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| Section | Weight | Objectives |
|---|---|---|
| IPv6 Routing | 20% | - IPv6 static routes - IS-IS for IPv6 - OSPFv3 - BGP4+ |
| Network O&M | 7% | - Routine maintenance - Data collection |
| Network Troubleshooting | 10% | - Structured troubleshooting processes - Troubleshooting methods |
| Advanced IGP Features | 17% | - Fast convergence - IS-IS advanced features - Route control - OSPF advanced features |
| Advanced BGP Features | 10% | - Advanced BGP features - BGP route control - Inter-domain routing optimization - Route reflectors |
| Network Cutover | 7% | - Basic cutover concepts - Migration process |
| MPLS Technologies | 19% | - MPLS configuration - MPLS VPN applications - MPLS forwarding - MPLS principles |
| Advanced Ethernet Technologies | 10% | - Ethernet security - VLANs |
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NEW QUESTION # 163
On the OSPFv3 network shown in the figure, OSPFv3 parameters use default values. The LSDB is checked on one of the devices. The router IDs of R1, R3, and R4 are 10.0.1.1, 10.0.3.3, and 10.0.4.4 respectively. The Origin Router part of some LSAs is hidden. Complete this part. (Tokens can be reused.) Match the Origin Router ID to the correct LSA entry below:
Answer:
Explanation:
Explanation:
* Link-LSA (ID 0.0.0.4) : This LSA is originated by each router to describe its link-local IPv6 address and prefixes. The value 0.0.0.4 maps to the interface on R1 , which has Router ID 10.0.1.1 . # So the origin router is 10.0.1.1 .
* Network-LSA (ID 0.0.0.5) : This LSA is generated by the DR on the link. In the diagram, R4 (10.0.4.4) is connected to the shared network (GE0/0/1). # So the origin router is 10.0.4.4 .
* Inter-Area-Prefix-LSA (ID 0.0.0.1) : This LSA is used to describe routes from other areas and is generated by an ABR . In this case, R3 (Router ID 10.0.3.3) acts as the ABR. # So the origin router is
10.0.3.3 .
* Intra-Area-Prefix-LSA (ID 0.0.0.2) : This references a Network-LSA , and the reference type is 1 (Network-LSA). Since the Network-LSA (0.0.0.5) came from 10.0.4.4 , this also must have been generated by R4 . # So the origin router is 10.0.4.4 .
# Final Answer Summary:
Number
Origin Router
1
10.0.1.1
2
10.0.4.4
3
10.0.3.3
4
10.0.4.4
Official Huawei Extract:
" Each router in OSPFv3 generates Link-LSAs for each interface. The DR generates Network-LSAs.
ABRs generate Inter-Area LSAs, and the Intra-Area-Prefix LSA references either Router or Network LSAs depending on the link type. "
- [Huawei HCIA-Datacom OSPFv3 LSAs Section]
NEW QUESTION # 164
As shown in the figure, an administrator configures static LSP between routers R1~R4. Which of the following configuration options are correct? (Multiple choice)
Answer: A,B
NEW QUESTION # 165
Part of the configuration of R1 is as follows. Which of the following statement about IS-IS on R1 is correct? (Multiple choice)
Answer: B,C
NEW QUESTION # 166
On the OSPF network shown in the figure, area 1 and area 2 are common areas . The IP address of Loopback0 on R5 is 10.0.5.5/32 , and OSPF is enabled on this interface . If the abr-summary 10.0.5.0
255.255.255.0 command is run in area 2 (where R1 resides) , which of the following routers have the route
10.0.5.0/24 in their routing tables?
Answer: A,B
Explanation:
Comprehensive and Detailed In-Depth Explanation:
Step 1: Understanding OSPF Areas and Summarization
* Loopback0 on R5 has IP 10.0.5.5/32 and is advertised into OSPF.
* The abr-summary 10.0.5.0 255.255.255.0 command is applied in area 2 on R1 , which means:
* Instead of advertising individual host routes (like 10.0.5.5/32), R1 advertises the summarized route 10.0.5.0/24 into Area 0 (Backbone) .
* This summarized route is then propagated into other areas via Area 0 (Backbone) .
Step 2: Analyzing the Routing Table of Each Router
* R5 (Originating Router in Area 2)
* R5 only knows 10.0.5.5/32 because it ' s the originating router.
* The abr-summary command does not affect R5 itself.
* # R5 does not have 10.0.5.0/24.
