4A0-F10인증덤프데모문제 & 4A0-F10인증시험덤프문제

PassTIP의 도움으로 여러분은 많은 시간과 돈을 들이지 않으셔도 혹은 여러학원등을 다니시지 않으셔도 우리 덤프로 안전하게 시험을 통과하실 수 있습니다.Nokia 4A0-F10시험자료는 우리 PassTIP에서 실제시험에 의하여 만들어진 것입니다. 지금까지의 시험문제와 답과 시험문제분석 등입니다. PassTIP에서 제공하는Nokia 4A0-F10시험자료의 문제와 답은 실제시험의 문제와 답과 아주 비슷합니다.
Nokia 4A0-F10 Exam Syllabus Topics:
| Section | Objectives |
|---|
| Topic 1: Fixed Networks Management | - Nokia SDAN solution - IPFIX telemetry collection - Corteca home device controller - NFV and SDN fundamentals - Altiplano SDAN Controller - NETCONF and YANG
|
| Topic 2: Access Network | - Access network architecture - Quality of Service (QoS) fundamentals - Multicast protocols for video distribution - Optical Line Terminal (OLT) functionality
|
| Topic 3: Introduction to Fixed Networks | - Fixed Wireless Access (FWA) - Broadband access services - FTTx concepts and solutions - Broadband network fundamentals - FTTH concepts and solutions
|
| Topic 4: Home Network | - Home network device management - Wi-Fi fundamentals - Home network devices - Home network connectivity
|
| Topic 5: Broadband Services | - Voice services - High-speed Internet services - Value-added and triple-play services - Intent-Based Networking (IBN) - Lightspan service components - Intent mapping to network layers - IPTV services
|
>> 4A0-F10인증덤프데모문제 <<
최신 4A0-F10인증덤프데모문제 덤프샘플문제 다운로드
예를 들어Nokia 4A0-F10 덤프를 보면 어떤 덤프제공사이트에서는 문항수가 아주 많은 자료를 제공해드리지만 저희Nokia 4A0-F10덤프는 문항수가 적은 편입니다.왜냐하면 저희는 더 이상 출제되지 않는 오래된 문제들을 삭제해버리기 때문입니다. 문제가 많으면 고객들의 시간을 허비하게 됩니다. PassTIP는 응시자에게 있어서 시간이 정말 소중하다는 것을 잘 알고 있습니다.
최신 Nokia Certified Fixed Networks Professional 4A0-F10 무료샘플문제 (Q40-Q45):
질문 # 40
What is the primary purpose of vectoring in a DSL access network?
- A. To divide optical power among multiple subscribers
- B. To cancel far-end crosstalk among coordinated copper lines
- C. To replace frequency-division duplexing with wavelength-division multiplexing
- D. To combine two or more copper pairs into one logical connection
정답:B
설명:
DSL vectoring is primarily used to reduce or cancel far-end crosstalk between copper pairs operating within the same cable bundle. Crosstalk can significantly reduce the attainable data rate, particularly with high-frequency technologies such as VDSL2. A vectoring system measures interference among coordinated lines and generates compensating signals that counteract the crosstalk. This can improve connection stability and allow lines to operate closer to their theoretical performance. Vectoring is different from bonding. Bonding combines the capacity of multiple physical copper pairs to increase the aggregate subscriber bitrate. Vectoring also does not divide optical signals because that is the function of a splitter in a passive optical network. Its effectiveness generally depends on coordinating the relevant DSL lines through compatible access equipment.
질문 # 41
Which component of a typical Optical Distribution Network requires no electrical power to perform its primary function?
