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Salesforce JavaScript-Developer-I Certification Exam is a highly respected certification in the Salesforce community. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is an excellent way for developers to showcase their skills and expertise in Salesforce development, and it is recognized by employers as a valuable credential. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is also a great way for developers to keep up with the latest trends and best practices in Salesforce development, as the exam is regularly updated to reflect changes in the platform.

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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q34-Q39):

NEW QUESTION # 34
A developer has an ErrorHandler module that contains multiple functions.
What kind of export be leverages so that multiple functions can be used?

A. All
B. Multi
C. Named
D. Default

Answer: C

NEW QUESTION # 35
Refer to the code below:

Which replacement for the conditional statement on line 02 allows a developer to correctly determine that a specific element, myElement on the page had been clicked?

Answer:

Explanation:
event.target.id =='myElement'

NEW QUESTION # 36
Which two code snippets show working examples of a recursive function?
Choose 2 answers

A. Function factorial ( numVar ) {
If (numVar < 0) return;
If ( numVar === 0 ) return 1;
return numVar -1;
B. Let countingDown = function(startNumber) {
If ( startNumber >0) {
console.log(startNumber) ;
return countingDown(startNUmber);
} else {
return startNumber;
}};
C. Const factorial =numVar => {
If (numVar < 0) return;
If ( numVar === 0 ) return 1;
return numVar * factorial ( numVar - 1 );
};
D. Const sumToTen = numVar => {
If (numVar < 0)
Return;
return sumToTen(numVar + 1)};

Answer: B,C

NEW QUESTION # 37
Universal Containers recently its new landing page to host crowd-function campaign. The page uses an external library to display some third-party ads. Once the page is fully loaded, It creates more than 50 new HTML items placed randomly inside the DOM, like the one in the code below.

All the elements included the same ad-library-item class. They are hidden by default, and they are randomly displayed while the user navigation through the page.
Tired of all the ads, what can the developer do to temporarily and quickly remove them?

A. Use the browser console to execute a script that prevents the load event to be fired.
B. Use the DOM inspector to prevent the load event to be fired.
C. Use the DOM inspector to remove all the elements containing the call ad-library -item.
D. Use the browser console to execute a script that removes all the elements containing the class ad-library-item.

Answer: D

NEW QUESTION # 38
A developer has a fizzbuzz function that, when passed in a number, returns the following:
* ' fizz ' if the number is divisible by 3.
* ' buzz ' if the number is divisible by 5.
* ' fizzbuzz ' if the number is divisible by both 3 and 5.
* Empty string ' ' if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?

A. let res = fizzbuzz(15);
console.assert(res === ' fizzbuzz ' );
B. let res = fizzbuzz(5);
console.assert(res === ' fizz ' );
C. let res = fizzbuzz(3);
console.assert(res === ' ' );
D. let res = fizzbuzz(true);
console.assert(res === ' ' );

Answer: A,D

Explanation:
First, recall the fizzbuzz rules:
* If n divisible by 3 and not by 5 # return ' fizz ' .
* If n divisible by 5 and not by 3 # return ' buzz ' .
* If n divisible by both 3 and 5 # return ' fizzbuzz ' .
* Otherwise # return ' ' (empty string).
Evaluate each test:
Option A:
let res = fizzbuzz(true);
console.assert(res === ' ' );
In JavaScript, when using arithmetic operations with true, it is coerced to the number 1. A typical implementation of fizzbuzz would treat the argument as a number and compute:
* true % 3 # 1 % 3 # 1
* true % 5 # 1 % 5 # 1
So true is effectively treated as 1, which is divisible by neither 3 nor 5. The function should return ' ' . The assertion res === ' ' will pass.
This test covers the scenario "neither divisible by 3 nor 5".
Option B:
let res = fizzbuzz(3);
console.assert(res === ' ' );
* 3 is divisible by 3 but not by 5.
* According to fizzbuzz rules, fizzbuzz(3) should return ' fizz ' .
* This test expects ' ' , so it is incorrect; the assertion would fail in a correct implementation.
Option C:
let res = fizzbuzz(5);
console.assert(res === ' fizz ' );
* 5 is divisible by 5 but not by 3.
* According to fizzbuzz rules, fizzbuzz(5) should return ' buzz ' .
* This test expects ' fizz ' , so it is incorrect.
Option D:
let res = fizzbuzz(15);
console.assert(res === ' fizzbuzz ' );
* 15 is divisible by both 3 and 5.
* According to fizzbuzz rules, fizzbuzz(15) should return ' fizzbuzz ' .
* This assertion correctly matches the expected result, so it is a proper test case.
Thus, the two test cases that correctly test valid fizzbuzz behavior are:
The answer: A, D
Study Guide / Concept References (no links):
* Modulo operator (%) for divisibility checks
* Truthy/number coercion of boolean true in arithmetic (Number(true) === 1)
* Designing unit tests with console.assert
* Typical fizzbuzz logic structure and expected outputs

NEW QUESTION # 39
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