* R1 (ABR for Area 2, Summarizing the Route)
* R1 creates and advertises 10.0.5.0/24 into Area 0 .
* This summary route is sent to other areas via Area 0.
* R2 (Connected to Area 0 & Area 1)
* Since R2 is part of Area 0 (Backbone), it receives 10.0.5.0/24 from R1 .
* # R2 has 10.0.5.0/24 in its routing table.
* R3 (Connected to Area 0 & Area 2)
* Since R3 is also connected to Area 0, it receives the summary route 10.0.5.0/24 from R1 .
* # R3 has 10.0.5.0/24 in its routing table.
* R4 (In Area 1, which is not directly connected to Area 2)
* R4 belongs to Area 1 , and unless explicitly advertised through inter-area summarization, it will not have 10.0.5.0/24 .
* Since no specific mention of summary advertisement into Area 1 is made, R4 does not get
10.0.5.0/24 .
* # R4 does not have 10.0.5.0/24.
Final answer: # R2, R3 (Option B, C)
References:
HCIP-Datacom-Advanced Routing & Switching Technology V1.0 - OSPF Route Summarization OSPF Inter-Area Route Advertisement via ABRs OSPF Backbone (Area 0) Behavior and Route Distribution
NEW QUESTION # 167
On the OSPF network shown in the figure, drag the values on the left to the correct positions so that:
* Traffic from PC1 to PC2 follows the path: PC1 - > R1 - > R3 - > R2 - > PC2
* Traffic from PC2 to PC1 follows the path: PC2 - > R2 - > R1 - > PC1
Which of the following OSPF cost values should be assigned to Cost-A, Cost-B, and Cost-C to achieve this routing behavior?
Answer:
Explanation:
Explanation:
* A = 50
* B = 10
* C = 20
Comprehensive and Detailed In-Depth Explanation:
Understanding OSPF Path Selection and Cost Calculation:
* OSPF selects the shortest path (lowest cost) to the destination.
* The OSPF cost is determined by the cumulative sum of interface costs along a path .
* By assigning specific costs to A, B, and C , we can influence OSPF's path selection to meet the desired routing behavior.
Step-by-Step Analysis of Required Traffic Flow:
1. Traffic from PC1 to PC2 must take the route:
PC1 - > R1 - > R3 - > R2 - > PC2
* To force traffic through R3 , the cost of the direct link R1 - > R2 (Cost-A) must be higher than the alternative path via R3 .
* We assign Cost-A = 50 (high cost) to discourage direct routing from R1 - > R2 .
* The cost of R1 - > R3 (Cost-C) should be lower , so we assign Cost-C = 20 .
* The cost of R3 - > R2 (default Cost-20) remains unchanged.
* Total cost via R3: 20 (R1- > R3) + 20 (R3- > R2) = 40 , which is less than the direct link of 50 , so OSPF prefers this path.
# Traffic follows: PC1 - > R1 - > R3 - > R2 - > PC2
2. Traffic from PC2 to PC1 must take the route:
PC2 - > R2 - > R1 - > PC1
* We need to make R2 - > R1 (Cost-B) the best (lowest cost) route for return traffic .
* Assign Cost-B = 10 (low cost).
* This ensures that R2 prefers the direct path R2 - > R1 instead of R2 - > R3 - > R1 (which costs
20+20=40).
# Traffic follows: PC2 - > R2 - > R1 - > PC1
Final Cost Assignments for Correct Routing Behavior:
Cost
Assigned Value
Reason
Cost-A (R1 - > R2)
50
High to discourage direct R1- > R2 routing
Cost-B (R2 - > R1)
10
Low to ensure PC2- > PC1 prefers direct R2- > R1
Cost-C (R1 - > R3)
20
Medium to encourage R1- > R3- > R2 path
Key Takeaways:
* Higher OSPF cost discourages path selection.
* Lower OSPF cost encourages path selection.
* By manipulating OSPF cost values, we achieve asymmetric routing between PC1 and PC2.
* This aligns with OSPF path selection principles covered in HCIP-Datacom certification.
HCIP-Datacom-Advanced Routing & Switching Technology References:
* Huawei HCIP-Datacom Official Certification Guide , Chapter on OSPF Cost Calculation and Path Selection .
* Huawei Enterprise Networking Training Materials , OSPF Path Optimization Techniques.
* Huawei Datacom Configuration Guide , OSPF Cost and Traffic Engineering.
NEW QUESTION # 168
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