- A. Passive optical splitter
- B. Residential gateway
- C. Optical line termination
- D. Optical network termination
정답:A
설명:
A passive optical splitter divides an incoming optical signal into multiple output paths without requiring electrical power. It is a fundamental component of the Optical Distribution Network connecting an OLT to multiple ONTs or ONUs. The splitter does not regenerate, amplify, or actively switch the optical signal. Consequently, splitting introduces optical loss that must be considered when calculating the PON power budget. The OLT and ONT are active devices because they require power to transmit, receive, process, and convert signals. A residential gateway also requires power to provide functions such as routing, firewall enforcement, DHCP, Ethernet switching, and Wi-Fi connectivity. The use of passive splitters reduces the need for powered equipment in the outside plant, which can simplify field maintenance and lower operational costs.
질문 # 42
An optical link experiences unexpectedly high signal loss immediately after a fiber cable is routed around a very tight corner. What is the most likely cause?
- A. DSL crosstalk
- B. Dynamic bandwidth allocation
- C. Chromatic dispersion
- D. Excessive macrobending
정답:D
설명:
Macrobending occurs when an optical fiber is bent with a radius smaller than its supported minimum bend radius. The excessive bend can cause part of the optical signal to escape from the core, increasing attenuation and reducing the received optical power. This problem can appear after poor cable installation, improper storage, or routing the cable sharply around structural objects. Chromatic dispersion causes different wavelengths or spectral components of an optical pulse to travel at slightly different speeds, but it is not normally triggered by one tight physical corner. DSL crosstalk applies to copper pairs, while Dynamic Bandwidth Allocation controls upstream transmission opportunities in a PON. Correcting the cable routing and respecting the specified bend radius can remove or reduce the loss.
질문 # 43
Which characteristic distinguishes G.fast from traditional ADSL technologies?
- A. G.fast operates only over passive optical splitters.
- B. G.fast commonly uses high frequencies and time-division duplexing over short copper loops.
- C. G.fast carries only voice services and does not support broadband data.
- D. G.fast requires a separate copper pair for upstream and downstream traffic.
- E. fast is designed to deliver high broadband rates over relatively short copper loops, frequently using existing building or drop wiring. It uses a much wider and higher-frequency spectrum than traditional ADSL and commonly employs Time Division Duplexing. With TDD, upstream and downstream transmission use the same frequency spectrum during different time intervals. The upstream-to-downstream capacity ratio can therefore be adjusted through the TDD configuration. Higher frequencies can support greater capacity but experience substantial attenuation over distance, which is why G.fast is best suited to short loops. It does not operate through passive optical splitters, although fiber may be deployed close to the subscriber before the final copper segment. G.fast also supports broadband services rather than voice-only delivery.
정답:B
질문 # 44
A residential gateway ONT provides routed Internet access to devices in a subscriber's home. Which DHCP role does it normally perform on the home LAN?
- A. It acts only as a DHCP relay and never maintains address information.
- B. It disables local addressing and assigns public addresses directly from the OLT.
- C. It acts as a DHCP client for every device connected to the LAN.
- D. It acts as a DHCP server and assigns private IP addresses to home devices.
정답:D
설명:
A Layer 3 residential gateway normally operates as a DHCP server on the subscriber's home LAN. It assigns private IP addresses and other configuration information, such as the default gateway and DNS server addresses, to connected devices. On its network-facing WAN interface, the gateway may operate as a DHCP client to obtain service parameters from the operator's network. These two DHCP roles must not be confused. The gateway also commonly performs routing, Network Address Translation, firewall enforcement, and local Ethernet or Wi-Fi connectivity. The OLT transports and controls subscriber access traffic but does not normally allocate private LAN addresses directly to individual home devices. This architecture separates the operator-facing connection from the subscriber's private local network and allows multiple home devices to share the broadband service.
질문 # 45
......
만약PassTIP를 선택하였다면 여러분은 반은 성공한 것입니다. 여러분은 아주 빠르게 안전하게 또 쉽게Nokia 4A0-F10인증시험 자격증을 취득하실 수 있습니다. 우리PassTIP에서 제공되는 모든 덤프들은 모두 100%보장 도를 자랑하며 그리고 우리는 일년무료 업데이트를 제공합니다.
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