JavaScript-Developer-I試験の準備方法｜ユニークなJavaScript-Developer-I基礎訓練試験｜正確的なSalesforce Certified JavaScript Developer (JS-Dev-101)資格練習

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Salesforce JavaScript-Developer-I Exam Syllabus Topics:

Section	Weight	Objectives
Testing	7%	- Code coverage and best practices - Test doubles and mocks - Unit testing concepts - Testing frameworks and assertions
Asynchronous Programming	13%	- Promises and chaining - Event loop and micro/macro tasks - Async/await syntax - Callbacks and callback hell - Fetch API and HTTP requests
Server-Side JavaScript	8%	- Module system and require/import - Core Node.js modules - Command-line tools and scripts - Node.js fundamentals and runtime
Objects, Functions, and Classes	25%	- Class syntax, inheritance, and prototypes - Modules and imports/exports - Function definitions, parameters, and scope - Object creation, properties, and methods - Decorators and advanced function patterns - Closures and execution context
Variables, Types, and Collections	23%	- Working with strings, numbers, dates, and booleans - Truthy and falsy values - Variable declaration and initialization - Array methods and data manipulation - Type coercion and conversion rules - JSON parsing and usage
Debugging and Error Handling	7%	- Defensive programming practices - Error types and exception handling - Debugging tools and breakpoints - Console methods and logging
Browsers and Events	17%	- Window and document object properties - Browser APIs and Web Storage - Script loading and execution order - Event handling, propagation, and delegation - Document Object Model (DOM) manipulation

>> JavaScript-Developer-I基礎訓練 <<

JavaScript-Developer-I試験準備、JavaScript-Developer-I試験問題、JavaScript-Developer-Iオンラインテスト

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Salesforce Certified JavaScript Developer (JS-Dev-101) 認定 JavaScript-Developer-I 試験問題 (Q26-Q31):

質問 # 26
A developer wrote the following code to test a sum3 function that takes in an array of numbers and returns the sum of the first three numbers in the array, and the test passes.
A different developer made changes to the behavior of sum3 to instead sum only the first two numbers present in the array.

Which two results occur when running this test on the updated sum3 function?
Choose 2 answers

A. The line 05 assertion passes.
B. The line 02 assertion passes.
C. Theline 02 assertion fails.
D. The line 05 assertion fails.

正解：B、D

質問 # 27
Refer to following code:
class Vehicle {
constructor(plate) {
This.plate =plate;
}
}
Class Truck extends Vehicle {
constructor(plate, weight) {
//Missing code
This.weight = weight;
}
displayWeight() {
console.log('The truck ${this.plate} has a weight of ${this.weight} lb.');}} Let myTruck = new Truck('123AB', 5000); myTruck.displayWeight(); Which statement should be added to line 09 for the code to display 'The truck 123AB has a weight of 5000lb.'?

A. Super.plate =plate;
B. Vehicle.plate = plate;
C. This.plate =plate;
D. super(plate);

正解：D

質問 # 28
A developer wants to iterate through an array of objects and count the objects and count the objects whose property value, name, starts with the letter N.
Const arrObj = [{"name" : "Zach"} , {"name" : "Kate"},{"name" : "Alise"},{"name" : "Bob"},{"name" :
"Natham"},{"name" : "nathaniel"}
Refer to the code snippet below:
01 arrObj.reduce(( acc, curr) => {
02 //missing line 02
02 //missing line 03
04 ). 0);
Which missing lines 02 and 03 return the correct count?

A. Const sum = curr.name.startsWIth('N') ? 1: 0;
Return curr+ sum
B. Const sum = curr.startsWith('N') ? 1: 0;
Return acc +sum
C. Const sum = curr.startsWIth('N') ? 1: 0;
Return curr+ sum
D. Const sum = curr.name.startsWith('N') ? 1: 0;
Return acc +sum

正解：D

質問 # 29
Given:
const str = ' Salesforce ' ;
Which two statements result in ' Sales ' ?

A. str.substr(1, 5);
B. str.substring(1, 5);
C. str.substr(0, 5);
D. str.substring(0, 5);

正解：C、D

解説：
str = ' Salesforce '
Index positions:
S(0) a(1) l(2) e(3) s(4) f(5) o(6) r(7) c(8) e(9)
* substring(start, end)
* Start index inclusive, end index exclusive.
* str.substring(0, 5) # characters at indices 0-4 # " Sales "
* str.substring(1, 5) # indices 1-4 # " ales "
* substr(start, length)
* Start index, then number of characters.
* str.substr(0, 5) # 5 characters starting at index 0 # " Sales "
* str.substr(1, 5) # 5 characters from index 1 # " alesf "
So the expressions that return " Sales " are A and C.

質問 # 30
Refer to the code below:
For (let number =2: number <= S; number += 1) ( // insert code statement here The developer needs to insert a code statement in the location shown. The code statement has these requirements:
1. Does not require an import
2. Logs an error when the Boolean statement evaluates to false
3. Works In both the browser and Node.js
Which statement meet these requirements?

A. Console. error (number $ 2 == 0) ;
B. Console. Assert ( number $ 2 == 0 ) ;
C. Console. Debug (number $ 2 == 0) ;
D. Assert (number $ 2 == 0);

正解：B

質問 # 31
......

SalesforceのJavaScript-Developer-I認定試験は全てのIT職員にとって大変重要な試験です。この試験に受かったら、あなたは絶対職場に廃れられることはありません。しかも、昇進と高給も実現できます。SalesforceのJavaScript-Developer-I試験に受かったら成功への鍵を握ったと言った人もいます。これは間違いないです。Xhs1991のSalesforceのJavaScript-Developer-I試験トレーニング資料はあなたが成功へのショートカットです。このトレーニング資料を持っていたら、成功への道を見つけます。

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