WGU Applied-Probability-and-Statistics技術問題、Applied-Probability-and-Statistics問題サンプル

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WGU Applied-Probability-and-Statistics Exam Syllabus Topics:

SectionObjectives
Probability Theory- Probability Distributions
  • 1. Normal distribution
    • 2. Binomial distribution basics
      - Fundamental Probability Concepts
      • 1. Independent vs dependent events
        • 2. Basic probability rules
          • 3. Conditional probability
            Regression and Modeling- Linear Relationships
            • 1. Slope and intercept interpretation
              • 2. Simple linear regression
                Statistical Inference- Hypothesis Testing (Introductory Level)
                • 1. p-values interpretation
                  • 2. Null vs alternative hypothesis
                    - Estimation and Confidence Intervals
                    • 1. Confidence interval interpretation
                      • 2. Point estimates
                        Descriptive Statistics- Two Variable Data Analysis
                        • 1. Correlation
                          • 2. Outliers and relationships
                            • 3. Scatter plots interpretation
                              - Single Variable Data Analysis
                              • 1. Data visualization (histograms, box plots)
                                • 2. Measures of dispersion (variance, standard deviation, range)
                                  • 3. Measures of central tendency (mean, median, mode)

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                                    WGU Applied Probability and Statistics (FZO1 C955) 認定 Applied-Probability-and-Statistics 試験問題 (Q136-Q141):

                                    質問 # 136
                                    The average lifespan of a dalmatian is 11.5 years, with a standard deviation of 1.5 years.
                                    What are the two values between which 95% of the data falls for the average lifespan of a dalmatian, assuming a normal distribution?

                                    正解:C

                                    解説:
                                    For a normal distribution, the empirical rule states that approximately 95% of observations lie within two standard deviations of the mean. The mean lifespan is 11.5 years, and the standard deviation is 1.5 years. Two standard deviations equal 2 × 1.5 = 3.0 years. Therefore, the interval containing approximately 95% of the data is found by subtracting and adding 3.0 years to the mean: 11.5 # 3.0 = 8.5 and 11.5 + 3.0 = 14.5. The resulting interval is 8.5 years to 14.5 years. Option C, 10.0 to 13.0, represents one standard deviation from the mean and would correspond to about 68% of the data. Options A and D are not centered correctly at the proper two-standard-deviation distance. The correct interval must be symmetric around the mean and use two standard deviations. References/topics from the Study Guide: normal distributions, empirical rule, standard deviation, measures of spread.


                                    質問 # 137
                                    What is the result of 2/5 + 1/3 # 1/4?

                                    正解:C

                                    解説:
                                    To add and subtract fractions, first rewrite all fractions using a common denominator. The denominators are
                                    5, 3, and 4. Their least common denominator is 60. Convert each fraction: 2/5 = 24/60, 1/3 = 20/60, and 1/4 =
                                    15/60. Now combine the numerators while keeping the common denominator: 24/60 + 20/60 # 15/60 = (24 +
                                    20 # 15)/60 = 29/60. The fraction 29/60 is already in simplest form because 29 is prime and does not divide
                                    60. Option A, 13/60, and option B, 11/60, result from incorrect numerator operations. Option D, 19/60, also fails to preserve the correct addition before subtraction. The essential technical step is establishing a common denominator before performing arithmetic operations. References/topics from the Study Guide: fractions, least common denominator, fraction addition, fraction subtraction.


                                    質問 # 138
                                    Determine z in the equation:
                                    1/(6z) = 2/9

                                    正解:D

                                    解説:
                                    The equation 1/(6z) = 2/9 is a proportion because it sets two fractions equal to each other. To solve it, use cross multiplication. Multiply the numerator of the first fraction by the denominator of the second fraction, and multiply the denominator of the first fraction by the numerator of the second fraction: 1 × 9 = 2 × 6z. This gives 9 = 12z. To isolate z, divide both sides by 12: z = 9/12. This fraction can also be simplified to 3/4, but the answer choices list the unsimplified equivalent form 9/12. The other options do not satisfy the original equation. For example, if z = 2/54, then 6z is very small and the left side becomes much larger than 2/9. If z =
                                    12/9 or 18/2, the denominator becomes too large, making the left side too small. References/topics from the Study Guide: proportions, solving equations, cross multiplication, equivalent fractions.


                                    質問 # 139
                                    In a class of 30 students, 18 are enrolled in a math course, and 12 are enrolled in a science course. Among the students enrolled in the science course, 8 are also enrolled in the math course.
                                    What is the probability that a student is enrolled in the math course given that they are enrolled in the science course?

                                    正解:D

                                    解説:
                                    The phrase "given that they are enrolled in the science course" indicates conditional probability. The reference group is not all 30 students; it is only the 12 students enrolled in science. Among those 12 science students, 8 are also enrolled in math. Therefore, the conditional probability is P(math | science) = P(math and science) ÷ P(science), or more directly, 8 ÷ 12. This simplifies to 2/3, which is approximately 0.6667, rounded to .67. Option A, .27, would come from comparing the 8 students to the entire class of 30, but that ignores the given condition. Option B, .40, corresponds to 12/30, the proportion enrolled in science. Option C, .44, is approximately 8/18, which reverses the condition and would represent the probability of science given math.
                                    The correct answer uses the science group as the denominator. References/topics from the Study Guide:
                                    conditional probability, two-way events, joint enrollment, probability ratios.


                                    質問 # 140
                                    Probability it does NOT rain = 1 # 0.25 = ?

                                    正解:B

                                    解説:
                                    This question uses the complement rule of probability. If the probability that it rains is 0.25, then the probability that it does not rain is the complement of that event. The complement rule states that P(not A) = 1
                                    # P(A). Here, A represents the event "it rains," so P(not rain) = 1 # 0.25 = 0.75. This means there is a 75% probability that rain does not occur. Option B repeats the probability of rain rather than its complement.
                                    Option C would imply rain and no rain are equally likely, which is not supported by the given probability.
                                    Option D would mean no rain is certain, but a 0.25 probability of rain means rain is still possible. The key technical point is that an event and its complement must sum to 1. Study Guide references/topics: probability, complement rule, event probability, sample-space total.


                                    質問 # 141
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