declared with static and belongs to the type itself. So static func increment() is a type method because it changes the shared type property docCount.
問題 #30
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
答案：D,E
解題說明：
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
問題 #31
Review the code snippet.
Which statement completes the code snippet so that:
* The lastReleaseDate remains the same when nextApplePhone.releaseDate is nil.
* The lastReleaseDate updates to the nextApplePhone.releaseDate when nextApplePhone.releaseDate is NOT nil.
答案：A
解題說明：
This question is from Swift Programming Language , especially the domains for Optional types , safe and unsafe unwrapping , and control flow . The code uses the ternary conditional operator :
nextApplePhone.releaseDate != nil ? _____
In Swift, the ternary operator follows this structure:
condition ? valueIfTrue : valueIfFalse
So if nextApplePhone.releaseDate != nil is true, the expression must return the new release date. If it is false, it must keep lastReleaseDate unchanged. That means the missing part must be:
nextApplePhone.releaseDate! : lastReleaseDate
which is option D .
This works because nextApplePhone.releaseDate is declared as String?, so it is an optional. Once the condition confirms it is not nil, the code force-unwraps it with ! to access the underlying String value. If the optional is nil, the expression returns lastReleaseDate instead. Apple's Swift documentation describes the ternary conditional operator as a shortcut for choosing one of two expressions based on a condition, and it explains that force unwrapping with ! accesses an optional's wrapped value when you know it is not nil.
The other options are incorrect because they reverse the true/false logic, omit the needed unwrap, or contain invalid identifiers. Therefore, the correct completion is D .
問題 #32 
Which two assignments of a value to direction are allowed? (Choose 2.)
答案：B,C
解題說明：
This question belongs to Swift Programming Language , specifically the domain covering basic Swift types and how Swift handles enumerations . The code defines an enum named CompassPoint with the cases north, south, east, and west, and then declares direction as type CompassPoint. In Swift, an enum case can be assigned using the fully qualified form CompassPoint.north, so B is valid. Swift also allows the shorthand form .north when the compiler already knows the expected type is CompassPoint, so D is also valid. Apple's Swift language documentation explains that once a variable is known to be of a specific enumeration type, you can set its value using the shorter dot syntax.
The other options are not allowed. A is invalid because enum cases are not assigned using constructor-style syntax like CompassPoint(north). C is invalid because north by itself is not enough unless it is written with dot shorthand in a context with inferred enum type. E is invalid because north is a case of the enum type, not a member accessed from the variable instance as direction.north. Swift enum cases are referenced from the enum type or by shorthand dot syntax, not as instance properties.
問題 #33
Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.
|Complete the code by typing in the boxes.
答案：
解題說明：
NavigationLink, .sheet
Explanation:
This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
So the completed structure is effectively:
NavigationLink( " Show Blue View " ) {
BlueView()
}
sheet(isPresented: $showRedView) {
RedView()
}
This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.
問題 #34
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