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| Section | Objectives |
|---|---|
| Topic 1: App Logic and Data Handling | - Data management in apps
|
| Topic 2: App Lifecycle and Deployment Concepts | - Understanding app structure
|
| Topic 3: User Interface Development | - Building iOS interfaces
|
| Topic 4: Introduction to App Development with Swift | - Swift programming fundamentals
|
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NEW QUESTION # 21
Review the code snippet.
What will print after the final line of code is executed?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objective on variable scope and shadowing .
The code first declares:
let even = 2
This creates a constant named even in the outer scope with the value 2.
Inside the for loop, the code declares another constant with the same name:
let even = num * 2
This inner even exists only inside the loop body. It shadows the outer even, which means that within the loop, the name even refers to the loop's local constant, not the original one. However, that inner constant goes out of scope at the end of each loop iteration.
After the loop finishes, the inner even no longer exists. So when the final line runs:
print(even)
Swift uses the original outer constant, which is still 2.
So the output is:
2
This question tests two important Swift concepts:
* Scope : where a variable or constant can be accessed
* Shadowing : when a local declaration temporarily hides another declaration with the same name Therefore, the correct answer is 2 .
NEW QUESTION # 22 
Which two assignments of a value to direction are allowed? (Choose 2.)
Answer: C,D
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering basic Swift types and how Swift handles enumerations . The code defines an enum named CompassPoint with the cases north, south, east, and west, and then declares direction as type CompassPoint. In Swift, an enum case can be assigned using the fully qualified form CompassPoint.north, so B is valid. Swift also allows the shorthand form .north when the compiler already knows the expected type is CompassPoint, so D is also valid. Apple's Swift language documentation explains that once a variable is known to be of a specific enumeration type, you can set its value using the shorter dot syntax.
The other options are not allowed. A is invalid because enum cases are not assigned using constructor-style syntax like CompassPoint(north). C is invalid because north by itself is not enough unless it is written with dot shorthand in a context with inferred enum type. E is invalid because north is a case of the enum type, not a member accessed from the variable instance as direction.north. Swift enum cases are referenced from the enum type or by shorthand dot syntax, not as instance properties.
NEW QUESTION # 23
Why does the initializer for the following struct need the keyword self?
Answer: D
Explanation:
This question belongs to Swift Programming Language , specifically the objective covering structs, properties, and initializers .
In the struct, both the property and the initializer parameter are named age:
struct person {
var age: Int
init(age: Int) {
self.age = age
}
}
Here, age inside the initializer could refer to either the property of the struct or the parameter passed into the initializer. Swift uses self.age to clearly mean the property that belongs to the current instance , while plain age refers to the initializer parameter . So self.age = age means: assign the parameter value to the instance property.
That is why C is correct. The keyword self is required here to remove ambiguity between two identifiers with the same name.
The other options are incorrect:
* A is wrong because self here is not pointing to the parameter; it points to the instance property.
* B is wrong because self is not always required in every initializer assignment. It is specifically needed here because of the naming conflict.
* D is wrong because whether the property has a default value is not the reason self is needed in this example.
So the correct answer is C. self is needed to distinguish between the property and the parameter with the same name.
NEW QUESTION # 24
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
Answer: A,E
Explanation:
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
NEW QUESTION # 25
Review the code snippet.
What is the value of answer after you run the code?
Answer:
Explanation:
4
Explanation:
This question belongs to Swift Programming Language , specifically the domains covering control flow , loops , and range operators .
The code starts with:
var count = 0
var answer = 0
So both variables begin with the value 0.
In the first loop:
for index in 1...5 {
count = index
}
the closed range 1...5 includes 1, 2, 3, 4, and 5 . During each iteration, count is updated to the current value of index. After the loop finishes, the final value assigned to count is 5 .
Then the second loop runs:
for index in 1.. < count {
answer = index
}
Here, the half-open range 1.. < count means values starting at 1 up to, but not including , count. Since count is 5, this loop runs with index equal to 1, 2, 3, and 4 . Each time through the loop, answer is updated to the current index. After the last iteration, answer becomes 4 .
So the final value of answer is 4 . This question tests understanding of the difference between the closed range operator ... and the half-open range operator .. < , which is a key Swift control-flow concept.
NEW QUESTION # 26
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