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Oracle 1z1-071 (Oracle Database SQL) Certification Exam is a multiple-choice exam that consists of 73 questions. Candidates are given 100 minutes to complete the exam and must score at least 63% to pass. 1z1-071 exam is available in English and Japanese and can be taken at authorized testing centers worldwide. 1z1-071 exam fee varies depending on the country and region.

Oracle 1z0-071 exam is aimed at professionals who work with Oracle databases and want to enhance their skills in SQL development. 1z1-071 Exam covers various topics, including data manipulation, data control language, data definition language, and data retrieval. The candidates are required to have a deep understanding of SQL language, data modeling, and database concepts to be able to pass the exam.

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Oracle 1z0-071 exam consists of 73 questions and has a duration of 100 minutes. The questions are multiple-choice and require the candidate to choose one or more correct answers. 1z1-071 exam is available in English and Japanese and can be taken at any Pearson VUE testing center worldwide. 1z1-071 Exam Fee is $245, and candidates must register for the exam through the Oracle certification website.

Oracle Database SQL Sample Questions (Q160-Q165):

NEW QUESTION # 160
View the Exhibit and examine the structure of the SALEStable.

The following query is written to retrieve all those product IDs from the SALEStable that have more than 55000 sold and have been ordered more than 10 items.

Which statement is true regarding this SQL statement?

A. It executes successfully and generates the required result.
B. It produces an error because COUNT (*)should be specified in the SELECTclause also.
C. It executes successfully but produces no result because COUNT(prod_id)should be used instead of COUNT(*).
D. It produces an error because COUNT (*)should be only in the HAVING clause and not in the WHERE clause.

Answer: D

NEW QUESTION # 161
View the exhibit and examine the structure of the PROMOTIONS table.

You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?

A. SELECT promo_name, promo_begin_date FROM promotions
WHERE promo_begin_date> ANY (SELECT promo_begin_date
FROM promotions
WHERE promo_category= `INTERNET');
B. SELECT promo_name, promo_begin_date FROM promotions
WHERE promo_begin_date> ALL (SELECT MAX (promo_begin_date) FROM promotions) AND promo_category= `INTERNET';
C. SELECT promo_name, promo_begin_date FROM promotions
WHERE promo_begin_date > ALL (SELECT promo_begin_date
FROM promotions
WHERE promo_category = `INTERNET');
D. SELECT promo_name, promo_begin_date FROM promotions
WHERE promo_begin_date IN (SELECT promo_begin_date
FROM promotions
WHERE promo_category= `INTERNET');

Answer: C

NEW QUESTION # 162
You issue this command which succeeds:
SQL> DROP TABLE products;
Which three statements are true?

A. Table data is deleted but the table structure is retained.
B. Table data and the table structure are deleted.
C. All the table's indexes if any exist, are invalidated but retained.
D. Any uncommitted transaction in the session is committed.
E. All existing views and synonyms that refer to the table are invalidated but retained.

Answer: B,C,E

NEW QUESTION # 163
Examine the description of the CUSTOMERS table:

You need to display last names and credit limits of all customers whose last name starts with A or B In lower or upper case, and whose credit limit is below 1000.
Examine this partial query:
SELECT cust_last_nare, cust_credit_limit FROM customers
Which two WHERE conditions give the required result?

A. WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND ROUND(cust_credit_limit) < 1000;
B. WHERE (UPPER(cust_last_name) like INITCAP ('A') OR UPPER(cust_last_name) like INITCAP('B')) AND ROUND(cust_credit_limit) < ROUND(1000) ;
C. WHERE UPPER(cust_last_name) BETWEEN UPPER('A%' AND 'B%') AND ROUND(cust_credit_limit) < 1000;
D. WHERE (INITCAP(cust_last_name) LIKE 'A%' OR ITITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000
E. WHERE UPPER(cust_last_name) IN ('A%', 'B%') AND cust_credit_limit < 1000:

Answer: A,D

Explanation:
The SQL query must find all customers with last names starting with A or B, regardless of case, and a credit limit below 1000:
B . WHERE (INITCAP(cust_last_name) LIKE 'A%' OR INITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000: The INITCAP function initializes the first letter to uppercase for comparison. However, it should be noted that using INITCAP is not necessary when using the LIKE operator with a wildcard % following a single character, because it will not correctly filter all last names that start with an upper or lower case A or B.
D . WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000: This correctly filters last names beginning with A or B in any case and includes only those with a credit limit below 1000. The UPPER function is used to convert cust_last_name to uppercase before comparison.
Reference:
Oracle Database SQL Language Reference 12c, especially sections on string functions and conditions.

NEW QUESTION # 164
Examine this SELECT statement and view the Exhibit to see its output:

SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output? (Choose two.)

A. In the second column, 'c' indicates a check constraint.
B. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
C. The STATUS column indicates whether the table is currently in use.
D. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.

Answer: A,D

NEW QUESTION # 165
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