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Salesforce PDI (Platform Developer I (PDI)) Certification Exam is a popular certification program offered by Salesforce, a leading cloud-based customer relationship management (CRM) platform. Platform Developer I (PDI) certification is designed for developers who want to validate their skills and knowledge in building custom applications on the Salesforce platform. It is an entry-level certification that is ideal for developers who are new to Salesforce development.
NEW QUESTION # 91
A developer creates an Apex Trigger with the following code block:List<Account> customers = new List<Account>();For (Order__c o: trigger.new){Account a = [SELECT Id, Is_Customer__c FROM Account WHERE Id
:o.Customer__c];a.Is_Customer__c = true;customers.add(a);}Database.update(customers, false);The developer tests the code using Apex Data Loader and successfully loads 10 Orders. Then, the developer loads 150 Orders.How many Orders are successfully loaded when the developer attempts to load the 150 Orders?
Answer: D
NEW QUESTION # 92
A developer is writing tests for a class and needs to insert records to validate functionality.
Which annotation method should be used to create record for every method in the test class?
Answer: C
NEW QUESTION # 93
A Licensed_Professional__c custom object exist in the system with two Master-Detail fields for the following objects: Certification__c and Contact. Users with the "Certification Representative" role can access the Certification records they own and view the related Licensed Professionals records, however users with the
"Salesforce representative" role report they cannot view any Licensed professional records even though they own the associated Contact record. What are two likely causes of users in the "Sales Representative" role not being able to access the Licensed Professional records? Choose 2 answers
Answer: A,D
NEW QUESTION # 94
Universal Containers hires a developer to build a custom search page to help user- find the Accounts they want. Users will be able to search on Name, Description, and a custom comments field.
Which consideration should the developer be aware of when deciding between SOQ1 Mid SOSL ?
Choose 2 answers
Answer: A,C
NEW QUESTION # 95
Refer to the following Apex code:
apex
Copy
Integer x = 0;
do {
x++;
} while (x < 1);
System.debug(x);
What is the value of x when it is written to the debug log?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
To determine the value of x when it is written to the debug log, we need to analyze the Apex code step by step, focusing on the behavior of the do-while loop and how it affects the variable x. Let's break down the code execution systematically, referencing Salesforce's official Apex Developer Guide.
Code Analysis:
The given Apex code is:
apex
Copy
Integer x = 0;
do {
x++;
} while (x < 1);
System.debug(x);
Step 1: Initial State
* Integer x = 0;: The variable x is initialized to 0. The Apex Developer Guide states: "An Integer in Apex is a 32-bit number that does not include decimal points, initialized to 0 by default if no value is provided" (Salesforce Apex Developer Guide, Primitive Data Types). Here, x is explicitly set to 0.
Step 2: Understanding the do-while Loop
* A do-while loop in Apex executes the loop body at least once before evaluating the condition. The Apex Developer Guide explains: "The do-while loop executes the block of code in the do statement first, then checks the condition in the while statement. If the condition is true, the loop continues; otherwise, it exits" (Salesforce Apex Developer Guide, Loops).
* The loop body is:
apex
Copy
x++;
This increments x by 1 using the post-increment operator (++). The Apex Developer Guide confirms: "The ++ operator increments the value of the variable by 1" (Salesforce Apex Developer Guide, Expressions and Operators).
* The condition is:
apex
Copy
while (x < 1);
The loop continues as long as x < 1 evaluates to true.
Step 3: Loop Execution
* First Iteration:
* Initial value: x = 0.
* Execute the loop body: x++ # x becomes 1 (0 + 1).
* Evaluate the condition: x < 1 # 1 < 1 # false (since 1 is not less than 1).
* Since the condition is false, the loop exits after the first iteration.
* After the Loop:
* The value of x is now 1.
* The do-while loop guarantees at least one execution, which is why x is incremented once before the condition check fails.
Step 4: Debug Statement
* System.debug(x);: This writes the value of x to the debug log. At this point, x = 1. The Apex Developer Guide states: "System.debug outputs the value of the specified variable to the debug log for troubleshooting" (Salesforce Apex Developer Guide, System Class).
* Therefore, the debug log will show 1.
Evaluating the Options:
* A. 0: Incorrect. The initial value of x is 0, but the do-while loop increments x to 1 in the first iteration, and the loop exits because the condition x < 1 is false. The debug log shows the final value of x, which is 1.
* B. 2: Incorrect. The loop only runs once because after the first iteration, x becomes 1, and the condition x < 1 fails (1 < 1 is false). There is no second iteration to increment x to 2.
* C. 1: Correct. As calculated, the loop executes once, incrementing x from 0 to 1, and then exits because the condition x < 1 is false. The debug log outputs x = 1.
* D. 3: Incorrect. The loop does not run enough times to increment x to 3. It only runs once, setting x to 1.
Why Option C is Correct:
Option C (1) is correct because:
* The do-while loop executes the body (x++) exactly once, incrementing x from 0 to 1.
* The condition x < 1 evaluates to false when x = 1, causing the loop to exit after the first iteration.
* The System.debug(x) statement outputs the final value of x, which is 1.
* This behavior aligns with Apex loop semantics as defined in the Salesforce Apex Developer Guide.
Handling Typos:
* The code in the image contains a typo: "salesforce" is randomly inserted in the middle of the do-while loop. This appears to be an artifact of the image and not part of the intended code. For analysis, we ignore this text and treat the code as:
apex
Copy
Integer x = 0;
do {
x++;
} while (x < 1);
System.debug(x);
* There are no other syntactic issues in the code that affect the execution or outcome.
Example for Clarity:
To illustrate, here's how the code executes:
Integer x = 0; // x is 0
do {
x++; // First iteration: x becomes 1
} while (x < 1); // Condition: 1 < 1 # false, exit loop
System.debug(x); // Outputs: 1
If this code were run in a Salesforce org, the debug log would show:
DEBUG|1
References:
Salesforce Apex Developer Guide:
"Primitive Data Types" section: Defines the Integer type and its initialization.
"Loops" section: Explains the do-while loop's behavior, including guaranteed first execution.
"Expressions and Operators" section: Details the ++ increment operator.
"System Class" section: Describes System.debug for logging variable values.(Available at: https://developer.
salesforce.com/docs/atlas.en-us.apexcode.meta/apexcode/)
Platform Developer I Study Guide:
Section on "Developer Fundamentals": Covers Apex basics, including variables, loops, and debugging techniques.(Available at: https://trailhead.salesforce.com/en/content/learn/modules/platform-developer-i- certification-study-guide)
NEW QUESTION # 96
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